結果
| 問題 |
No.1284 Flip Game
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2020-11-06 22:04:06 |
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 64 ms / 2,000 ms |
| コード長 | 2,057 bytes |
| コンパイル時間 | 2,248 ms |
| コンパイル使用メモリ | 210,044 KB |
| 最終ジャッジ日時 | 2025-01-15 20:43:22 |
|
ジャッジサーバーID (参考情報) |
judge4 / judge4 |
(要ログイン)
| ファイルパターン | 結果 |
|---|---|
| other | AC * 28 |
ソースコード
#include <bits/stdc++.h>
#define REP(i, n) for (int i = 0; (i) < (int)(n); ++(i))
#define REP3(i, m, n) for (int i = (m); (i) < (int)(n); ++(i))
#define REP_R(i, n) for (int i = (int)(n)-1; (i) >= 0; --(i))
#define REP3R(i, m, n) for (int i = (int)(n)-1; (i) >= (int)(m); --(i))
#define ALL(x) ::std::begin(x), ::std::end(x)
using namespace std;
template <class T> using reversed_priority_queue = priority_queue<T, vector<T>, greater<T> >;
int64_t solve(int n, const vector<vector<int64_t> >& c) {
vector<int> three(n + 1);
three[0] = 1;
REP (i, n) {
three[i + 1] = 3 * three[i];
}
// dijkstra
vector<vector<int64_t> > dist(n, vector<int64_t>(three[n], INT64_MAX));
reversed_priority_queue<tuple<int64_t, int, int> > que;
REP (p, n) {
dist[p][three[p]] = 0;
que.emplace(0, p, three[p]);
}
while (not que.empty()) {
int64_t dist_q_s; int q, s; tie(dist_q_s, q, s) = que.top();
que.pop();
if (dist[q][s] < dist_q_s) continue;
vector<int> cur(n);
{
int t = s;
REP (p, n) {
cur[p] = t % 3;
t /= 3;
}
}
REP (p, n) if (cur[p] != 2 and p != q) {
int t = s + three[p];
if (dist[q][s] + c[q][p] < dist[p][t]) {
dist[p][t] = dist[q][s] + c[q][p];
que.emplace(dist[p][t], p, t);
}
}
}
int64_t ans = INT64_MAX;
REP (p, n) {
ans = min(ans, dist[p][three[n] - 1]);
ans = min(ans, dist[p][three[n] - 1 - three[p]]);
}
return ans;
}
// generated by online-judge-template-generator v4.7.1 (https://github.com/online-judge-tools/template-generator)
int main() {
std::ios::sync_with_stdio(false);
std::cin.tie(nullptr);
constexpr char endl = '\n';
int N;
cin >> N;
vector<vector<int64_t> > c(N, vector<int64_t>(N));
REP (j, N) {
REP (i, N) { cin >> c[j][i]; }
}
auto ans = solve(N, c);
cout << ans << endl;
return 0;
}