結果

問題 No.1265 Balloon Survival
コンテスト
ユーザー uchiiii
提出日時 2020-10-24 00:00:10
言語 C++17(gcc12)
(gcc 12.3.0 + boost 1.87.0)
結果
WA  
実行時間 -
コード長 4,094 bytes
コンパイル時間 11,585 ms
コンパイル使用メモリ 288,344 KB
最終ジャッジ日時 2025-01-15 14:29:20
ジャッジサーバーID
（参考情報） 		judge5 / judge1
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 4
other AC * 31 WA * 1
権限があれば一括ダウンロードができます
コンパイルメッセージ
main.cpp: In function 'int main()':
main.cpp:69:28: warning: narrowing conversion of 'dist.main()::<lambda(int, int)>(i, j)' from 'double' to 'long long int' [-Wnarrowing]
   69 |             st.insert({dist(i,j), {i, j}});
      |                        ~~~~^~~~~

ソースコード

diff # 

#pragma GCC target("avx2")
#pragma GCC optimize("03")
#pragma GCC optimize("unroll-loops")
#include <bits/stdc++.h>
using namespace std; using ld = long double; using ll = long long;
using ull = unsigned long long;
#define endl "\n"
#define FOR(i,a,b) for(int i=(a);i<=(b);i++)
#define rep(i,n) for(int i=0;i<(n);i++)
#define REP(i,a,b) for(int i=(a);i<(b);i++)
#define PII pair<int, int>
#define PLL pair<ll, ll>
#define ALL(x) (x).begin(), (x).end()
#define QUERY int num_query;cin>>num_query; while(num_query--)
// int dx[] = {1, 0, -1, 0}; int dy[] = {0, 1, 0, -1};
constexpr int INF=1<<30;
constexpr ll LINF=1LL<<60; 
constexpr ll mod=1e9+7;
void flush() {cout<<flush;}
template <typename T> static constexpr T inf = numeric_limits<T>::max()/2;
template<class T>vector<T> vec(int len, T elem) { return vector<T>(len, elem); } // auto dp = vec(52, vec(103, vec(103, INF)));
template<class T>inline bool chmax(T &a, const T &b) { if (a<b) { a = b; return 1; } return 0; }
template<class T>inline bool chmin(T &a, const T &b) { if (b<a) { a = b; return 1; } return 0; }
template<class T>inline int popcount(T a) {return __builtin_popcountll(a);}
template<class T>inline T emod(T a, T p) { return (a%p + p) % p;}
template <typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &pa) { os << '(' << pa.first << ',' << pa.second << ')'; return os; }
template <typename T> istream &operator>>(istream &is, vector<T> &vec) { for (auto &v : vec) is >> v; return is; }
template <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) {os << '\n'; for (auto v : vec) os << v << ' '; os << '\n'; return os;}
template <typename T> ostream &operator<<(ostream &os, const deque<T> &vec) { os << "deq["; for (auto v : vec) os << v << ','; os << ']'; return os; }
template <typename T> ostream &operator<<(ostream &os, const set<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }
template <typename T> ostream &operator<<(ostream &os, const unordered_set<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }
template <typename T> ostream &operator<<(ostream &os, const multiset<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }
template <typename T> ostream &operator<<(ostream &os, const unordered_multiset<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }
template <typename TK, typename TV> ostream &operator<<(ostream &os, const map<TK, TV> &mp) { os << '{'; for (auto v : mp) os << v.first << "=>" << v.second << ','; os << '}'; return os; }
template <typename TK, typename TV> ostream &operator<<(ostream &os, const unordered_map<TK, TV> &mp) { os << '{'; for (auto v : mp) os << v.first << "=>" << v.second << ','; os << '}'; return os; }
struct MyIO {
    MyIO(){
        cin.tie(0); 
        ios::sync_with_stdio(false); 
        cout << fixed << setprecision(15);
    }
} IO_OI;
#ifdef LOCAL
void debug_out() { cerr << endl; }
template <typename Head, typename... Tail>
void debug_out(Head H, Tail... T) {
    cerr << " " << H;
    debug_out(T...);
}
#define debug(...) \
    cerr << __LINE__ << " [" << #__VA_ARGS__ << "]:", debug_out(__VA_ARGS__)
#define dump(x) cerr << __LINE__ << " " << #x << " = " << (x) << endl
#else
#define debug(...) (void(0))
#define dump(x) (void(0))
#endif
//-------------------
int main() {
    int n;cin>>n;
    vector<ll> x(n), y(n);
    rep(i,n) cin>>x[i]>>y[i];
    auto dist = [&](int i, int j) {
        return pow(abs(x[i]-x[j]), 2) + pow(abs(y[i]-y[j]), 2);
    };

    set<pair<ll, PII>> st;
    rep(i,n) {
        REP(j, i+1, n) {
            st.insert({dist(i,j), {i, j}});
        }
    }
    set<int> del;
    int ans = 0;
    for(auto [d, c]: st) {
        if(c.first==0) {
            if(del.count(c.second)==0) {
                del.insert(c.second);
                ans++;
            }
            continue;
        }
        if(del.count(c.first)==0 and del.count(c.second)==0) {
            del.insert(c.first);
            del.insert(c.second);
        } 
    }
    cout << ans << endl;

}
0