結果

問題 No.1294 マウンテン数列
ユーザー Enjapma_kyopro
提出日時 2020-11-21 03:09:10
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 291 ms / 2,000 ms
コード長 3,769 bytes
コンパイル時間 1,625 ms
コンパイル使用メモリ 173,420 KB
実行使用メモリ 6,944 KB
最終ジャッジ日時 2024-07-23 14:21:43
合計ジャッジ時間 4,179 ms
ジャッジサーバーID
(参考情報)
judge5 / judge1
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ファイルパターン 結果
other AC * 17
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
using namespace std;
// using mint = long double;
// using mint = modint998244353;
// using mint = modint1000000007;
typedef long long ll;
typedef pair<ll, ll> P;
typedef pair<P, ll> T;
typedef pair<ll, vector<ll>> Pd;
const ll INF = 1e18;
const ll fact_table = 3200008;
priority_queue <ll> pql;
priority_queue <P> pqp;
//big priority queue
priority_queue <ll, vector<ll>, greater<ll> > pqls;
priority_queue <P, vector<P>, greater<P> > pqps;
//small priority queue
//top pop
ll dx[8] = {1, 0, -1, 0, 1, 1, -1, -1};
ll dy[8] = {0, 1, 0, -1, -1, 1, 1, -1};
//↓,→,↑,←
/*
#define endl "\n"
#ifdef ENJAPMA
#undef endl
#endif
*/
#define p(x) cout<<x<<endl;
#define el cout<<endl;
#define pe(x) cout<<x<<" ";
#define ps(x) cout<<fixed<<setprecision(25)<<x<<endl;
#define pu(x) cout<<(x);
#define pb push_back
#define lb lower_bound
#define ub upper_bound
#define pc(x) cout << x << ",";
#define rep(i, n) for (ll i = 0; i < (n); i ++)
#define rep2(i, a, b) for (ll i = a; i <= (b); i++)
#define rep3(i, a, b) for (ll i = a; i >= (b); i--)
typedef vector<ll> vec;
typedef vector<vector<ll>> mat;
const ll mod = 998244353ll;
// const ll mod = 1000000007ll;
ll mypow(ll a, ll b, ll m = mod) {ll x = 1; while (b) {while (!(b & 1)) {(a *= a) %= m; b >>= 1;}(x *= a) %= m; b--;} return x;}
vec readvec(ll read) { vec res(read); for (int i = 0; i < read; i++) { cin >> res[i]; } return res;}
void YES(bool cond) { if (cond) { p("YES");} else { p("NO");} return;}
void Yes(bool cond) { if (cond) { p("Yes");} else { p("No");} return;}
void line() { p("--------------------"); return;}
/*
ll fact[fact_table + 5], rfact[fact_table + 5];
void c3_init() {
fact[0] = rfact[0] = 1;
for (ll i = 1; i <= fact_table; i++) {
fact[i] = (fact[i - 1] * i) % mod;
}
rfact[fact_table] = mypow(fact[fact_table], mod - 2, mod);
for (ll i = fact_table; i >= 1; i--) {
rfact[i - 1] = rfact[i] * i;
rfact[i - 1] %= mod;
}
return;
}
ll c3(ll n, ll r) {
return (((fact[n] * rfact[r]) % mod ) * rfact[n - r]) % mod;
}
*/
bool icpc = false;
bool multicase = false;
ll n;
ll x[2505], xsum[2505];
ll dp[2505];
ll table[2505];
bool solve() {
cin >> n;
for (int i = 1; i <= n; i++) {
cin >> x[i];
}
reverse(x + 1, x + n + 1);
dp[2] = 1;
for (int d = 1; d <= 2500; d++) {
bool ok = true;
for (int i = 1; i < n; i++) {
if (x[i] - x[i + 1] > d) ok = false;
}
if (!ok) {
table[d] = 0;
continue;
}
for (int i = 0; i <= n; i++) {
dp[i] = xsum[i] = 0;
}
dp[2] = xsum[2] = 2;
for (int i = 3; i <= n; i++) {
ll ok = i, ng = 1;
while (ok - ng > 1) {
ll mid = (ok + ng) / 2;
if (abs(x[mid - 1] - x[i]) <= d) {
ok = mid;
} else {
ng = mid;
}
}
dp[i] = xsum[i - 1] + (mod - xsum[ok - 1]);
dp[i] %= mod;
xsum[i] = xsum[i - 1] + dp[i];
xsum[i] %= mod;
}
ll ans = xsum[n];
table[d] = ans;
}
ll ans = 0;
for (int i = 1; i <= 2500; i++) {
ll r = table[i] + mod - table[i - 1];
ans += (r * i) % mod;
ans %= mod;
}
p(ans);
return true;
}
int main() {
ios::sync_with_stdio(false);
cin.tie(nullptr);
if (icpc) {
while (solve());
return 0;
}
ll q, testcase = 1;
if (multicase) {
cin >> q;
} else {
q = 1;
}
while (q--) {
// pu("Case ");pu("#");pu(testcase);pu(": ");
solve();
testcase++;
}
// solve();
return 0;
}
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