結果

問題 No.1279 Array Battle
ユーザー packer_jppacker_jp
提出日時 2020-11-06 21:29:41
言語 C++17
(gcc 13.2.0 + boost 1.83.0)
結果
AC  
実行時間 8 ms / 2,000 ms
コード長 3,352 bytes
コンパイル時間 2,061 ms
コンパイル使用メモリ 204,296 KB
実行使用メモリ 4,380 KB
最終ジャッジ日時 2023-09-29 18:13:00
合計ジャッジ時間 2,874 ms
ジャッジサーバーID
（参考情報） 		judge15 / judge11
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 1 ms
4,376 KB
testcase_01 AC 1 ms
4,380 KB
testcase_02 AC 2 ms
4,380 KB
testcase_03 AC 1 ms
4,380 KB
testcase_04 AC 2 ms
4,380 KB
testcase_05 AC 2 ms
4,380 KB
testcase_06 AC 2 ms
4,380 KB
testcase_07 AC 2 ms
4,380 KB
testcase_08 AC 1 ms
4,380 KB
testcase_09 AC 1 ms
4,380 KB
testcase_10 AC 1 ms
4,376 KB
testcase_11 AC 1 ms
4,380 KB
testcase_12 AC 2 ms
4,380 KB
testcase_13 AC 2 ms
4,376 KB
testcase_14 AC 2 ms
4,380 KB
testcase_15 AC 7 ms
4,376 KB
testcase_16 AC 7 ms
4,380 KB
testcase_17 AC 7 ms
4,380 KB
testcase_18 AC 7 ms
4,380 KB
testcase_19 AC 8 ms
4,380 KB
権限があれば一括ダウンロードができます

ソースコード

diff # 

#include <bits/stdc++.h>
using namespace std;

#define int long long
#define rep(i, n) for (int i = 0; i < (int) (n); i++)
#define reps(i, n) for (int i = 1; i <= (int) (n); i++)
#define all(a) (a).begin(), (a).end()
#define uniq(a) (a).erase(unique(all(a)), (a).end())
#define bit(n) (1LL << (n))
#define dump(a) cerr << #a " = " << (a) << endl
#define fin(a) cout << (a) << endl; return
using vint = vector<int>;
using pint = pair<int, int>;
using vpint = vector<pint>;
template<typename T> using priority_queue_rev = priority_queue<T, vector<T>, greater<T>>;
constexpr double PI = 3.1415926535897932384626433832795028;
constexpr int DY[9] = {0, 1, 0, -1, 1, 1, -1, -1, 0};
constexpr int DX[9] = {1, 0, -1, 0, 1, -1, -1, 1, 0};
int sign(int a) { return (a > 0) - (a < 0); }
int cdiv(int a, int b) { return (a - 1 + b) / b; }
template<typename T> T sq(T a) { return a * a; }
template<typename T, typename U> bool chmax(T &a, const U &b) {
    if (a < b) {
        a = b;
        return true;
    }
    return false;
}
template<typename T, typename U> bool chmin(T &a, const U &b) {
    if (b < a) {
        a = b;
        return true;
    }
    return false;
}
template<typename T, typename U> ostream &operator<<(ostream &os, const pair<T, U> &a) {
    os << "(" << a.first << ", " << a.second << ")";
    return os;
}
template<typename T, typename U, typename V> ostream &operator<<(ostream &os, const tuple<T, U, V> &a) {
    os << "(" << get<0>(a) << ", " << get<1>(a) << ", " << get<2>(a) << ")";
    return os;
}
template<typename T> ostream &operator<<(ostream &os, const vector<T> &a) {
    os << "(";
    for (auto itr = a.begin(); itr != a.end(); itr++) {
        os << *itr << (next(itr) != a.end() ? ", " : "");
    }
    os << ")";
    return os;
}
template<typename T> ostream &operator<<(ostream &os, const deque<T> &a) {
    os << "(";
    for (auto itr = a.begin(); itr != a.end(); itr++) {
        os << *itr << (next(itr) != a.end() ? ", " : "");
    }
    os << ")";
    return os;
}
template<typename T> ostream &operator<<(ostream &os, const set<T> &a) {
    os << "{";
    for (auto itr = a.begin(); itr != a.end(); itr++) {
        os << *itr << (next(itr) != a.end() ? ", " : "");
    }
    os << "}";
    return os;
}
template<typename T> ostream &operator<<(ostream &os, const multiset<T> &a) {
    os << "{";
    for (auto itr = a.begin(); itr != a.end(); itr++) {
        os << *itr << (next(itr) != a.end() ? ", " : "");
    }
    os << "}";
    return os;
}
template<typename T, typename U> ostream &operator<<(ostream &os, const map<T, U> &a) {
    os << "{";
    for (auto itr = a.begin(); itr != a.end(); itr++) {
        os << *itr << (next(itr) != a.end() ? ", " : "");
    }
    os << "}";
    return os;
}
void solve();

signed main() {
    static constexpr int PREC = 20;
    cout << fixed << setprecision(PREC);
    cerr << fixed << setprecision(PREC);
    solve();
}
void solve() {
    int N;
    cin >> N;
    vint a(N), b(N);
    rep(i, N) { cin >> a[i]; }
    rep(i, N) { cin >> b[i]; }
    vint idx(N);
    iota(all(idx), 0);
    int m = 0, ans = 0;
    do {
        int cur = 0;
        rep(i, N) {
            cur += max(0LL, a[idx[i]] - b[i]);
        }
        if (cur == m) { ans++; }
        else if (cur > m) { ans = 1, m = cur; }
    } while (next_permutation(all(idx)));
    cout << ans << endl;
}
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