結果
問題 | No.1311 Reverse Permutation Index |
ユーザー | ningenMe |
提出日時 | 2020-12-08 01:30:54 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 2 ms / 1,500 ms |
コード長 | 3,731 bytes |
コンパイル時間 | 2,159 ms |
コンパイル使用メモリ | 213,724 KB |
実行使用メモリ | 6,944 KB |
最終ジャッジ日時 | 2024-09-17 14:14:53 |
合計ジャッジ時間 | 2,591 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge6 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 1 ms
6,816 KB |
testcase_01 | AC | 1 ms
6,940 KB |
testcase_02 | AC | 1 ms
6,940 KB |
testcase_03 | AC | 1 ms
6,940 KB |
testcase_04 | AC | 1 ms
6,940 KB |
testcase_05 | AC | 1 ms
6,940 KB |
testcase_06 | AC | 2 ms
6,944 KB |
testcase_07 | AC | 1 ms
6,940 KB |
ソースコード
#include <bits/stdc++.h> using namespace std; using ll = long long; #define ALL(obj) (obj).begin(),(obj).end() template<class T> using priority_queue_reverse = priority_queue<T,vector<T>,greater<T>>; constexpr long long MOD = 1'000'000'000LL + 7; //' constexpr long long MOD2 = 998244353; constexpr long long HIGHINF = (long long)1e18; constexpr long long LOWINF = (long long)1e15; constexpr long double PI = 3.1415926535897932384626433L; template <class T> vector<T> multivector(size_t N,T init){return vector<T>(N,init);} template <class... T> auto multivector(size_t N,T... t){return vector<decltype(multivector(t...))>(N,multivector(t...));} template <class T> void corner(bool flg, T hoge) {if (flg) {cout << hoge << endl; exit(0);}} template <class T, class U>ostream &operator<<(ostream &o, const map<T, U>&obj) {o << "{"; for (auto &x : obj) o << " {" << x.first << " : " << x.second << "}" << ","; o << " }"; return o;} template <class T>ostream &operator<<(ostream &o, const set<T>&obj) {o << "{"; for (auto itr = obj.begin(); itr != obj.end(); ++itr) o << (itr != obj.begin() ? ", " : "") << *itr; o << "}"; return o;} template <class T>ostream &operator<<(ostream &o, const multiset<T>&obj) {o << "{"; for (auto itr = obj.begin(); itr != obj.end(); ++itr) o << (itr != obj.begin() ? ", " : "") << *itr; o << "}"; return o;} template <class T>ostream &operator<<(ostream &o, const vector<T>&obj) {o << "{"; for (int i = 0; i < (int)obj.size(); ++i)o << (i > 0 ? ", " : "") << obj[i]; o << "}"; return o;} template <class T, class U>ostream &operator<<(ostream &o, const pair<T, U>&obj) {o << "{" << obj.first << ", " << obj.second << "}"; return o;} void print(void) {cout << endl;} template <class Head> void print(Head&& head) {cout << head;print();} template <class Head, class... Tail> void print(Head&& head, Tail&&... tail) {cout << head << " ";print(forward<Tail>(tail)...);} template <class T> void chmax(T& a, const T b){a=max(a,b);} template <class T> void chmin(T& a, const T b){a=min(a,b);} vector<string> split(const string &str, const char delemiter) {vector<string> res;stringstream ss(str);string buffer; while( getline(ss, buffer, delemiter) ) res.push_back(buffer); return res;} int msb(int x) {return x?31-__builtin_clz(x):-1;} void YN(bool flg) {cout << (flg ? "YES" : "NO") << endl;} void Yn(bool flg) {cout << (flg ? "Yes" : "No") << endl;} void yn(bool flg) {cout << (flg ? "yes" : "no") << endl;} vector<int> NtoPermutation(int S,long long N) { vector<ll> c(S+1,1); for(ll i=1;i<=S;++i) c[i]=c[i-1]*i; vector<int> v; for(int i=1;i<=S;++i) v.push_back(i); vector<int> p; ll sum = 0; int n=S; while(p.size()<S) { --n; int m=0; for(int i=0;i<v.size();++i) { if(sum + i*c[n]<=N) m=i; } sum += m*c[n]; int x=v[m]; p.push_back(x); v.erase(find(v.begin(),v.end(),x)); } return p; } vector<int> invPermutation(vector<int> p) { vector<int> q(p.size()); for(int i=0;i<p.size();++i) { q[p[i]-1]=i+1; } return q; } long long PermutationtoN(vector<int> p) { int S = p.size(); vector<ll> c(S+1,1); for(ll i=1;i<=S;++i) c[i]=c[i-1]*i; vector<int> v; for(int i=1;i<=S;++i) v.push_back(i); long long sum=0; int n=S; for(int i=0;i<S;++i) { --n; int m=0; for(int j=0;j<v.size();++j)if(v[j]==p[i]) m=j; int x=v[m]; v.erase(find(v.begin(),v.end(),x)); sum += m*c[n]; } return sum; } /** * @url * @est */ int main() { cin.tie(0);ios::sync_with_stdio(false); ll N,S; cin >> N >> S; cout << PermutationtoN(invPermutation(NtoPermutation(S,N))) << endl; return 0; }