結果

問題 No.1262 グラフを作ろう!
ユーザー heno239
提出日時 2020-10-16 22:27:34
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
TLE  
(最新)
AC  
(最初)
実行時間 -
コード長 4,595 bytes
コンパイル時間 1,952 ms
コンパイル使用メモリ 128,460 KB
実行使用メモリ 151,808 KB
最終ジャッジ日時 2024-07-20 22:51:01
合計ジャッジ時間 165,824 ms
ジャッジサーバーID
(参考情報)
judge4 / judge5
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
other AC * 95 TLE * 1
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#pragma GCC optimize("Ofast")
#pragma GCC target ("sse4")
#include<iostream>
#include<string>
#include<cstdio>
#include<vector>
#include<cmath>
#include<algorithm>
#include<functional>
#include<iomanip>
#include<queue>
#include<ciso646>
#include<random>
#include<map>
#include<set>
#include<bitset>
#include<stack>
#include<unordered_map>
#include<unordered_set>
#include<utility>
#include<cassert>
#include<complex>
#include<numeric>
#include<array>
using namespace std;
//#define int long long
typedef long long ll;
typedef unsigned long long ul;
typedef unsigned int ui;
constexpr ll mod = 1000000007;
const ll INF = mod * mod;
typedef pair<int, int>P;
#define stop char nyaa;cin>>nyaa;
#define rep(i,n) for(int i=0;i<n;i++)
#define per(i,n) for(int i=n-1;i>=0;i--)
#define Rep(i,sta,n) for(int i=sta;i<n;i++)
#define rep1(i,n) for(int i=1;i<=n;i++)
#define per1(i,n) for(int i=n;i>=1;i--)
#define Rep1(i,sta,n) for(int i=sta;i<=n;i++)
#define all(v) (v).begin(),(v).end()
typedef pair<ll, ll> LP;
typedef long double ld;
typedef pair<ld, ld> LDP;
const ld eps = 1e-12;
const ld pi = acosl(-1.0);
ll mod_pow(ll x, ll n, ll m = mod) {
ll res = 1;
while (n) {
if (n & 1)res = res * x % m;
x = x * x % m; n >>= 1;
}
return res;
}
struct modint {
ll n;
modint() :n(0) { ; }
modint(ll m) :n(m) {
if (n >= mod)n %= mod;
else if (n < 0)n = (n % mod + mod) % mod;
}
operator int() { return n; }
};
bool operator==(modint a, modint b) { return a.n == b.n; }
modint operator+=(modint& a, modint b) { a.n += b.n; if (a.n >= mod)a.n -= mod; return a; }
modint operator-=(modint& a, modint b) { a.n -= b.n; if (a.n < 0)a.n += mod; return a; }
modint operator*=(modint& a, modint b) { a.n = ((ll)a.n * b.n) % mod; return a; }
modint operator+(modint a, modint b) { return a += b; }
modint operator-(modint a, modint b) { return a -= b; }
modint operator*(modint a, modint b) { return a *= b; }
modint operator^(modint a, ll n) {
if (n == 0)return modint(1);
modint res = (a * a) ^ (n / 2);
if (n % 2)res = res * a;
return res;
}
ll inv(ll a, ll p) {
return (a == 1 ? 1 : (1 - p * inv(p % a, a)) / a + p);
}
modint operator/(modint a, modint b) { return a * modint(inv(b, mod)); }
const int max_n = 1 << 21;
modint fact[max_n], factinv[max_n];
void init_f() {
fact[0] = modint(1);
for (int i = 0; i < max_n - 1; i++) {
fact[i + 1] = fact[i] * modint(i + 1);
}
factinv[max_n - 1] = modint(1) / fact[max_n - 1];
for (int i = max_n - 2; i >= 0; i--) {
factinv[i] = factinv[i + 1] * modint(i + 1);
}
}
modint comb(int a, int b) {
if (a < 0 || b < 0 || a < b)return 0;
return fact[a] * factinv[b] * factinv[a - b];
}
int mebius[1 << 20];
vector<int> chcnt(1 << 20);
int loc[1 << 20];
vector<int> ch[1 << 20];
bool isp[1 << 20];
void init() {
fill(isp + 2, isp + (1 << 20), true);
fill(mebius, mebius + (1 << 20), 1);
for (int i = 2; i < (1 << 20); i++) {
if (!isp[i])continue;
mebius[i] *= -1;
for (int j = 2 * i; j < (1 << 20); j += i) {
isp[j] = false;
mebius[j] *= -1;
if ((j / i) % i == 0) {
mebius[j] = 0;
}
}
}
for (int i = 2; i < (1 << 20); i++) {
for (int j = i; j < (1 << 20); j += i) {
chcnt[j]++;
}
}
for (int i = 2; i < (1 << 20); i++)ch[i].resize(chcnt[i]);
for (int i = 2; i < (1 << 20); i++) {
for (int j = i; j < (1 << 20); j += i) {
ch[j][loc[j]]= i; loc[j]++;
}
}
}
void solve() {
int n, m; cin >> n >> m;
vector<int> cnt(n+1);
rep(i, m) {
int a; cin >> a; cnt[a]++;
}
ll ans = 0;
vector<ll> num;
rep1(i, n) {
if (cnt[i] == 0)continue;
ll s = 0;
num.clear();
num.resize(ch[i].size());
for (int j = ch[i].size() - 1; j >= 0; j--) {
num[j] = i / ch[i][j];
for (int k = j + 1; k < ch[i].size(); k++) {
if (ch[i][k] % ch[i][j] == 0) {
num[j] += mebius[ch[i][k] / ch[i][j]] * (i / ch[i][k]);
}
}
}
ll sum = 0;
rep(j, ch[i].size()) {
int d = ch[i][j];
sum += (d - 1) * num[j];
}
ans += cnt[i]*sum;
}
cout << ans << "\n";
}
signed main() {
ios::sync_with_stdio(false);
cin.tie(0);
//cout << fixed << setprecision(15);
//init_f();
init();
//expr();
//int t; cin >> t; rep(i, t)
solve();
return 0;
}
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