結果
問題 | No.1561 connect x connect |
ユーザー | shinchan |
提出日時 | 2020-11-23 11:34:05 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 6,734 bytes |
コンパイル時間 | 3,614 ms |
コンパイル使用メモリ | 258,224 KB |
実行使用メモリ | 27,420 KB |
最終ジャッジ日時 | 2024-06-25 07:53:05 |
合計ジャッジ時間 | 7,997 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge5 |
(要ログイン)
テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
13,880 KB |
testcase_01 | WA | - |
testcase_02 | WA | - |
testcase_03 | AC | 2 ms
6,944 KB |
testcase_04 | WA | - |
testcase_05 | WA | - |
testcase_06 | AC | 2 ms
6,944 KB |
testcase_07 | WA | - |
testcase_08 | WA | - |
testcase_09 | WA | - |
testcase_10 | WA | - |
testcase_11 | WA | - |
testcase_12 | WA | - |
testcase_13 | WA | - |
testcase_14 | WA | - |
testcase_15 | WA | - |
testcase_16 | TLE | - |
testcase_17 | -- | - |
testcase_18 | -- | - |
testcase_19 | -- | - |
testcase_20 | -- | - |
testcase_21 | -- | - |
testcase_22 | -- | - |
testcase_23 | -- | - |
testcase_24 | -- | - |
testcase_25 | -- | - |
testcase_26 | -- | - |
testcase_27 | -- | - |
testcase_28 | -- | - |
testcase_29 | -- | - |
testcase_30 | -- | - |
testcase_31 | -- | - |
testcase_32 | -- | - |
testcase_33 | -- | - |
testcase_34 | -- | - |
testcase_35 | -- | - |
testcase_36 | -- | - |
testcase_37 | -- | - |
ソースコード
#include <bits/stdc++.h> #define be(v) (v).begin(),(v).end() #define pb(q) push_back(q) typedef long long ll; using namespace std; const ll mod=1000000007, INF=(1LL<<60); #define doublecout(a) cout<<fixed<<setprecision(10)<<a<<endl; #define rep(i,n) for (int i = 0; i < (n); ++i) #define repp(i,n,m) for (int i = m; i < (n); ++i) struct mint { ll x; // typedef long long ll; mint(ll x=0):x((x%mod+mod)%mod){} mint operator-() const { return mint(-x);} mint& operator+=(const mint a) { if ((x += a.x) >= mod) x -= mod; return *this; } mint& operator-=(const mint a) { if ((x += mod-a.x) >= mod) x -= mod; return *this; } mint& operator*=(const mint a) { (x *= a.x) %= mod; return *this;} mint operator+(const mint a) const { return mint(*this) += a;} mint operator-(const mint a) const { return mint(*this) -= a;} mint operator*(const mint a) const { return mint(*this) *= a;} mint pow(ll t) const { if (!t) return 1; mint a = pow(t>>1); a *= a; if (t&1) a *= *this; return a; } // for prime mod mint inv() const { return pow(mod-2);} mint& operator/=(const mint a) { return *this *= a.inv();} mint operator/(const mint a) const { return mint(*this) /= a;} }; struct UnionFind { vector<int> d; UnionFind(int n=0): d(n,-1) {} int find(int x) { if (d[x] < 0) return x; return d[x] = find(d[x]); } bool unite(int x, int y) { x = find(x); y = find(y); if (x == y) return false; if (d[x] > d[y]) swap(x,y); d[x] += d[y]; d[y] = x; return true; } bool same(int x, int y) { return find(x) == find(y);} int size(int x) { return -d[find(x)];} }; int count(vector<int> v){ v.pb(0); int ret = 0; bool f = false; for(int i : v){ if(i) f = true; else if(f) ret++, f = false; } return ret; } vector<int> paint(vector<int> &a, vector<int> &b){ int id = 0, n = a.size(); vector<int> ret(n, 0); bool f = false; for(int i=0;i<n;i++){ if(a[i]) ret[i] = b[id], f = true; else if(f) id++, f = false; } return ret; } //aとbを接続したときの新たな右端の色 vector<int> iro(vector<int> &a, vector<int> &b){ int n = a.size(); vector<int> ans(n,0); int ma = 0; rep(i,n) ma = max(ma,a[i]); vector<vector<int>> ar(ma,vector<int>(0)); vector<bool> ok(ma,false); rep(i,n){ if (a[i] != 0){ if (b[i] == 1) ok[a[i]-1] = true; ar[a[i]-1].emplace_back(i); } } rep(i,ma) if (!ok[i]) return ans; UnionFind tree(n); repp(i,n,1){ if (b[i-1] == 1 && b[i] == 1) tree.unite(i-1,i); } rep(i,ma){ auto &r = ar[i]; repp(j,r.size(),1) tree.unite(r[0],r[j]); } int ima = 1; map<int,int> mp; rep(i,n){ if (b[i] == 0) ans[i] = 0; else { int ne = tree.find(i); if (mp.find(ne) == mp.end()){ mp[ne] = ima; ans[i] = ima; ima++; } else { ans[i] = mp[ne]; } } } return ans; } struct dat{ set<int> s; stack<int> st; vector<int> an; set<int> stin; int ima; }; vector<vector<int>> komo(int n){ vector<vector<int>> ans(0,vector<int>(n)); queue<dat> que; dat a; a.ima = 2; a.s.insert(1); que.push(a); while (!que.empty()){ dat q = que.front(); que.pop(); if (q.an.size() == n){ ans.emplace_back(q.an); continue; } for (auto itr = q.s.begin(); itr != q.s.end(); itr++){ dat p = q; int m = *itr; if (p.stin.find(m) == p.stin.end()){ p.an.emplace_back(m); p.stin.insert(m); p.st.push(m); if (m == p.ima -1){ p.s.insert(p.ima); p.ima++; } } else { p.an.emplace_back(m); int col = p.st.top(); while (col != m){ p.s.erase(col); p.st.pop(); col = p.st.top(); } } que.push(p); } } return ans; } //S_(m,1) としてありえるか bool chan(vector<int> &a){ int ma = 0; vector<int> si = a; rep(i,a.size()) { ma = max(ma,a[i]); if (a[i] == 0) si[i] = 0; else si[i] = 1; } return ma == count(si); } vector<ll> next(vector<vector<ll>> &mat, vector<ll> &ima){ int n = ima.size(); vector<ll> ret(n, 0LL); rep(i, n) rep(j, n) (ret[i] += mat[i][j] & ima[j]) %= mod; return ret; } vector<ll> mnpoly(vector<vector<ll>> &mnp, vector<int> &truepoly){ vector<ll> ans(mnp.size(),0LL); rep(i,mnp.size()){ rep(j,truepoly.size()){ ans[i] += mnp[i][truepoly[j]]; } } return ans; } int main() { int m; cin >> m; int n; cin >> n; int ni = 1<<m; vector<vector<int>> ar(1<<m,vector<int>(m)); repp(i,1<<m,1){ rep(j,m){ if (i >> j & 1) ar[i][j] = 1; else ar[i][j] = 0; } } vector<vector<vector<int>>> col((m+3)/2,vector<vector<int>>(0,vector<int>(0))); repp(i,(m+3)/2,1){ col[i] = komo(i); } vector<vector<int>> ans; rep(i,ar.size()){ int a = count(ar[i]); rep(j,col[a].size()){ auto b = ar[i]; ans.emplace_back(paint(b,col[a][j])); } } //the number of recurrence formulas int zen = ans.size(); map<vector<int>,int> mp; rep(i,zen){ mp[ans[i]] = i; } //recurrence matrix vector<vector<ll> > mat(zen,vector<ll> (zen,0LL)); vector<int> tan(m, 0); rep(i,zen){ repp(j,ni,1){ auto x = iro(ans[i],ar[j]); if (x == tan) continue; int ind = mp[x]; mat[ind][i] += 1LL; } } vector<vector<ll>> mnp(1,vector<ll>(zen)); rep(i,zen){ if (chan(ans[i])) mnp[0][i] = 1LL; else mnp[0][i] = 0LL; } rep(i,n){ auto a = mnp[i]; auto b = next(mat, a); mnp.emplace_back(b); } //連結なpolyominoのindex vector<int> truepoly; rep(i,zen){ bool t = true; rep(j,m){ if (ans[i][j] > 1) t = false; } if (t) truepoly.emplace_back(i); } auto kai = mnpoly(mnp,truepoly); ll polysum = 0LL; rep(i,n) { polysum += ll(n-i) * kai[i]; polysum %= mod; } cout << polysum << endl; }