結果

問題 No.1244 Black Segment
ユーザー theory_and_metheory_and_me
提出日時 2020-10-03 01:17:10
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 82 ms / 2,000 ms
コード長 4,086 bytes
コンパイル時間 2,141 ms
コンパイル使用メモリ 207,816 KB
最終ジャッジ日時 2025-01-15 01:32:25
ジャッジサーバーID
(参考情報)
judge5 / judge4
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 36
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
using namespace std;
#define REP(i,n) for(ll i=0;i<(ll)n;i++)
#define dump(x) cerr << "Line " << __LINE__ << ": " << #x << " = " << (x) << "\n";
#define spa << " " <<
#define fi first
#define se second
#define ALL(a) (a).begin(),(a).end()
#define ALLR(a) (a).rbegin(),(a).rend()
using ld = long double;
using ll = long long;
using ull = unsigned long long;
using pii = pair<int, int>;
using pll = pair<ll, ll>;
using pdd = pair<ld, ld>;
template<typename T> using V = vector<T>;
template<typename T> using P = pair<T, T>;
template<typename T> vector<T> make_vec(size_t n, T a) { return vector<T>(n, a); }
template<typename... Ts> auto make_vec(size_t n, Ts... ts) { return vector<decltype(make_vec(ts...))>(n, make_vec(ts...)); }
template<class S, class T> ostream& operator << (ostream& os, const pair<S, T> v){os << "(" << v.first << ", " << v.second << ")"; return os;}
template<typename T> ostream& operator<<(ostream &os, const vector<T> &v) { for (auto &e : v) os << e << ' '; return os; }
template<class T> ostream& operator<<(ostream& os, const vector<vector<T>> &v){ for(auto &e : v){os << e << "\n";} return os;}
struct fast_ios { fast_ios(){ cin.tie(nullptr); ios::sync_with_stdio(false); cout << fixed << setprecision(20); }; } fast_ios_;
template <class T> void UNIQUE(vector<T> &x) {sort(ALL(x));x.erase(unique(ALL(x)), x.end());}
template<class T> bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }
template<class T> bool chmin(T &a, const T &b) { if (a>b) { a=b; return 1; } return 0; }
void fail() { cout << -1 << '\n'; exit(0); }
inline int popcount(const int x) { return __builtin_popcount(x); }
inline int popcount(const ll x) { return __builtin_popcountll(x); }
template<typename T> void debug(vector<vector<T>>&v,ll h,ll w){for(ll i=0;i<h;i++)
{cerr<<v[i][0];for(ll j=1;j<w;j++)cerr spa v[i][j];cerr<<"\n";}};
template<typename T> void debug(vector<T>&v,ll n){if(n!=0)cerr<<v[0];
for(ll i=1;i<n;i++)cerr spa v[i];
cerr<<"\n";};
const ll INF = (1ll<<62);
// const ld EPS = 1e-10;
// const ld PI = acos(-1.0);
const ll mod = (int)1e9 + 7;
//const ll mod = 998244353;
template< typename T >
struct edge {
int src, to;
T cost;
edge(int to, T cost) : src(-1), to(to), cost(cost) {}
edge(int src, int to, T cost) : src(src), to(to), cost(cost) {}
edge &operator=(const int &x) {
to = x;
return *this;
}
operator int() const { return to; }
};
template< typename T >
using Edges = vector< edge< T > >;
template< typename T >
using WeightedGraph = vector< Edges< T > >;
using UnWeightedGraph = vector< vector< int > >;
template< typename T >
using Matrix = vector< vector< T > >;
template< typename T >
vector< T > Dijkstra(WeightedGraph< T > &g, int s) {
const auto INF = numeric_limits< T >::max();
vector< T > dist(g.size(), INF);
using Pi = pair< T, int >;
priority_queue< Pi, vector< Pi >, greater< Pi > > que;
dist[s] = 0;
que.emplace(dist[s], s);
while(!que.empty()) {
T cost;
int idx;
tie(cost, idx) = que.top();
que.pop();
if(dist[idx] < cost) continue;
for(auto &e : g[idx]) {
auto next_cost = cost + e.cost;
if(dist[e.to] <= next_cost) continue;
dist[e.to] = next_cost;
que.emplace(dist[e.to], e.to);
}
}
return dist;
}
int main(){
ll N, M, A, B;
cin >> N >> M >> A >> B;
A--, B--;
V<ll> L(M), R(M);
REP(i, M) cin >> L[i] >> R[i];
REP(i, M) L[i]--, R[i]--;
using Graph = V<V<edge<ll>>>;
Graph G(N+1);
REP(i, M){
G[L[i]].emplace_back(R[i]+1, 1);
G[R[i]+1].emplace_back(L[i], 1);
}
REP(i, N+1){
if(i<A){
G[A].emplace_back(i, 0);
G[i].emplace_back(A, 0);
}
if(B+1<i){
G[B+1].emplace_back(i, 0);
G[i].emplace_back(B+1, 0);
}
}
// REP(i, N+1){
// dump(i)
// for(auto &e: G[i]) cout << e.to spa e.cost << endl;
// }
auto dist = Dijkstra(G, A);
ll res = dist[B+1];
cout << (res >= INF ? -1 : res) << endl;
return 0;
}
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