結果

問題 No.1115 二つの数列 / Two Sequences
ユーザー Coki628
提出日時 2020-11-24 19:14:19
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 162 ms / 2,000 ms
コード長 1,900 bytes
コンパイル時間 143 ms
コンパイル使用メモリ 82,608 KB
実行使用メモリ 108,416 KB
最終ジャッジ日時 2024-07-23 18:46:24
合計ジャッジ時間 5,094 ms
ジャッジサーバーID
(参考情報)
judge5 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 5
other AC * 35
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

import sys
def input(): return sys.stdin.readline().strip()
def list2d(a, b, c): return [[c] * b for i in range(a)]
def list3d(a, b, c, d): return [[[d] * c for k in range(b)] for i in range(a)]
def list4d(a, b, c, d, e): return [[[[e] * d for k in range(c)] for k in range(b)] for i in range(a)]
def ceil(x, y=1): return int(-(-x // y))
def INT(): return int(input())
def MAP(): return map(int, input().split())
def LIST(N=None): return list(MAP()) if N is None else [INT() for i in range(N)]
def Yes(): print('Yes')
def No(): print('No')
def YES(): print('YES')
def NO(): print('NO')
sys.setrecursionlimit(10**9)
INF = 10**19
MOD = 10**9 + 7
EPS = 10**-10
class BIT:
""" Binary Indexed Tree """
def __init__(self, n):
self.n = n
# 0-indexed
n += 1
nv = 1
while nv < n:
nv *= 2
self.size = nv
self.tree = [0] * nv
def sum(self, i):
""" [0, i] """
s = 0
i += 1
while i > 0:
s += self.tree[i-1]
i -= i & -i
return s
def add(self, i, x):
""" i, x """
i += 1
while i <= self.size:
self.tree[i-1] += x
i += i & -i
def query(self, l, r):
""" [l, r) """
return self.sum(r-1) - self.sum(l-1)
def get(self, i):
""" """
return self.query(i, i+1)
def update(self, i, x):
""" i, x """
self.add(i, x - self.get(i))
def print(self):
for i in range(self.n):
print(self.get(i), end=' ')
print()
N = INT()
A = [a-1 for a in LIST()]
B = [b-1 for b in LIST()]
D = {}
for i, a in enumerate(A):
D[a] = i
bit = BIT(N)
ans = 0
for i in range(N-1, -1, -1):
ans += bit.sum(D[B[i]])
bit.add(D[B[i]], 1)
print(ans)
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