結果

問題 No.1301 Strange Graph Shortest Path
ユーザー ygussanyygussany
提出日時 2020-11-27 21:53:16
言語 C
(gcc 12.3.0)
結果
WA  
実行時間 -
コード長 2,629 bytes
コンパイル時間 1,755 ms
コンパイル使用メモリ 31,232 KB
実行使用メモリ 18,204 KB
最終ジャッジ日時 2024-09-13 00:54:39
合計ジャッジ時間 10,832 ms
ジャッジサーバーID
(参考情報)
judge3 / judge4
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 3 ms
8,796 KB
testcase_01 AC 2 ms
8,568 KB
testcase_02 WA -
testcase_03 WA -
testcase_04 WA -
testcase_05 AC 115 ms
15,876 KB
testcase_06 WA -
testcase_07 WA -
testcase_08 WA -
testcase_09 WA -
testcase_10 WA -
testcase_11 WA -
testcase_12 AC 359 ms
17,468 KB
testcase_13 WA -
testcase_14 WA -
testcase_15 WA -
testcase_16 WA -
testcase_17 WA -
testcase_18 WA -
testcase_19 WA -
testcase_20 WA -
testcase_21 WA -
testcase_22 WA -
testcase_23 WA -
testcase_24 WA -
testcase_25 WA -
testcase_26 WA -
testcase_27 WA -
testcase_28 WA -
testcase_29 WA -
testcase_30 WA -
testcase_31 WA -
testcase_32 WA -
testcase_33 WA -
testcase_34 AC 104 ms
17,764 KB
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ソースコード

diff #

#include <stdio.h>

typedef struct {
	int key, id;
} data;
 
typedef struct {
	data obj[400001];
	int size;
} min_heap;

void push(data x, min_heap* h)
{
	int i = ++(h->size), j = i >> 1;
	data tmp;
	h->obj[i] = x;
	while (j > 0) {
		if (h->obj[i].key < h->obj[j].key) {
			tmp = h->obj[j];
			h->obj[j] = h->obj[i];
			h->obj[i] = tmp;
			i = j;
			j >>= 1;
		} else break;
	}
}

data pop(min_heap* h)
{
	int i = 1, j = 2;
	data output = h->obj[1], tmp;
	h->obj[1] = h->obj[(h->size)--];
	while (j <= h->size) {
		if (j < h->size && h->obj[j^1].key < h->obj[j].key) j ^= 1;
		if (h->obj[j].key < h->obj[i].key) {
			tmp = h->obj[j];
			h->obj[j] = h->obj[i];
			h->obj[i] = tmp;
			i = j;
			j = i << 1;
		} else break;
	}
	return output;
}

typedef struct List {
	struct List *next;
	int v, id;
	long long cost;
} list;

int main()
{
	int i, N, M, u, w, c, d;
	list *adj[100001] = {}, e[400001], *p;
	scanf("%d %d", &N, &M);
	for (i = 0; i < M; i++) {
		scanf("%d %d %d %d", &u, &w, &c, &d);
		e[i*4].v = w;
		e[i*4+1].v = u;
		e[i*4+2].v = w;
		e[i*4+3].v = u;
		e[i*4].cost = c;
		e[i*4+1].cost = c;
		e[i*4+2].cost = d;
		e[i*4+3].cost = d;
		e[i*4].id = i * 4;
		e[i*4+1].id = i * 4 + 1;
		e[i*4+2].id = i * 4 + 2;
		e[i*4+3].id = i * 4 + 3;
		e[i*4].next = adj[u];
		e[i*4+1].next = adj[w];
		adj[u] = &(e[i*4]);
		adj[w] = &(e[i*4+1]);
		e[i*4+2].next = adj[u];
		e[i*4+3].next = adj[w];
		adj[u] = &(e[i*4+2]);
		adj[w] = &(e[i*4+3]);
	}
	
	int prev[2][100001], flag[2][100001] = {};
	long long dist[2][100001];
	for (i = 1; i <= N; i++) {
		dist[0][i] = 1LL << 60;
		dist[1][i] = 1LL << 60;
		prev[0][i] = -1;
		prev[1][i] = -1;
	}

	data da;
	min_heap h;
	h.size = 0;
	dist[0][1] = 0;
	da.key = 0;
	da.id = 1;
	push(da, &h);
	while (h.size > 0) {
		u = pop(&h).id;
		if (flag[0][u] != 0) continue;
		flag[0][u] = 0;
		for (p = adj[u]; p != NULL; p = p->next) {
			w = p->v;
			if (dist[0][u] + p->cost < dist[0][w]) {
				dist[0][w] = dist[0][u] + p->cost;
				prev[0][w] = p->id;
				da.key = dist[0][w];
				da.id = w;
				push(da, &h);
			}
		}
	}
	for (i = prev[0][N]; i != -1; i = prev[0][e[i^1].v]) {
		e[i].cost = 1LL << 60;
		e[i^1].cost = 1LL << 60;
	}
	dist[1][N] = 0;
	da.key = 0;
	da.id = N;
	push(da, &h);
	while (h.size > 0) {
		u = pop(&h).id;
		if (flag[1][u] != 0) continue;
		flag[1][u] = 1;
		for (p = adj[u]; p != NULL; p = p->next) {
			w = p->v;
			if (dist[1][u] + p->cost < dist[1][w]) {
				dist[1][w] = dist[1][u] + p->cost;
				prev[1][w] = p->id;
				da.key = dist[1][w];
				da.id = w;
				push(da, &h);
			}
		}
	}
	printf("%lld\n", dist[0][N] + dist[1][1]);
	fflush(stdout);
	return 0;
}
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