結果

問題 No.1270 Range Arrange Query
ユーザー packer_jppacker_jp
提出日時 2020-10-24 00:01:07
言語 C++17
(gcc 12.3.0 + boost 1.83.0)
結果
MLE  
実行時間 -
コード長 3,790 bytes
コンパイル時間 2,258 ms
コンパイル使用メモリ 204,424 KB
実行使用メモリ 808,512 KB
最終ジャッジ日時 2023-09-28 19:22:33
合計ジャッジ時間 12,022 ms
ジャッジサーバーID
(参考情報)
judge15 / judge12
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 1 ms
4,376 KB
testcase_01 MLE -
testcase_02 AC 2 ms
4,380 KB
testcase_03 AC 2 ms
4,380 KB
testcase_04 AC 2 ms
4,376 KB
testcase_05 AC 2 ms
4,380 KB
testcase_06 AC 793 ms
63,308 KB
testcase_07 MLE -
testcase_08 -- -
testcase_09 -- -
testcase_10 -- -
testcase_11 -- -
testcase_12 -- -
testcase_13 -- -
testcase_14 -- -
testcase_15 -- -
testcase_16 -- -
testcase_17 -- -
権限があれば一括ダウンロードができます

ソースコード

diff #

#include <bits/stdc++.h>
using namespace std;

#define rep(i, n) for (int i = 0; i < (int) (n); i++)
#define reps(i, n) for (int i = 1; i <= (int) (n); i++)
#define all(a) (a).begin(), (a).end()
#define uniq(a) (a).erase(unique(all(a)), (a).end())
#define bit(n) (1LL << (n))
#define dump(a) cerr << #a " = " << (a) << endl
using vint = vector<int>;
using pint = pair<int, int>;
using vpint = vector<pint>;
template<typename T> using priority_queue_rev = priority_queue<T, vector<T>, greater<T>>;
constexpr double PI = 3.1415926535897932384626433832795028;
constexpr int DY[9] = {0, 1, 0, -1, 1, 1, -1, -1, 0};
constexpr int DX[9] = {1, 0, -1, 0, 1, -1, -1, 1, 0};
int sign(int a) { return (a > 0) - (a < 0); }
int cdiv(int a, int b) { return (a - 1 + b) / b; }
template<typename T> void fin(T a) {
    cout << a << endl;
    exit(0);
}
template<typename T> T sq(T a) { return a * a; }
template<typename T, typename U> bool chmax(T &a, const U &b) {
    if (a < b) {
        a = b;
        return true;
    }
    return false;
}
template<typename T, typename U> bool chmin(T &a, const U &b) {
    if (b < a) {
        a = b;
        return true;
    }
    return false;
}
template<typename T, typename U> ostream &operator<<(ostream &os, const pair<T, U> &a) {
    os << "(" << a.first << ", " << a.second << ")";
    return os;
}
template<typename T, typename U, typename V> ostream &operator<<(ostream &os, const tuple<T, U, V> &a) {
    os << "(" << get<0>(a) << ", " << get<1>(a) << ", " << get<2>(a) << ")";
    return os;
}
template<typename T> ostream &operator<<(ostream &os, const vector<T> &a) {
    os << "{";
    for (auto itr = a.begin(); itr != a.end(); itr++) {
        os << *itr << (next(itr) != a.end() ? ", " : "");
    }
    os << "}";
    return os;
}
template<typename T> ostream &operator<<(ostream &os, const deque<T> &a) {
    os << "{";
    for (auto itr = a.begin(); itr != a.end(); itr++) {
        os << *itr << (next(itr) != a.end() ? ", " : "");
    }
    os << "}";
    return os;
}
template<typename T> ostream &operator<<(ostream &os, const set<T> &a) {
    os << "{";
    for (auto itr = a.begin(); itr != a.end(); itr++) {
        os << *itr << (next(itr) != a.end() ? ", " : "");
    }
    os << "}";
    return os;
}
template<typename T> ostream &operator<<(ostream &os, const multiset<T> &a) {
    os << "{";
    for (auto itr = a.begin(); itr != a.end(); itr++) {
        os << *itr << (next(itr) != a.end() ? ", " : "");
    }
    os << "}";
    return os;
}
template<typename T, typename U> ostream &operator<<(ostream &os, const map<T, U> &a) {
    os << "{";
    for (auto itr = a.begin(); itr != a.end(); itr++) {
        os << *itr << (next(itr) != a.end() ? ", " : "");
    }
    os << "}";
    return os;
}
struct setup {
    static constexpr int PREC = 20;
    setup() {
        cout << fixed << setprecision(PREC);
        cerr << fixed << setprecision(PREC);
    };
} setup;

signed main() {
    int N, Q;
    cin >> N >> Q;
    vint A(N);
    rep(i, N) { cin >> A[i], A[i]--; }
    vector imos(N + 1, vint(N + 1));
    rep(i, N + 1) {
        vint src(N);
        rep(j, N) { if (A[j] < i) { src[j]++; }}
        rep(j, N) { imos[i][j + 1] = imos[i][j] + src[j]; }
    }
    rep(i, Q) {
        int l, r;
        cin >> l >> r, l--;
        int ans = 0;
        rep(j, l) {
            ans += imos[A[j]][l] - imos[A[j]][j];
            ans += imos[A[j]][N] - imos[A[j]][r];
        }
        for (int j = r; j < N; j++) {
            ans += imos[A[j]][N] - imos[A[j]][j];
        }
        int m = INT_MAX;
        rep(j, N) {
            int cur = 0;
            cur += imos[j][N] - imos[j][r];
            cur += l - imos[j + 1][l];
            chmin(m, cur * (r - l));
        }
        ans += m;
        cout << ans << endl;
    }

}
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