結果

問題 No.1310 量子アニーリング
ユーザー sapphire__15sapphire__15
提出日時 2020-12-07 17:09:38
言語 C++17
(gcc 12.3.0 + boost 1.83.0)
結果
AC  
実行時間 19 ms / 2,000 ms
コード長 5,301 bytes
コンパイル時間 1,214 ms
コンパイル使用メモリ 118,820 KB
実行使用メモリ 12,724 KB
最終ジャッジ日時 2023-10-17 16:32:58
合計ジャッジ時間 2,098 ms
ジャッジサーバーID
（参考情報） 		judge15 / judge12
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 10 ms
9,316 KB
testcase_01 AC 9 ms
9,316 KB
testcase_02 AC 9 ms
9,316 KB
testcase_03 AC 9 ms
9,316 KB
testcase_04 AC 9 ms
9,316 KB
testcase_05 AC 9 ms
9,316 KB
testcase_06 AC 8 ms
9,316 KB
testcase_07 AC 9 ms
9,316 KB
testcase_08 AC 9 ms
9,316 KB
testcase_09 AC 9 ms
9,316 KB
testcase_10 AC 9 ms
9,316 KB
testcase_11 AC 9 ms
9,316 KB
testcase_12 AC 10 ms
9,820 KB
testcase_13 AC 13 ms
10,348 KB
testcase_14 AC 14 ms
10,876 KB
testcase_15 AC 14 ms
11,140 KB
testcase_16 AC 14 ms
11,140 KB
testcase_17 AC 16 ms
11,932 KB
testcase_18 AC 19 ms
12,724 KB
testcase_19 AC 14 ms
10,876 KB
testcase_20 AC 11 ms
10,084 KB
testcase_21 AC 10 ms
10,084 KB
testcase_22 AC 19 ms
12,724 KB
testcase_23 AC 12 ms
10,612 KB
権限があれば一括ダウンロードができます

ソースコード

diff # 

#include <iostream>
#include <algorithm>
#include <map>
#include <set>
#include <queue>
#include <bitset>
#include <climits>
#include <cmath>
#include <bitset>
#include <complex>
#include <functional>
#include <cmath>
#include <cassert>
#include <stack>

typedef long long ll;
typedef std::pair<int, int> Pii;
typedef std::pair<long long, long long> Pll;
typedef std::pair<double, double> Pdd;

#define rip(i, n, ss) for (int i = (ss);i < (int)( n ); i++)
#define all(l) l.begin(), l.end()
#define MM << " " <<

template<typename T>
using MaxHeap = std::priority_queue<T>;
template<typename T>
using MinHeap = std::priority_queue<T, std::vector<T>, std::greater<T>>;

template<typename T>
inline bool chmax(T &l, const T b) {
    if (l < b) {
        l = b;
        return true;
    }
    return false;
}
template<typename T>
inline bool chmin(T &l, const T b) {
    if (l > b) {
        l = b;
        return true;
    }
    return false;
}

# ifdef LOCAL_DEBUG
template<typename T>
void vdeb(const std::vector<T> &bb) {
    for (unsigned int i = 0;i < bb.size();i++) {
        if (i == bb.size() - 1) std::cout << bb[i];
        else std::cout << bb[i] << ' ';
    }
    std::cout << '\n';
}
template<typename T>
void vdeb(const std::vector<std::vector<T>> &bb) {
    for (unsigned int i = 0;i < bb.size();i++) {
        std::cout << i << ' ';
        vdeb(bb[i]);
    }
    std::cout << '\n';
}
# endif

long long pow(long long n, long long p, long long k) {//n^k(mod p)
    if (!k) return 1;
    long long a = pow(n,p, k>>1);
    a = a * a%p;
    if (k & 1) a = a * n%p;
    return a;
}
void euclid(long long &a, long long &b, long long p) { // a>=b A*b+B*(a-a/b*b)=1
    if (a == 1) {
        a = 1;
    }
    else {
        long long A = b, B = a % b;
        euclid(A, B, p);
        b = (A - (p + a / b) % p * B % p + p) % p;
        a = B;
    }
}
long long rev(long long n, long long p) {// n*x-p*y=1
    //long long q = p;
    //euclid(p, n, p);
    //return n % q;
    return pow(n,p,p-2);
}
long long bino(long long n, long long m, long long p) {//nCm(mod p)
    long long ans = 1, div = 1;
    for(int i = 0;i < m; i++){
        ans = (n - i) * ans % p;
        div = div * (i +1) % p;
    }
    return ans * rev(div, p) % p;
}
struct modint {
    long long num;
    long long p;
    modint() {
        num = 0;
        p = 998244353;
    }
    modint(long long x) {
        p = 998244353;
        num = x % p;
    }
    modint inv()const{return rev(num, p);}
    modint operator-() const{return modint(p-num);}
    modint& operator+=(const modint &other){
        num = (num + other.num) % p;
        return *this;
    }
    modint& operator-=(const modint &other){
        num = (num - other.num + p) % p;
        return *this;
    }
    modint& operator*=(const modint &other){
        num = (num * other.num) % p;
        return *this;
    }
    modint& operator/=(const modint &other){
        (*this) *= other.inv();
        return *this;
    }
    modint& operator+=(const long long &other){
        num = (num + other) % p;
        return *this;
    }
    modint& operator-=(const long long &other){
        num = (num - other + p) % p;
        return *this;
    }
    modint& operator*=(const long long &other){
        num = (num * other) % p;
        return *this;
    }
    modint& operator/=(const long long &other){
        (*this) *= rev(other, p);
        return *this;
    }
    modint& operator++(){return *this += 1;}
    modint& operator--(){return *this -= 1;}
    modint& operator=(const long long &other){return (*this) = modint(other);}
    modint operator+(const modint &other) const{return modint(*this) += other;}
    modint operator-(const modint &other) const{return modint(*this) -= other;}
    modint operator*(const modint &other) const{return modint(*this) *= other;}
    modint operator/(const modint &other) const{return modint(*this) /= other;}
    modint operator+(const long long &other) const{return modint(*this) += other;}
    modint operator-(const long long &other) const{return modint(*this) -= other;}
    modint operator*(const long long &other) const{return modint(*this) *= other;}
    modint operator/(const long long &other) const{return modint(*this) /= other;}
    bool operator==(const modint &other) const{return num == other.num;}
};
std::istream& operator>>(std::istream &is, const modint x) {
    std::cin >> x.num;
    return is;
}
std::ostream& operator<<(std::ostream &os, const modint &x){
    std::cout << x.num;
    return os;
}

struct combination{
    std::vector<modint> li;
    std::vector<modint> rev;
    combination(int size){
        li = std::vector<modint>(size);
        rev = std::vector<modint>(size);
        li[0] = 1;
        for(int i= 1; i< size;i++) li[i] = li[i-1]*i;
        rev.back() = modint(1)/li.back();
        for(int i = size-1; i > 0; i--) rev[i-1] = rev[i]*i;
    }
    modint nCk(int n, int k){
        if(k <= 0 || n <= k) return 1;
        return li[n]*rev[k]*rev[n-k];
    }
} comb(202000);

using namespace std;

int main() {
    int n; cin >> n;
    vector<modint> da(n+1);
    da[0] += 1;
    rip(i,n,0) {
        da[i+1] = da[i] * 2;
    }
    modint ans;
    rip(i,n/2+1,0) {
        int j = n-i*2;
        ans += comb.nCk(n, j) * da[abs(i*2-j)] * 2;
    }
    cout << ans << endl;
}
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