結果

問題 No.1045 直方体大学
ユーザー kissshot7kissshot7
提出日時 2020-11-27 19:41:02
言語 C++14
(gcc 12.3.0 + boost 1.83.0)
結果
AC  
実行時間 438 ms / 2,000 ms
コード長 3,577 bytes
コンパイル時間 1,681 ms
コンパイル使用メモリ 173,000 KB
実行使用メモリ 35,296 KB
最終ジャッジ日時 2023-10-01 04:19:43
合計ジャッジ時間 3,355 ms
ジャッジサーバーID
(参考情報)
judge11 / judge14
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 11 ms
35,136 KB
testcase_01 AC 11 ms
35,056 KB
testcase_02 AC 11 ms
35,076 KB
testcase_03 AC 11 ms
35,080 KB
testcase_04 AC 11 ms
35,112 KB
testcase_05 AC 11 ms
35,136 KB
testcase_06 AC 12 ms
35,128 KB
testcase_07 AC 11 ms
35,040 KB
testcase_08 AC 24 ms
35,176 KB
testcase_09 AC 20 ms
35,120 KB
testcase_10 AC 15 ms
35,056 KB
testcase_11 AC 19 ms
35,096 KB
testcase_12 AC 24 ms
35,092 KB
testcase_13 AC 45 ms
35,248 KB
testcase_14 AC 24 ms
35,060 KB
testcase_15 AC 41 ms
35,052 KB
testcase_16 AC 43 ms
35,092 KB
testcase_17 AC 11 ms
35,124 KB
testcase_18 AC 438 ms
35,296 KB
権限があれば一括ダウンロードができます

ソースコード

diff #

#include <bits/stdc++.h>
using namespace std;

//#define int long long
typedef long long ll;

typedef unsigned long long ul;
typedef unsigned int ui;
const ll mod = 1000000007;
// const ll mod = 998244353;
const ll INF = mod * mod;
const int INF_N = 1e+9;
typedef pair<int, int> P;
#define rep(i,n) for(int i=0;i<n;i++)
#define per(i,n) for(int i=n-1;i>=0;i--)
#define Rep(i,sta,n) for(int i=sta;i<n;i++)
#define rep1(i,n) for(int i=1;i<=n;i++)
#define per1(i,n) for(int i=n;i>=1;i--)
#define Rep1(i,sta,n) for(int i=sta;i<=n;i++)
#define all(v) (v).begin(),(v).end()
typedef pair<ll, ll> LP;
typedef long double ld;
typedef pair<ld, ld> LDP;
const ld eps = 1e-12;
const ld pi = acos(-1.0);
//typedef vector<vector<ll>> mat;
typedef vector<int> vec;

//繰り返し二乗法
ll mod_pow(ll a, ll n, ll m) {
	ll res = 1;
	while (n) {
		if (n & 1)res = res * a%m;
		a = a * a%m; n >>= 1;
	}
	return res;
}

struct modint {
	ll n;
	modint() :n(0) { ; }
	modint(ll m) :n(m) {
		if (n >= mod)n %= mod;
		else if (n < 0)n = (n%mod + mod) % mod;
	}
	operator int() { return n; }
};
bool operator==(modint a, modint b) { return a.n == b.n; }
modint operator+=(modint &a, modint b) { a.n += b.n; if (a.n >= mod)a.n -= mod; return a; }
modint operator-=(modint &a, modint b) { a.n -= b.n; if (a.n < 0)a.n += mod; return a; }
modint operator*=(modint &a, modint b) { a.n = ((ll)a.n*b.n) % mod; return a; }
modint operator+(modint a, modint b) { return a += b; }
modint operator-(modint a, modint b) { return a -= b; }
modint operator*(modint a, modint b) { return a *= b; }
modint operator^(modint a, int n) {
	if (n == 0)return modint(1);
	modint res = (a*a) ^ (n / 2);
	if (n % 2)res = res * a;
	return res;
}

//逆元(Eucledean algorithm)
ll inv(ll a, ll p) {
	return (a == 1 ? 1 : (1 - p * inv(p%a, a)) / a + p);
}
modint operator/(modint a, modint b) { return a * modint(inv(b, mod)); }

const int max_n = 1 << 18;
modint fact[max_n], factinv[max_n];
void init_f() {
	fact[0] = modint(1);
	for (int i = 0; i < max_n - 1; i++) {
		fact[i + 1] = fact[i] * modint(i + 1);
	}
	factinv[max_n - 1] = modint(1) / fact[max_n - 1];
	for (int i = max_n - 2; i >= 0; i--) {
		factinv[i] = factinv[i + 1] * modint(i + 1);
	}
}
modint comb(int a, int b) {
	if (a < 0 || b < 0 || a < b)return 0;
	return fact[a] * factinv[b] * factinv[a - b];
}
using mP = pair<modint, modint>;

int dx[4] = { 0,1,0,-1 };
int dy[4] = { 1,0,-1,0 };


int n;
struct Box{
    ll a, b, h;
    Box(ll _a, ll _b, ll _h) : a(_a), b(_b), h(_h) {};
};
struct Bs{
    ll a, b, c;
	vector<Box> s;
	Bs(ll _a, ll _b, ll _c) :a(_a), b(_b), c(_c) {
		s.emplace_back(min(a, b), max(a, b), c);
		s.emplace_back(min(b, c), max(b, c), a);
		s.emplace_back(min(c, a), max(c, a), b);
	}
};
bool check(Box x, Box y){
	return x.a >= y.a && x.b >= y.b;
}
ll dp[(1<<16)+5][18][3];
vector<Bs> vr;
ll dfs(ll S, int pre, int bt){
	if(pre != -1 && dp[S][pre][bt] != -1) return dp[S][pre][bt];
	if(S == (1<<n) - 1) return 0;
	ll res = 0;
	rep(i, n){
		if(!(S>>i & 1)){
			rep(j, 3){
				if(pre == -1 || check(vr[pre].s[bt], vr[i].s[j])){
					res = max(res, dfs((S | (1 << i)), i, j) + vr[i].s[j].h);
				}
			}
		}
	}
	if(pre != -1) dp[S][pre][bt] = res;
	return res;
}

void solve() {
    cin >> n;
	memset(dp, -1, sizeof(dp));
	rep(i, n){
		ll a, b, c; cin >> a >> b >> c;
		vr.emplace_back(a, b, c);
	}
	cout << dfs(0, -1, 0) << endl;
}

signed main() {
  ios::sync_with_stdio(false);
  cin.tie(0);
  //cout << fixed << setprecision(10);
  //init_f();
  //init();
  //int t; cin >> t; rep(i, t)solve();
  solve();
//   stop
    return 0;
}
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