結果

問題 No.1266 7 Colors
ユーザー tnakao0123
提出日時 2020-10-24 22:53:31
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 162 ms / 3,000 ms
コード長 2,884 bytes
コンパイル時間 895 ms
コンパイル使用メモリ 98,720 KB
実行使用メモリ 17,800 KB
最終ジャッジ日時 2024-07-21 15:48:19
合計ジャッジ時間 4,768 ms
ジャッジサーバーID
(参考情報)
judge2 / judge5
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 19
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

/* -*- coding: utf-8 -*-
*
* 1266.cc: No.1266 7 Colors - yukicoder
*/
#include<cstdio>
#include<cstdlib>
#include<cstring>
#include<cmath>
#include<iostream>
#include<string>
#include<vector>
#include<map>
#include<set>
#include<stack>
#include<list>
#include<queue>
#include<deque>
#include<algorithm>
#include<numeric>
#include<utility>
#include<complex>
#include<functional>
using namespace std;
/* constant */
const int MAX_N = 100000;
const int C = 7;
const int MAX_GN = MAX_N * C;
/* typedef */
typedef vector<int> vi;
struct UFT {
int links[MAX_GN], ranks[MAX_GN], sizes[MAX_GN];
UFT() {}
void init(int n) {
for (int i = 0; i < n; i++) links[i] = i, ranks[i] = sizes[i] = 1;
}
int root(int i) {
int i0 = i;
while (links[i0] != i0) i0 = links[i0];
return (links[i] = i0);
}
int rank(int i) { return ranks[root(i)]; }
int size(int i) { return sizes[root(i)]; }
bool same(int i, int j) { return root(i) == root(j); }
int merge(int i0, int i1) {
int r0 = root(i0), r1 = root(i1), mr;
if (r0 == r1) return r0;
if (ranks[r0] == ranks[r1]) {
links[r1] = r0;
sizes[r0] += sizes[r1];
ranks[r0]++;
mr = r0;
}
else if (ranks[r0] > ranks[r1]) {
links[r1] = r0;
sizes[r0] += sizes[r1];
mr = r0;
}
else {
links[r0] = r1;
sizes[r1] += sizes[r0];
mr = r1;
}
return mr;
}
};
/* global variables */
int cbs[MAX_N];
vi nbrs[MAX_N];
UFT uft;
/* subroutines */
inline int upos(int i, int j) { return i * C + j; }
/* main */
int main() {
int n, m, qn;
scanf("%d%d%d", &n, &m, &qn);
uft.init(n * C);
for (int i = 0; i < n; i++) {
char s[16];
scanf("%s", s);
for (int j = 0, bj = 1; j < C; j++, bj <<= 1)
cbs[i] |= (bj * (s[j] - '0'));
for (int j = 0, bj = 1; j < C; j++, bj <<= 1) {
int j1 = (j + 1) % C, bj1 = (1 << j1);
if ((cbs[i] & bj) && (cbs[i] & bj1))
uft.merge(upos(i, j), upos(i, j1));
}
}
for (int i = 0; i < m; i++) {
int u, v;
scanf("%d%d", &u, &v);
u--, v--;
nbrs[u].push_back(v);
nbrs[v].push_back(u);
for (int j = 0, bj = 1; j < C; j++, bj <<= 1)
if ((cbs[u] & bj) && (cbs[v] & bj))
uft.merge(upos(u, j), upos(v, j));
}
while (qn--) {
int op, x, y;
scanf("%d%d%d", &op, &x, &y);
x--, y--;
if (op == 1) {
int by = 1 << y;
cbs[x] |= by;
int pxy = upos(x, y);
vi &nbrx = nbrs[x];
for (vi::iterator vit = nbrx.begin(); vit != nbrx.end(); vit++) {
int v = *vit;
if (cbs[v] & by)
uft.merge(pxy, upos(v, y));
}
int y0 = (y + C - 1) % C, y1 = (y + 1) % C;
if (cbs[x] & (1 << y0)) uft.merge(pxy, upos(x, y0));
if (cbs[x] & (1 << y1)) uft.merge(pxy, upos(x, y1));
}
else {
int sz = uft.size(upos(x, 0));
printf("%d\n", sz);
}
}
return 0;
}
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