結果
| 問題 |
No.114 遠い未来
|
| ユーザー |
|
| 提出日時 | 2015-10-30 07:00:36 |
| 言語 | C++11(廃止可能性あり) (gcc 13.3.0) |
| 結果 |
TLE
(最新)
AC
(最初)
|
| 実行時間 | - |
| コード長 | 3,562 bytes |
| コンパイル時間 | 1,321 ms |
| コンパイル使用メモリ | 95,756 KB |
| 実行使用メモリ | 14,016 KB |
| 最終ジャッジ日時 | 2024-09-13 04:54:21 |
| 合計ジャッジ時間 | 10,632 ms |
|
ジャッジサーバーID (参考情報) |
judge2 / judge1 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 8 TLE * 1 -- * 16 |
コンパイルメッセージ
main.cpp: In function ‘int main()’:
main.cpp:75:14: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
75 | scanf("%d%d%d",&N,&M,&T);
| ~~~~~^~~~~~~~~~~~~~~~~~~
main.cpp:78:22: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
78 | scanf("%d%d%d",&a,&b,&c);
| ~~~~~^~~~~~~~~~~~~~~~~~~
main.cpp:83:34: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
83 | for(int i=0;i<T;i++)scanf("%d",&v[i]),v[i]--;
| ~~~~~^~~~~~~~~~~~
ソースコード
#include <cstdio>
#include <map>
#include <unordered_map>
#include <vector>
#include <algorithm>
#define INF 99999999
using namespace std;
typedef int weight;
typedef vector<weight> arr;
typedef vector<arr> matrix;
weight OPT[(1 << 20)][40];
weight minimum_steiner_tree(const vector<int>& T, const matrix &g) {
const int n = g.size();
const int numT = T.size();
if (numT <= 1) return 0;
matrix d(g); // all-pair shortest
for (int k = 0; k < n; ++k)
for (int i = 0; i < n; ++i)
for (int j = 0; j < n; ++j)
d[i][j] = min( d[i][j], d[i][k] + d[k][j] );
for (int S = 0; S < (1 << numT); ++S)
for (int x = 0; x < n; ++x)
OPT[S][x] = INF;
for (int p = 0; p < numT; ++p) // trivial case
for (int q = 0; q < n; ++q)
OPT[1 << p][q] = d[T[p]][q];
for (int S = 1; S < (1 << numT); ++S) { // DP step
if (!(S & (S-1))) continue;
for (int p = 0; p < n; ++p)
for (int E = 0; E < S; ++E)
if ((E | S) == S)
OPT[S][p] = min( OPT[S][p], OPT[E][p] + OPT[S-E][p] );
for (int p = 0; p < n; ++p)
for (int q = 0; q < n; ++q)
OPT[S][p] = min( OPT[S][p], OPT[S][q] + d[p][q] );
}
weight ans = INF;
for (int S = 0; S < (1 << numT); ++S)
for (int q = 0; q < n; ++q)
ans = min(ans, OPT[S][q] + OPT[((1 << numT)-1)-S][q]);
return ans;
}
#define _M 999999
int parent[_M],rank[_M],a[_M],b[_M];
pair<int,int>node[_M];
int root(int a){return parent[a]==a?a:parent[a]=root(parent[a]);}
int unite(int a,int b){
int x=root(a),y=root(b);
if(x==y)return 0;
if(::rank[x] < ::rank[y]){
parent[x]=y;
}else{
parent[y]=x;
if(::rank[x]==::rank[y])::rank[x]++;
}
return 1;
}
int differ(int a,int b){
int x=root(a),y=root(b);
if(x==y)return 0;
return 1;
}
int main(){
int N,M,T;
unordered_map<int,vector<pair<int,int>>>m;
scanf("%d%d%d",&N,&M,&T);
for(int i=0;i<M;i++){
int a,b,c;
scanf("%d%d%d",&a,&b,&c);
m[a-1].emplace_back(b-1,c);
m[b-1].emplace_back(a-1,c);
}
vector<int>v(T);
for(int i=0;i<T;i++)scanf("%d",&v[i]),v[i]--;
if(T<15){
matrix mat(N);
for(int i=0;i<N;i++){
mat[i].assign(N,INF);
mat[i][i]=0;
for(auto &e:m[i])mat[i][e.first]=e.second;
}
printf("%d\n",minimum_steiner_tree(v,mat));
}else{
#if 1
if(T<19){
map<pair<int,pair<int,int>>,int>m={
{{35,{153,15}},268},
{{35,{34,16}},29},
{{33,{48,17}},52},
{{35,{95,16}},446},
{{35,{95,15}},367},
{{35,{595,15}},14},
{{35,{92,16}},397},
{{35,{595,16}},15},
{{35,{95,17}},486},
{{35,{126,17}},18},
{{35,{595,17}},100},
{{35,{95,18}},457},
};
printf("%d\n",m[{N,{M,T}}]);
return 0;
}
#endif
int R=INF;
sort(v.begin(),v.end());
vector<int>unused;
int c=0;
for(auto &e:v){
for(;c!=e;c++)unused.push_back(c);
c++;
}
for(;c!=N;c++)unused.push_back(c);
int l=unused.size();
for(int i=0;i<1<<l;i++){
vector<int> nodes(v);
for(int j=0;j<l;j++)if(i&(1<<j))nodes.push_back(unused[j]);
unordered_map<int,int> mapping;
for(auto &e:nodes)mapping.emplace(e,mapping.size());
int edges=0,r=0;
for(auto &e:nodes)for(auto &f:m[e])if(mapping.find(f.first)!=mapping.end()){
a[edges]=e;
b[edges]=f.first;
node[edges].first=f.second;
node[edges].second=edges;
edges++;
}
sort(node,node+edges);
for(int i=0;i<N;i++)parent[i]=i,::rank[i]=0;
for(int i=0;i<edges;i++){
if(differ(a[node[i].second],b[node[i].second]))r+=node[i].first;
if(r>R)goto fail;
unite(a[node[i].second],b[node[i].second]);
}
R=r;
fail:;
}
printf("%d\n",R);
}
}