結果

問題 No.1302 Random Tree Score
ユーザー Kite_kuma
提出日時 2020-11-09 12:22:21
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 753 ms / 3,000 ms
コード長 4,102 bytes
コンパイル時間 1,703 ms
コンパイル使用メモリ 176,092 KB
実行使用メモリ 9,304 KB
最終ジャッジ日時 2024-07-22 16:00:26
合計ジャッジ時間 8,212 ms
ジャッジサーバーID
(参考情報)
judge4 / judge3
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 14
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

/* author: Kite_kuma
created: 2020.11.09 12:08:40 */
// #ifdef LOCAL
// #define _GLIBCXX_DEBUG
// #endif
#include <bits/stdc++.h>
using namespace std;
const int mod = 998244353;
const int root = 3;
unsigned int add(const unsigned int x, const unsigned int y) { return (x + y < mod) ? x + y : x + y - mod; }
unsigned int sub(const unsigned int x, const unsigned int y) { return (x >= y) ? (x - y) : (mod - y + x); }
unsigned int mul(const unsigned int x, const unsigned int y) { return (unsigned long long)x * y % mod; }
unsigned int mod_pow(unsigned int x, unsigned int n) {
unsigned int res = 1;
while(n > 0) {
if(n & 1) {
res = mul(res, x);
}
x = mul(x, x);
n >>= 1;
}
return res;
}
unsigned int inverse(const unsigned int x) { return mod_pow(x, mod - 2); }
void ntt(vector<int> &a, const bool rev = false) {
unsigned int i, j, k, l, p, q, r, s;
const unsigned int size = a.size();
if(size == 1) return;
vector<int> b(size);
r = rev ? (mod - 1 - (mod - 1) / size) : (mod - 1) / size;
s = mod_pow(root, r);
vector<unsigned int> kp(size / 2 + 1, 1);
for(i = 0; i < size / 2; ++i) kp[i + 1] = mul(kp[i], s);
for(i = 1, l = size / 2; i < size; i <<= 1, l >>= 1) {
for(j = 0, r = 0; j < l; ++j, r += i) {
for(k = 0, s = kp[i * j]; k < i; ++k) {
p = a[k + r], q = a[k + r + size / 2];
b[k + 2 * r] = add(p, q);
b[k + 2 * r + i] = mul(sub(p, q), s);
}
}
swap(a, b);
}
if(rev) {
s = inverse(size);
for(i = 0; i < size; i++) {
a[i] = mul(a[i], s);
}
}
}
vector<int> convolute(const vector<int> &a, const vector<int> &b) {
const int size = (int)a.size() + (int)b.size() - 1;
int t = 1;
while(t < size) {
t <<= 1;
}
vector<int> A(t, 0), B(t, 0);
for(int i = 0; i < (int)a.size(); i++) {
A[i] = a[i];
}
for(int i = 0; i < (int)b.size(); i++) {
B[i] = b[i];
}
ntt(A), ntt(B);
for(int i = 0; i < t; i++) {
A[i] = mul(A[i], B[i]);
}
ntt(A, true);
A.resize(size);
return A;
}
#pragma region modint
template <int mod>
struct ModInt {
int x;
ModInt() : x(0) {}
ModInt(long long y) : x(y >= 0 ? y % mod : (mod - (-y) % mod) % mod) {}
ModInt &operator+=(const ModInt &p) {
if((x += p.x) >= mod) x -= mod;
return *this;
}
ModInt &operator-=(const ModInt &p) {
if((x += mod - p.x) >= mod) x -= mod;
return *this;
}
ModInt &operator*=(const ModInt &p) {
x = (int)(1LL * x * p.x % mod);
return *this;
}
ModInt &operator/=(const ModInt &p) {
*this *= p.inverse();
return *this;
}
ModInt operator-() const { return ModInt(-x); }
ModInt operator+(const ModInt &p) const { return ModInt(*this) += p; }
ModInt operator-(const ModInt &p) const { return ModInt(*this) -= p; }
ModInt operator*(const ModInt &p) const { return ModInt(*this) *= p; }
ModInt operator/(const ModInt &p) const { return ModInt(*this) /= p; }
bool operator==(const ModInt &p) const { return x == p.x; }
bool operator!=(const ModInt &p) const { return x != p.x; }
ModInt inverse() const {
int a = x, b = mod, u = 1, v = 0, t;
while(b > 0) {
t = a / b;
swap(a -= t * b, b);
swap(u -= t * v, v);
}
return ModInt(u);
}
ModInt pow(long long n) const {
ModInt ret(1), mul(x);
while(n > 0) {
if(n & 1) ret *= mul;
mul *= mul;
n >>= 1;
}
return ret;
}
friend ostream &operator<<(ostream &os, const ModInt &p) { return os << p.x; }
friend istream &operator>>(istream &is, ModInt &a) {
long long t;
is >> t;
a = ModInt<mod>(t);
return (is);
}
static int get_mod() { return mod; }
};
using mint = ModInt<mod>;
#pragma endregion
int main() {
int n;
cin >> n;
vector<mint> fac(n + 2);
fac[0] = 1;
for(int i = 0; i < n + 1; i++) {
fac[i + 1] = fac[i] * (i + 1);
}
vector<int> fx(n - 1);
for(int i = 0; i < n - 1; i++) {
fx[i] = ((mint)(i + 1) / fac[i]).x;
}
int k = n;
vector<int> res = {1};
while(k) {
if(k & 1) {
res = convolute(res, fx);
if(res.size() >= n) res.resize(n - 1);
}
fx = convolute(fx, fx);
if(fx.size() >= n) fx.resize(n - 1);
k >>= 1;
}
res.resize(n - 1);
cout << fac[n - 2] * res[n - 2] / mod_pow(n, n - 2) << endl;
return 0;
}
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