結果
問題 | No.1302 Random Tree Score |
ユーザー |
![]() |
提出日時 | 2020-11-09 12:22:21 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 753 ms / 3,000 ms |
コード長 | 4,102 bytes |
コンパイル時間 | 1,703 ms |
コンパイル使用メモリ | 176,092 KB |
実行使用メモリ | 9,304 KB |
最終ジャッジ日時 | 2024-07-22 16:00:26 |
合計ジャッジ時間 | 8,212 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge3 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 14 |
ソースコード
/* author: Kite_kumacreated: 2020.11.09 12:08:40 */// #ifdef LOCAL// #define _GLIBCXX_DEBUG// #endif#include <bits/stdc++.h>using namespace std;const int mod = 998244353;const int root = 3;unsigned int add(const unsigned int x, const unsigned int y) { return (x + y < mod) ? x + y : x + y - mod; }unsigned int sub(const unsigned int x, const unsigned int y) { return (x >= y) ? (x - y) : (mod - y + x); }unsigned int mul(const unsigned int x, const unsigned int y) { return (unsigned long long)x * y % mod; }unsigned int mod_pow(unsigned int x, unsigned int n) {unsigned int res = 1;while(n > 0) {if(n & 1) {res = mul(res, x);}x = mul(x, x);n >>= 1;}return res;}unsigned int inverse(const unsigned int x) { return mod_pow(x, mod - 2); }void ntt(vector<int> &a, const bool rev = false) {unsigned int i, j, k, l, p, q, r, s;const unsigned int size = a.size();if(size == 1) return;vector<int> b(size);r = rev ? (mod - 1 - (mod - 1) / size) : (mod - 1) / size;s = mod_pow(root, r);vector<unsigned int> kp(size / 2 + 1, 1);for(i = 0; i < size / 2; ++i) kp[i + 1] = mul(kp[i], s);for(i = 1, l = size / 2; i < size; i <<= 1, l >>= 1) {for(j = 0, r = 0; j < l; ++j, r += i) {for(k = 0, s = kp[i * j]; k < i; ++k) {p = a[k + r], q = a[k + r + size / 2];b[k + 2 * r] = add(p, q);b[k + 2 * r + i] = mul(sub(p, q), s);}}swap(a, b);}if(rev) {s = inverse(size);for(i = 0; i < size; i++) {a[i] = mul(a[i], s);}}}vector<int> convolute(const vector<int> &a, const vector<int> &b) {const int size = (int)a.size() + (int)b.size() - 1;int t = 1;while(t < size) {t <<= 1;}vector<int> A(t, 0), B(t, 0);for(int i = 0; i < (int)a.size(); i++) {A[i] = a[i];}for(int i = 0; i < (int)b.size(); i++) {B[i] = b[i];}ntt(A), ntt(B);for(int i = 0; i < t; i++) {A[i] = mul(A[i], B[i]);}ntt(A, true);A.resize(size);return A;}#pragma region modinttemplate <int mod>struct ModInt {int x;ModInt() : x(0) {}ModInt(long long y) : x(y >= 0 ? y % mod : (mod - (-y) % mod) % mod) {}ModInt &operator+=(const ModInt &p) {if((x += p.x) >= mod) x -= mod;return *this;}ModInt &operator-=(const ModInt &p) {if((x += mod - p.x) >= mod) x -= mod;return *this;}ModInt &operator*=(const ModInt &p) {x = (int)(1LL * x * p.x % mod);return *this;}ModInt &operator/=(const ModInt &p) {*this *= p.inverse();return *this;}ModInt operator-() const { return ModInt(-x); }ModInt operator+(const ModInt &p) const { return ModInt(*this) += p; }ModInt operator-(const ModInt &p) const { return ModInt(*this) -= p; }ModInt operator*(const ModInt &p) const { return ModInt(*this) *= p; }ModInt operator/(const ModInt &p) const { return ModInt(*this) /= p; }bool operator==(const ModInt &p) const { return x == p.x; }bool operator!=(const ModInt &p) const { return x != p.x; }ModInt inverse() const {int a = x, b = mod, u = 1, v = 0, t;while(b > 0) {t = a / b;swap(a -= t * b, b);swap(u -= t * v, v);}return ModInt(u);}ModInt pow(long long n) const {ModInt ret(1), mul(x);while(n > 0) {if(n & 1) ret *= mul;mul *= mul;n >>= 1;}return ret;}friend ostream &operator<<(ostream &os, const ModInt &p) { return os << p.x; }friend istream &operator>>(istream &is, ModInt &a) {long long t;is >> t;a = ModInt<mod>(t);return (is);}static int get_mod() { return mod; }};using mint = ModInt<mod>;#pragma endregionint main() {int n;cin >> n;vector<mint> fac(n + 2);fac[0] = 1;for(int i = 0; i < n + 1; i++) {fac[i + 1] = fac[i] * (i + 1);}vector<int> fx(n - 1);for(int i = 0; i < n - 1; i++) {fx[i] = ((mint)(i + 1) / fac[i]).x;}int k = n;vector<int> res = {1};while(k) {if(k & 1) {res = convolute(res, fx);if(res.size() >= n) res.resize(n - 1);}fx = convolute(fx, fx);if(fx.size() >= n) fx.resize(n - 1);k >>= 1;}res.resize(n - 1);cout << fac[n - 2] * res[n - 2] / mod_pow(n, n - 2) << endl;return 0;}