結果

問題 No.1287 えぬけー
ユーザー hamamuhamamu
提出日時 2020-11-13 23:18:20
言語 C++17
(gcc 12.3.0 + boost 1.83.0)
結果
TLE  
実行時間 -
コード長 6,884 bytes
コンパイル時間 2,266 ms
コンパイル使用メモリ 206,696 KB
実行使用メモリ 70,288 KB
最終ジャッジ日時 2023-09-30 04:17:22
合計ジャッジ時間 13,033 ms
ジャッジサーバーID
（参考情報） 		judge14 / judge12
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 1,203 ms
70,252 KB
testcase_01 AC 1,183 ms
65,912 KB
testcase_02 AC 1,191 ms
65,892 KB
testcase_03 AC 1,179 ms
65,868 KB
testcase_04 AC 1,180 ms
66,016 KB
testcase_05 TLE -
testcase_06 -- -
testcase_07 -- -
testcase_08 -- -
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ソースコード

diff # 

#include "bits/stdc++.h"
using namespace std;
using     ll=long long;     using   dd=double;     
using    vll=vector<   ll>; using  vdd=vector< dd>;
using   vvll=vector<  vll>; using vvdd=vector<vdd>;
using  vvvll=vector< vvll>;
using vvvvll=vector<vvvll>;
using   pll=pair<ll,ll>;  using   tll=tuple<ll,ll,ll>; using   qll=tuple<ll,ll,ll,ll>;
using  vpll=vector< pll>; using  vtll=vector< tll>;    using  vqll=vector< qll>;
using vvpll=vector<vpll>; using vvtll=vector<vtll>;    using vvqll=vector<vqll>;
constexpr ll INF = 1LL << 60;
struct Fast{ Fast(){ cin.tie(0); ios::sync_with_stdio(false); cout<<fixed<<setprecision(numeric_limits<double>::max_digits10); } } fast;
#define REPS(i, S, E) for (ll i = (S); i <= (E); i++)
#define REP(i, N) REPS(i, 0, (N)-1)
#define DEPS(i, S, E) for (ll i = (E); i >= (S); i--)
#define DEP(i, N) DEPS(i, 0, (N)-1)
#define rep(i, S, E)  for (ll i = (S); i <= (E); i++)
#define dep(i, E, S)  for (ll i = (E); i >= (S); i--)
#define each(e, v) for (auto&& e : v)
#define ALL(v) (v).begin(), (v).end()
#define RALL(v) (v).rbegin(), (v).rend()
template<class T> inline bool chmax(T &a, T b) { if (a < b) { a = b; return true; }return false; }
template<class T> inline bool chmin(T &a, T b) { if (a > b) { a = b; return true; }return false; }
template<class T> inline T MaxE(vector<T>&v,ll S,ll E){ T m=v[S]; rep(i,S,E)chmax(m,v[i]); return m; }
template<class T> inline T MinE(vector<T>&v,ll S,ll E){ T m=v[S]; rep(i,S,E)chmin(m,v[i]); return m; }
template<class T> inline T MaxE(vector<T> &v) { return MaxE(v,0,(ll)v.size()-1); }
template<class T> inline T MinE(vector<T> &v) { return MinE(v,0,(ll)v.size()-1); }
template<class T> inline T Sum(vector<T> &v,ll S,ll E){ T s=T(); rep(i,S,E)s+=v[i]; return s; }
template<class T> inline T Sum(vector<T> &v) { return Sum(v,0,v.size()-1); }
template<class T> inline ll sz(T &v){ return (ll)v.size(); }
inline ll CEIL(ll a,ll b){ return (a<0) ? -(-a/b) : (a+b-1)/b; }
inline ll FLOOR(ll a,ll b){ return -CEIL(-a,b); }


template<ll MOD> struct mll_{
	ll val;
	mll_(ll v = 0): val(v % MOD){ if (val < 0) val += MOD; }
	mll_ operator - () const { return -val; }
	mll_ operator + (const mll_ &b) const { return val + b.val; }
	mll_ operator - (const mll_ &b) const { return val - b.val; }
	mll_ operator * (const mll_ &b) const { return val * b.val; }
	mll_ operator / (const mll_ &b) const { return mll_(*this) /= b; }
	mll_ operator + (ll b) const { return *this + mll_(b); }
	mll_ operator - (ll b) const { return *this - mll_(b); }
	mll_ operator * (ll b) const { return *this * mll_(b); }
	friend mll_ operator + (ll a,const mll_ &b) { return b + a; }
	friend mll_ operator - (ll a,const mll_ &b) { return -b + a; }
	friend mll_ operator * (ll a,const mll_ &b) { return b * a; }
	friend mll_ operator / (ll a,const mll_ &b) { return mll_(a)/b; }
	mll_ &operator += (const mll_ &b) { val=(val+b.val)%MOD; return *this; }
	mll_ &operator -= (const mll_ &b) { val=(val+MOD-b.val)%MOD; return *this; }
	mll_ &operator *= (const mll_ &b) { val=(val*b.val)%MOD; return *this; }
	mll_ &operator /= (const mll_ &b) {
		ll c=b.val,d=MOD,u=1,v=0;
		while (d){
			ll t = c / d;
			c -= t * d; swap(c,d);
			u -= t * v; swap(u,v);
		}
		val = val * u % MOD;
		if (val < 0) val += MOD;
		return *this;
	}
	mll_ &operator += (ll b) { return *this += mll_(b); }
	mll_ &operator -= (ll b) { return *this -= mll_(b); }
	mll_ &operator *= (ll b) { return *this *= mll_(b); }
	mll_ &operator /= (ll b) { return *this /= mll_(b); }
	bool operator == (const mll_ &b) const { return val == b.val; }
	bool operator != (const mll_ &b) const { return val != b.val; }
	bool operator == (ll b) const { return *this == mll_(b); }
	bool operator != (ll b) const { return *this != mll_(b); }
	friend bool operator == (ll a,const mll_ &b) { return mll_(a) == b.val; }
	friend bool operator != (ll a,const mll_ &b) { return mll_(a) != b.val; }
	friend ostream &operator << (ostream &os,const mll_ &a) { return os << a.val; }
	friend istream &operator >> (istream &is,mll_ &a) { return is >> a.val; }
	static mll_ Combination(ll a,ll b){
		chmin(b,a-b);
		if (b<0) return mll_(0);
		mll_ c = 1;
		rep(i,0,b-1) c *= a-i;
		rep(i,0,b-1) c /= i+1;
		return c;
	}
};
using mll = mll_<1000000006LL>;
using mllb = mll_<1000000007LL>;
using vmll    = std::vector<mll>;
using vvmll   = std::vector<vmll>;
using vvvmll  = std::vector<vvmll>;
using vvvvmll = std::vector<vvvmll>;


template<class T> inline T POW(T a,ll n){ T r=1; for (; n>0; n>>=1,a*=a){ if (n&1)r*=a; } return r; }
inline ll POW(int a,ll n){ return POW((ll)a,n); }

#if 0
#include <atcoder/all>
using namespace atcoder;
#endif

const int MOD = 1000000007;

// a^b
long long modpow(long long a, long long n, long long mod) {
	long long res = 1;
	while (n > 0) {
		if (n & 1) res = res * a % mod;
		a = a * a % mod;
		n >>= 1;
	}
	return res;
}

// a^-1
long long modinv(long long a, long long m) {
	long long b = m, u = 1, v = 0;
	while (b) {
		long long t = a / b;
		a -= t * b; swap(a, b);
		u -= t * v; swap(u, v);
	}
	u %= m;
	if (u < 0) u += m;
	return u;
}

const ll M=1000001;
map<long long, long long> apow;
void prep(long long a, int m){
	long long amari = a;
	for (long long r = 1; r < M; ++r) {
		if (!apow.count(amari)) apow[amari] = r;
		(amari *= a) %= m;
	}
}


// a^x ≡ b (mod. m) となる最小の正の整数 x を求める
long long modlog(long long a, long long b, int m) {
	a %= m, b %= m;

	// calc sqrt{M}
	long long lo = -1, hi = m;
	while (hi - lo > 1) {
		long long mid = (lo + hi) / 2;
		if (mid * mid >= m) hi = mid;
		else lo = mid;
	}
	long long sqrtM = hi;

	// {a^0, a^1, a^2, ..., a^sqrt(m)} 
#if 0
	map<long long, long long> apow;
	long long amari = a;
	for (long long r = 1; r < sqrtM; ++r) {
		if (!apow.count(amari)) apow[amari] = r;
		(amari *= a) %= m;
	}
#endif
	// check each A^p
	long long A = modpow(modinv(a, m), M, m);
	ll amari = b;
	for (long long q = 0; q < 1000; ++q) {
		if (amari == 1 && q > 0) return q * M;
		else if (apow.count(amari)) return q * M + apow[amari];
		(amari *= A) %= m;
	}

	// no solutions
	return -1;
}

void solve()
{
	//{
	//	rep(i,2,10000000-1){
	//		auto a=POW(mllb(i),2);
	//		if (a==1){
	//			continue;
	//		}
	//		a=POW(mllb(i),500000003);
	//		if (a==1){
	//			continue;
	//		}
	//		cout << i << '\n'; return;
	//	}
	//}

	ll X,K;  cin >> X >> K;
	if (X==0){
		cout << 0 << '\n';return;
	}
	//10^9+7の原始根 5
	ll x=modlog(5,X,MOD);
	mll xx=x;
	xx/=K;
	mllb ans=POW(mllb(5),xx.val);
	cout << ans << '\n';
}

int main(){
#if 0
	solve();
	//cin2solve();
	//generand();
#else
	ll t;  cin >> t;
	prep(5,MOD);
	rep(i, 0, t-1){
		solve();
		//cin2solve();
	}
#endif
	return 0;
}
0