結果
| 問題 |
No.1283 Extra Fee
|
| コンテスト | |
| ユーザー |
Coki628
|
| 提出日時 | 2020-12-08 18:52:30 |
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 175 ms / 2,000 ms |
| コード長 | 4,500 bytes |
| コンパイル時間 | 3,024 ms |
| コンパイル使用メモリ | 215,940 KB |
| 最終ジャッジ日時 | 2025-01-16 19:48:13 |
|
ジャッジサーバーID (参考情報) |
judge3 / judge3 |
(要ログイン)
| ファイルパターン | 結果 |
|---|---|
| other | AC * 30 |
ソースコード
// #pragma GCC target("avx2")
// #pragma GCC optimize("O3")
// #pragma GCC optimize("unroll-loops")
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using ld = long double;
using pll = pair<ll, ll>;
using pii = pair<int, int>;
using vvl = vector<vector<ll>>;
using vvi = vector<vector<int>>;
using vvpll = vector<vector<pll>>;
#define rep(i, a, b) for (ll i=(a); i<(b); i++)
#define rrep(i, a, b) for (ll i=(a); i>(b); i--)
#define pb push_back
#define tostr to_string
#define ALL(A) A.begin(), A.end()
constexpr ll INF = LONG_LONG_MAX;
constexpr ll MOD = 1000000007;
template<typename T> vector<vector<T>> list2d(int N, int M, T init) { vector<vector<T>> res(N, vector<T>(M, init)); return res; }
template<typename T> vector<vector<vector<T>>> list3d(int N, int M, int L, T init) { vector<vector<vector<T>>> res(N, vector<vector<T>>(M, vector<T>(L, init))); return res; }
void print(ld out) { cout << fixed << setprecision(15) << out << '\n'; }
void print(double out) { cout << fixed << setprecision(15) << out << '\n'; }
template<typename T> void print(T out) { cout << out << '\n'; }
template<typename T1, typename T2> void print(pair<T1, T2> out) { cout << out.first << ' ' << out.second << '\n'; }
template<typename T> void print(vector<T> A) { rep(i, 0, A.size()) { cout << A[i]; cout << (i == A.size()-1 ? '\n' : ' '); } }
template<typename T> void print(set<T> S) { vector<T> A(S.begin(), S.end()); print(A); }
void Yes() { print("Yes"); }
void No() { print("No"); }
void YES() { print("YES"); }
void NO() { print("NO"); }
template<typename T> inline bool chmax(T &x, T y) { return (y > x) ? x = y, true : false; }
template<typename T> inline bool chmin(T &x, T y) { return (y < x) ? x = y, true : false; }
ll sum(vector<ll> A) { ll res = 0; for (ll a: A) res += a; return res; }
ll max(vector<ll> A) { ll res = -INF; for (ll a: A) chmax(res, a); return res; }
ll min(vector<ll> A) { ll res = INF; for (ll a: A) chmin(res, a); return res; }
ll toint(string s) { ll res = 0; for (char c : s) { res *= 10; res += (c - '0'); } return res; }
int toint(char num) { return num - '0'; }
char tochar(int num) { return '0' + num; }
inline ll pow(int x, ll n) { ll res = 1; rep(_, 0, n) res *= x; return res; }
inline ll pow(ll x, ll n, int mod) { ll res = 1; while (n > 0) { if (n & 1) { res = (res * x) % mod; } x = (x * x) % mod; n >>= 1; } return res; }
inline ll floor(ll a, ll b) { if (a < 0) { return (a-b+1) / b; } else { return a / b; } }
inline ll ceil(ll a, ll b) { if (a >= 0) { return (a+b-1) / b; } else { return a / b; } }
pll divmod(ll a, ll b) { ll d = a / b; ll m = a % b; return {d, m}; }
int popcount(ll S) { return __builtin_popcountll(S); }
ll gcd(ll a, ll b) { return __gcd(a, b); }
// グリッドダイクストラ(縦, 横, H*Wグリッド, 始点{h, w})
using P = tuple<ll, bool, int, int>;
vector<vector<vector<ll>>> dijkstra(vvl grid, pll src) {
int H = grid.size();
int W = grid[0].size();
auto res = list3d(2, H, W, INF);
auto [sh, sw] = src;
const vector<pii> directions = {{1, 0}, {-1, 0}, {0, 1}, {0, -1}};
priority_queue<P, vector<P>, greater<P>> que;
que.push({0, 0, sh, sw});
res[0][sh][sw] = 0;
while (!que.empty()) {
auto [dist, used, h, w] = que.top(); que.pop();
if (res[used][h][w] < dist) {
continue;
}
for (auto [dh, dw] : directions) {
int nh = h + dh;
int nw = w + dw;
if (grid[nh][nw] == -1) {
continue;
}
ll cost = grid[nh][nw];
if (dist + cost < res[used][nh][nw]) {
res[used][nh][nw] = dist + cost;
que.push({dist+cost, used, nh, nw});
}
if (cost > 1 and !used) {
cost = 1;
if (dist + cost < res[1][nh][nw]) {
res[1][nh][nw] = dist + cost;
que.push({dist+cost, 1, nh, nw});
}
}
}
}
return res;
}
int main() {
cin.tie(0);
ios::sync_with_stdio(false);
ll N, M;
cin >> N >> M;
auto grid = list2d(N+2, N+2, 1LL);
rep(i, 0, N+2) {
grid[i][0] = -1;
grid[i][N+1] = -1;
grid[0][i] = -1;
grid[N+1][i] = -1;
}
rep(i, 0, M) {
ll h, w, c;
cin >> h >> w >> c;
grid[h][w] += c;
}
auto res = dijkstra(grid, {1, 1});
ll ans = min(res[0][N][N], res[1][N][N]);
print(ans);
return 0;
}
Coki628