結果
| 問題 |
No.1251 絶対に間違ってはいけない最小化問題
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2020-10-15 22:28:34 |
| 言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 62 ms / 2,000 ms |
| コード長 | 1,292 bytes |
| コンパイル時間 | 1,922 ms |
| コンパイル使用メモリ | 173,828 KB |
| 実行使用メモリ | 6,784 KB |
| 最終ジャッジ日時 | 2024-07-20 20:02:52 |
| 合計ジャッジ時間 | 16,032 ms |
|
ジャッジサーバーID (参考情報) |
judge5 / judge1 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 42 |
コンパイルメッセージ
In file included from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/istream:39,
from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/sstream:38,
from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/complex:45,
from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/ccomplex:39,
from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/x86_64-pc-linux-gnu/bits/stdc++.h:54,
from main.cpp:2:
In member function 'std::basic_ostream<_CharT, _Traits>::__ostream_type& std::basic_ostream<_CharT, _Traits>::operator<<(long double) [with _CharT = char; _Traits = std::char_traits<char>]',
inlined from 'int main()' at main.cpp:59:41:
/home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/ostream:233:25: warning: 'med' may be used uninitialized [-Wmaybe-uninitialized]
233 | { return _M_insert(__f); }
| ~~~~~~~~~^~~~~
main.cpp: In function 'int main()':
main.cpp:30:8: note: 'med' was declared here
30 | ld med;
| ^~~
ソースコード
#include <algorithm>
#include <bits/stdc++.h>
using namespace std;
#define rep(i, n) for (int i = 0; i < (int)(n); i++)
#define all(x) (x).begin(), (x).end()
#define ll long long
#define ld long double
#define INF 1000000000000000000
typedef pair<ll, ll> pll;
typedef pair<int, int> pint;
vector<pll> A;
int main() {
cin.tie(0);
ios::sync_with_stdio(false);
int N;
cin >> N;
A.resize(N);
ll sum = 0, ssum;
rep(i, N) { cin >> A[i].first; }
rep(i, N) {
cin >> A[i].second;
sum += A[i].second;
}
ssum = sum;
ld med;
sort(all(A));
if (sum % 2 == 0) {
ll bd = sum / 2;
rep(i, N) {
ssum -= A[i].second;
if (ssum == bd) {
med = (A[i + 1].first + A[i].first) / 2;
break;
}
if (ssum < bd) {
med = A[i].first;
break;
}
}
} else {
ll bd = sum / 2;
rep(i, N) {
ssum -= A[i].second;
if (ssum <= bd) {
med = A[i].first;
break;
}
}
}
ld ans = 0;
rep(i, N) { ans += A[i].second * abs(A[i].first - med); }
cout << fixed << setprecision(5) << med << " " << (ll)ans << endl;
}