結果

問題 No.176 2種類の切手
ユーザー hamray
提出日時 2020-11-22 17:53:13
言語 C++11（廃止可能性あり）
(gcc 13.3.0)
結果
AC  
実行時間 51 ms / 1,000 ms
コード長 5,493 bytes
コンパイル時間 1,512 ms
コンパイル使用メモリ 162,576 KB
実行使用メモリ 6,944 KB
最終ジャッジ日時 2024-07-23 16:40:01
合計ジャッジ時間 3,367 ms
ジャッジサーバーID
（参考情報） 		judge1 / judge3
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 29
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
//#include <atcoder/all>
//using namespace atcoder;
#pragma GCC target ("avx2")
#pragma GCC optimization ("O3")
#pragma GCC optimization ("unroll-loops")
const double pi = 3.141592653589793238462643383279;
using namespace std;
//typedef
//------------------------------------------
typedef vector<int> VI;
typedef vector<VI> VVI;
typedef vector<string> VS;
typedef pair<int, int> PII;
typedef pair<long long, long long> PLL;
typedef pair<int, PII> TIII;
typedef long long LL;
typedef unsigned long long ULL;
typedef vector<LL> VLL;
typedef vector<VLL> VVLL;
//container util
//------------------------------------------
#define ALL(a) (a).begin(), (a).endf()
#define RALL(a) (a).rbegin(), (a).rend()
#define PB push_back
#define MP make_pair
#define SZ(a) int((a).size())
#define SQ(a) ((a) * (a))
#define EACH(i, c) for (typeof((c).begin()) i = (c).begin(); i != (c).endf(); ++i)
#define EXIST(s, e) ((s).find(e) != (s).endf())
#define SORT(c) sort((c).begin(), (c).endf())
//repetition
//------------------------------------------
#define FOR(i, s, n) for (int i = s; i < (int)n; ++i)
#define REP(i, n) FOR(i, 0, n)
#define MOD 1000000007
#define rep(i, a, b) for (int i = a; i < (b); ++i)
#define trav(a, x) for (auto &a : x)
#define all(x) x.begin(), x.end()
typedef long long ll;
typedef pair<int, int> pii;
typedef vector<int> vi;
#define chmin(x, y) x = min(x, y)
#define chmax(x, y) x = max(x, y)
const double EPS = 1e-9, PI = acos(-1);
//ここから編集    
typedef string::const_iterator State;
template< int mod >
struct ModInt {
  int x;
  ModInt() : x(0) {}
  ModInt(int64_t y) : x(y >= 0 ? y % mod : (mod - (-y) % mod) % mod) {}
  ModInt &operator+=(const ModInt &p) {
    if((x += p.x) >= mod) x -= mod;
    return *this;
  }
  ModInt &operator-=(const ModInt &p) {
    if((x += mod - p.x) >= mod) x -= mod;
    return *this;
  }
  ModInt &operator*=(const ModInt &p) {
    x = (int) (1LL * x * p.x % mod);
    return *this;
  }
  ModInt &operator/=(const ModInt &p) {
    *this *= p.inverse();
    return *this;
  }
  ModInt operator-() const { return ModInt(-x); }
  ModInt operator+(const ModInt &p) const { return ModInt(*this) += p; }
  ModInt operator-(const ModInt &p) const { return ModInt(*this) -= p; }
  ModInt operator*(const ModInt &p) const { return ModInt(*this) *= p; }
  ModInt operator/(const ModInt &p) const { return ModInt(*this) /= p; }
  bool operator==(const ModInt &p) const { return x == p.x; }
  bool operator!=(const ModInt &p) const { return x != p.x; }
  ModInt inverse() const {
    int a = x, b = mod, u = 1, v = 0, t;
    while(b > 0) {
      t = a / b;
      swap(a -= t * b, b);
      swap(u -= t * v, v);
    }
    return ModInt(u);
  }
  ModInt pow(int64_t n) const {
    ModInt ret(1), mul(x);
    while(n > 0) {
      if(n & 1) ret *= mul;
      mul *= mul;
      n >>= 1;
    }
    return ret;
  }
  friend ostream &operator<<(ostream &os, const ModInt &p) {
    return os << p.x;
  }
  friend istream &operator>>(istream &is, ModInt &a) {
    int64_t t;
    is >> t;
    a = ModInt< mod >(t);
    return (is);
  }
  static int get_mod() { return mod; }
};
using modint = ModInt< 1000000007 >;
template< typename T >
struct Combination {
  vector< T > _fact, _rfact, _inv;
  Combination(int sz) : _fact(sz + 1), _rfact(sz + 1), _inv(sz + 1) {
    _fact[0] = _rfact[sz] = _inv[0] = 1;
    for(int i = 1; i <= sz; i++) _fact[i] = _fact[i - 1] * i;
    _rfact[sz] /= _fact[sz];
    for(int i = sz - 1; i >= 0; i--) _rfact[i] = _rfact[i + 1] * (i + 1);
    for(int i = 1; i <= sz; i++) _inv[i] = _rfact[i] * _fact[i - 1];
  }
  inline T fact(int k) const { return _fact[k]; }
  inline T rfact(int k) const { return _rfact[k]; }
  inline T inv(int k) const { return _inv[k]; }
  T P(int n, int r) const {
    if(r < 0 || n < r) return 0;
    return fact(n) * rfact(n - r);
  }
  T C(int p, int q) const {
    if(q < 0 || p < q) return 0;
    return fact(p) * rfact(q) * rfact(p - q);
  }
  T H(int n, int r) const {
    if(n < 0 || r < 0) return (0);
    return r == 0 ? 1 : C(n + r - 1, r);
  }
};
template<typename T = int> struct BIT{
  vector<T> node;
  int N;
  BIT(int n){
    N = n;
    node.resize(N+1);
  }
  void add(int i, T x){
    i++;
    while(i <= N){
      node[i] += x;
      i += (i & -i);
    }
  }
  T sum(int i){
    T res = 0;
    while(i > 0){
      res += node[i];
      i -= (i & -i);
    }
    return res;
  }
};
ll dp[410][50];
int main() {
    cin.tie(0);
    ios::sync_with_stdio(false);
    cout << fixed << setprecision(12);
    ll a, b, t; cin >> a >> b >> t;
    auto f = [&](int x){
 
      ll lb = -1, ub = 1e9;
      while(ub-lb>1){
        int mid = (lb+ub)/2;
        if(x*a + mid*b >= t){
          ub = mid;
        }else{
          lb = mid;
        }
      }
      return (x*a+ub*b-t);
    };
    ll low = 0;
    ll high = 1e9;
    int epoch = 500;
    while(epoch--){
      int c1 = (low * 2 + high) / 3;
      int c2 = (low + high * 2) / 3;
      if(f(c1) > f(c2)) low = c1;
      else high = c2;
    }
    
    ll ans = 0;
    ll mi = (1LL<<60);
    for(ll i=low-200000; i<low+200000; i++){
      if(i<0) continue;
      ll lb = -1, ub = 1e9;
      while(ub-lb>1){
        int mid = (lb+ub)/2;
        if(i*a + mid*b >= t){
          ub = mid;
        }else{
          lb = mid;
        }
      }
      if(mi > i*a + ub*b - t){
        mi = i*a+ub*b-t;
        ans = i*a+ub*b;
      }
    }
    cout << ans << endl;
    return 0; 
}
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