結果
問題 | No.1287 えぬけー |
ユーザー |
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提出日時 | 2020-11-13 23:16:46 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 6,838 bytes |
コンパイル時間 | 2,191 ms |
コンパイル使用メモリ | 200,304 KB |
最終ジャッジ日時 | 2025-01-16 00:03:33 |
ジャッジサーバーID (参考情報) |
judge5 / judge1 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 4 |
other | WA * 1 TLE * 4 |
ソースコード
·#include "bits/stdc++.h"using namespace std;using ll=long long; using dd=double;using vll=vector< ll>; using vdd=vector< dd>;using vvll=vector< vll>; using vvdd=vector<vdd>;using vvvll=vector< vvll>;using vvvvll=vector<vvvll>;using pll=pair<ll,ll>; using tll=tuple<ll,ll,ll>; using qll=tuple<ll,ll,ll,ll>;using vpll=vector< pll>; using vtll=vector< tll>; using vqll=vector< qll>;using vvpll=vector<vpll>; using vvtll=vector<vtll>; using vvqll=vector<vqll>;constexpr ll INF = 1LL << 60;struct Fast{ Fast(){ cin.tie(0); ios::sync_with_stdio(false); cout<<fixed<<setprecision(numeric_limits<double>::max_digits10); } } fast;#define REPS(i, S, E) for (ll i = (S); i <= (E); i++)#define REP(i, N) REPS(i, 0, (N)-1)#define DEPS(i, S, E) for (ll i = (E); i >= (S); i--)#define DEP(i, N) DEPS(i, 0, (N)-1)#define rep(i, S, E) for (ll i = (S); i <= (E); i++)#define dep(i, E, S) for (ll i = (E); i >= (S); i--)#define each(e, v) for (auto&& e : v)#define ALL(v) (v).begin(), (v).end()#define RALL(v) (v).rbegin(), (v).rend()template<class T> inline bool chmax(T &a, T b) { if (a < b) { a = b; return true; }return false; }template<class T> inline bool chmin(T &a, T b) { if (a > b) { a = b; return true; }return false; }template<class T> inline T MaxE(vector<T>&v,ll S,ll E){ T m=v[S]; rep(i,S,E)chmax(m,v[i]); return m; }template<class T> inline T MinE(vector<T>&v,ll S,ll E){ T m=v[S]; rep(i,S,E)chmin(m,v[i]); return m; }template<class T> inline T MaxE(vector<T> &v) { return MaxE(v,0,(ll)v.size()-1); }template<class T> inline T MinE(vector<T> &v) { return MinE(v,0,(ll)v.size()-1); }template<class T> inline T Sum(vector<T> &v,ll S,ll E){ T s=T(); rep(i,S,E)s+=v[i]; return s; }template<class T> inline T Sum(vector<T> &v) { return Sum(v,0,v.size()-1); }template<class T> inline ll sz(T &v){ return (ll)v.size(); }inline ll CEIL(ll a,ll b){ return (a<0) ? -(-a/b) : (a+b-1)/b; }inline ll FLOOR(ll a,ll b){ return -CEIL(-a,b); }template<ll MOD> struct mll_{ll val;mll_(ll v = 0): val(v % MOD){ if (val < 0) val += MOD; }mll_ operator - () const { return -val; }mll_ operator + (const mll_ &b) const { return val + b.val; }mll_ operator - (const mll_ &b) const { return val - b.val; }mll_ operator * (const mll_ &b) const { return val * b.val; }mll_ operator / (const mll_ &b) const { return mll_(*this) /= b; }mll_ operator + (ll b) const { return *this + mll_(b); }mll_ operator - (ll b) const { return *this - mll_(b); }mll_ operator * (ll b) const { return *this * mll_(b); }friend mll_ operator + (ll a,const mll_ &b) { return b + a; }friend mll_ operator - (ll a,const mll_ &b) { return -b + a; }friend mll_ operator * (ll a,const mll_ &b) { return b * a; }friend mll_ operator / (ll a,const mll_ &b) { return mll_(a)/b; }mll_ &operator += (const mll_ &b) { val=(val+b.val)%MOD; return *this; }mll_ &operator -= (const mll_ &b) { val=(val+MOD-b.val)%MOD; return *this; }mll_ &operator *= (const mll_ &b) { val=(val*b.val)%MOD; return *this; }mll_ &operator /= (const mll_ &b) {ll c=b.val,d=MOD,u=1,v=0;while (d){ll t = c / d;c -= t * d; swap(c,d);u -= t * v; swap(u,v);}val = val * u % MOD;if (val < 0) val += MOD;return *this;}mll_ &operator += (ll b) { return *this += mll_(b); }mll_ &operator -= (ll b) { return *this -= mll_(b); }mll_ &operator *= (ll b) { return *this *= mll_(b); }mll_ &operator /= (ll b) { return *this /= mll_(b); }bool operator == (const mll_ &b) const { return val == b.val; }bool operator != (const mll_ &b) const { return val != b.val; }bool operator == (ll b) const { return *this == mll_(b); }bool operator != (ll b) const { return *this != mll_(b); }friend bool operator == (ll a,const mll_ &b) { return mll_(a) == b.val; }friend bool operator != (ll a,const mll_ &b) { return mll_(a) != b.val; }friend ostream &operator << (ostream &os,const mll_ &a) { return os << a.val; }friend istream &operator >> (istream &is,mll_ &a) { return is >> a.val; }static mll_ Combination(ll a,ll b){chmin(b,a-b);if (b<0) return mll_(0);mll_ c = 1;rep(i,0,b-1) c *= a-i;rep(i,0,b-1) c /= i+1;return c;}};using mll = mll_<1000000006LL>;using mllb = mll_<1000000007LL>;using vmll = std::vector<mll>;using vvmll = std::vector<vmll>;using vvvmll = std::vector<vvmll>;using vvvvmll = std::vector<vvvmll>;template<class T> inline T POW(T a,ll n){ T r=1; for (; n>0; n>>=1,a*=a){ if (n&1)r*=a; } return r; }inline ll POW(int a,ll n){ return POW((ll)a,n); }#if 0#include <atcoder/all>using namespace atcoder;#endifconst int MOD = 1000000007;// a^blong long modpow(long long a, long long n, long long mod) {long long res = 1;while (n > 0) {if (n & 1) res = res * a % mod;a = a * a % mod;n >>= 1;}return res;}// a^-1long long modinv(long long a, long long m) {long long b = m, u = 1, v = 0;while (b) {long long t = a / b;a -= t * b; swap(a, b);u -= t * v; swap(u, v);}u %= m;if (u < 0) u += m;return u;}const ll M=1000001;map<long long, long long> apow;void prep(long long a, int m){long long amari = a;for (long long r = 1; r < M; ++r) {if (!apow.count(amari)) apow[amari] = r;(amari *= a) %= m;}}// a^x ≡ b (mod. m) となる最小の正の整数 x を求めるlong long modlog(long long a, long long b, int m) {a %= m, b %= m;// calc sqrt{M}long long lo = -1, hi = m;while (hi - lo > 1) {long long mid = (lo + hi) / 2;if (mid * mid >= m) hi = mid;else lo = mid;}long long sqrtM = hi;// {a^0, a^1, a^2, ..., a^sqrt(m)}#if 0map<long long, long long> apow;long long amari = a;for (long long r = 1; r < sqrtM; ++r) {if (!apow.count(amari)) apow[amari] = r;(amari *= a) %= m;}#endif// check each A^plong long A = modpow(modinv(a, m), M, m);ll amari = b;for (long long q = 0; q < 1000; ++q) {if (amari == 1 && q > 0) return q * M;else if (apow.count(amari)) return q * M + apow[amari];(amari *= A) %= m;}// no solutionsreturn -1;}void solve(){//{// rep(i,2,10000000-1){// auto a=POW(mllb(i),2);// if (a==1){// continue;// }// a=POW(mllb(i),500000003);// if (a==1){// continue;// }// cout << i << '\n'; return;// }//}ll X,K; cin >> X >> K;//10^9+7の原始根 5ll x=modlog(5,X,MOD);mll xx=x;xx/=K;mllb ans=POW(mllb(5),xx.val);cout << ans << '\n';}int main(){#if 0solve();//cin2solve();//generand();#elsell t; cin >> t;prep(5,MOD);rep(i, 0, t-1){solve();//cin2solve();}#endifreturn 0;}