結果

問題 No.1266 7 Colors
ユーザー packer_jp
提出日時 2020-10-23 22:40:03
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 331 ms / 3,000 ms
コード長 5,011 bytes
コンパイル時間 2,225 ms
コンパイル使用メモリ 208,080 KB
最終ジャッジ日時 2025-01-15 13:35:24
ジャッジサーバーID
(参考情報)
judge4 / judge1
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 19
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
using namespace std;
#define int long long
#define rep(i, n) for (int i = 0; i < (int) (n); i++)
#define reps(i, n) for (int i = 1; i <= (int) (n); i++)
#define all(a) (a).begin(), (a).end()
#define uniq(a) (a).erase(unique(all(a)), (a).end())
#define bit(n) (1LL << (n))
#define dump(a) cerr << #a " = " << (a) << endl
using vint = vector<int>;
using pint = pair<int, int>;
using vpint = vector<pint>;
template<typename T> using priority_queue_rev = priority_queue<T, vector<T>, greater<T>>;
constexpr double PI = 3.1415926535897932384626433832795028;
constexpr int DY[9] = {0, 1, 0, -1, 1, 1, -1, -1, 0};
constexpr int DX[9] = {1, 0, -1, 0, 1, -1, -1, 1, 0};
int sign(int a) { return (a > 0) - (a < 0); }
int cdiv(int a, int b) { return (a - 1 + b) / b; }
template<typename T> void fin(T a) {
cout << a << endl;
exit(0);
}
template<typename T> T sq(T a) { return a * a; }
template<typename T, typename U> bool chmax(T &a, const U &b) {
if (a < b) {
a = b;
return true;
}
return false;
}
template<typename T, typename U> bool chmin(T &a, const U &b) {
if (b < a) {
a = b;
return true;
}
return false;
}
template<typename T, typename U> ostream &operator<<(ostream &os, const pair<T, U> &a) {
os << "(" << a.first << ", " << a.second << ")";
return os;
}
template<typename T, typename U, typename V> ostream &operator<<(ostream &os, const tuple<T, U, V> &a) {
os << "(" << get<0>(a) << ", " << get<1>(a) << ", " << get<2>(a) << ")";
return os;
}
template<typename T> ostream &operator<<(ostream &os, const vector<T> &a) {
os << "{";
for (auto itr = a.begin(); itr != a.end(); itr++) {
os << *itr << (next(itr) != a.end() ? ", " : "");
}
os << "}";
return os;
}
template<typename T> ostream &operator<<(ostream &os, const deque<T> &a) {
os << "{";
for (auto itr = a.begin(); itr != a.end(); itr++) {
os << *itr << (next(itr) != a.end() ? ", " : "");
}
os << "}";
return os;
}
template<typename T> ostream &operator<<(ostream &os, const set<T> &a) {
os << "{";
for (auto itr = a.begin(); itr != a.end(); itr++) {
os << *itr << (next(itr) != a.end() ? ", " : "");
}
os << "}";
return os;
}
template<typename T> ostream &operator<<(ostream &os, const multiset<T> &a) {
os << "{";
for (auto itr = a.begin(); itr != a.end(); itr++) {
os << *itr << (next(itr) != a.end() ? ", " : "");
}
os << "}";
return os;
}
template<typename T, typename U> ostream &operator<<(ostream &os, const map<T, U> &a) {
os << "{";
for (auto itr = a.begin(); itr != a.end(); itr++) {
os << *itr << (next(itr) != a.end() ? ", " : "");
}
os << "}";
return os;
}
struct setup {
static constexpr int PREC = 20;
setup() {
cout << fixed << setprecision(PREC);
cerr << fixed << setprecision(PREC);
};
} setup;
template<typename S>
struct union_find_tree {
using T = typename S::T;
std::vector<int> par, sz;
std::vector<T> val;
union_find_tree(const std::vector<T> &val) : par(val.size(), -1), sz(val.size(), 1), val(val) {}
union_find_tree(int n, const T &x = {}) : union_find_tree(std::vector<T>(n, x)) {}
int root(int i) {
if (par[i] == -1) { return i; }
else { return par[i] = root(par[i]); }
}
void unite(int i, int j) {
if ((i = root(i)) == (j = root(j))) { return; }
if (sz[i] < sz[j]) { std::swap(i, j); }
sz[i] += sz[j];
val[i] = S::op(val[i], val[j]);
par[j] = i;
}
bool same(int i, int j) { return root(i) == root(j); }
int size(int i) { return sz[root(i)]; }
T &operator[](int i) { return val[root(i)]; }
};
struct normal_uf {
struct T {};
static T op(const T &a, const T &b) { return {}; }
};
signed main() {
int N, M, Q;
cin >> N >> M >> Q;
vector<string> s(N);
union_find_tree<normal_uf> uf(7 * N);
rep(i, N) {
cin >> s[i];
rep(j, 7) {
if (s[i][j] == '1' && s[i][(j + 1) % 7] == '1') {
uf.unite(i * 7 + j, i * 7 + (j + 1) % 7);
}
}
}
vint u(M), v(M);
vector adj(N, vint());
rep(i, M) {
cin >> u[i] >> v[i], u[i]--, v[i]--;
adj[u[i]].emplace_back(v[i]);
adj[v[i]].emplace_back(u[i]);
rep(j, 7) {
if (s[u[i]][j] == '1' && s[v[i]][j] == '1') { uf.unite(u[i] * 7 + j, v[i] * 7 + j); }
}
}
while (Q--) {
int q, x, y;
cin >> q >> x >> y, x--, y--;
if (q == 1) {
s[x][y] = '1';
if (s[x][(y + 6) % 7] == '1') { uf.unite(x * 7 + y, x * 7 + (y + 6) % 7); }
if (s[x][(y + 1) % 7] == '1') { uf.unite(x * 7 + y, x * 7 + (y + 1) % 7); }
for (int to:adj[x]) {
if (s[to][y] == '1') { uf.unite(x * 7 + y, to * 7 + y); }
}
} else {
cout << uf.size(x * 7) << endl;
}
}
}
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