結果
問題 |
No.455 冬の大三角
|
ユーザー |
|
提出日時 | 2020-10-15 11:24:50 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 1,378 bytes |
コンパイル時間 | 856 ms |
コンパイル使用メモリ | 92,988 KB |
実行使用メモリ | 5,376 KB |
最終ジャッジ日時 | 2024-07-20 19:44:41 |
合計ジャッジ時間 | 3,151 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge2 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 51 WA * 3 |
コンパイルメッセージ
main.cpp: In function 'int main()': main.cpp:42:5: warning: 'y2' may be used uninitialized [-Wmaybe-uninitialized] 42 | if (y1 == y2) { | ^~ main.cpp:25:21: note: 'y2' was declared here 25 | int x1, y1, x2, y2; | ^~ main.cpp:50:10: warning: 'x2' may be used uninitialized [-Wmaybe-uninitialized] 50 | else if (x1 == x2) { | ^~ main.cpp:25:17: note: 'x2' was declared here 25 | int x1, y1, x2, y2; | ^~ main.cpp:52:25: warning: 'y1' may be used uninitialized [-Wmaybe-uninitialized] 52 | s[x1 + 1][y1] = '*'; | ^ main.cpp:25:13: note: 'y1' was declared here 25 | int x1, y1, x2, y2; | ^~ main.cpp:52:18: warning: 'x1' may be used uninitialized [-Wmaybe-uninitialized] 52 | s[x1 + 1][y1] = '*'; | ~~~^~~ main.cpp:25:9: note: 'x1' was declared here 25 | int x1, y1, x2, y2; | ^~
ソースコード
#include <iostream> #include <string> #include <algorithm> #include <iostream> #include <string> #include <algorithm> #include <vector> #include <iomanip> #include <cmath> #include <stdio.h> #include <queue> #include <deque> #include <cstdio> #include <set> #include <map> #include <bitset> #include <stack> #include <cctype> using namespace std; string s[110]; int main() { int h, w; cin >> h >> w; bool b = false; int x1, y1, x2, y2; for (int i = 0; i < h; i++) { cin >> s[i]; for (int j = 0; j < w; j++) { if (s[i][j] == '*') { if (!b) { x1 = i; y1 = j; b = true; } else { x2 = i; y2 = j; } } } } if (y1 == y2) { if (y1 != w - 1) { s[x1][y1 + 1] = '*'; } else { s[x1][y1 - 1] = '*'; } } else if (x1 == x2) { if (x1 != h - 1) { s[x1 + 1][y1] = '*'; } else { s[x1 + 1][y1] = '*'; } } else{ if (x1 != h - 1) { s[x1 + 1][y1] = '*'; } else { s[x1 + 1][y1] = '*'; } } for (int i = 0; i < h; i++) { cout << s[i] << endl; } return 0; }