結果

問題 No.1318 ABCD quadruplets
ユーザー fuppy_kyopro
提出日時 2020-12-16 18:58:02
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 311 ms / 2,000 ms
コード長 4,942 bytes
コンパイル時間 2,636 ms
コンパイル使用メモリ 191,968 KB
実行使用メモリ 6,944 KB
最終ジャッジ日時 2024-09-20 05:15:37
合計ジャッジ時間 6,441 ms
ジャッジサーバーID
(参考情報)
judge2 / judge3
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 3
other AC * 30
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

//*
#pragma GCC target("avx2")
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
//*/
#include <bits/stdc++.h>
// #include <atcoder/all>
using namespace std;
// using namespace atcoder;
#define DEBUG(x) cerr<<#x<<": "<<x<<endl;
#define DEBUG_VEC(v) cerr<<#v<<":";for(int i=0;i<v.size();i++) cerr<<" "<<v[i]; cerr<<endl;
#define DEBUG_MAT(v) cerr<<#v<<endl;for(int i=0;i<v.size();i++){for(int j=0;j<v[i].size();j++) {cerr<<v[i][j]<<" ";}cerr<<endl;}
typedef long long ll;
// #define int ll
#define vi vector<int>
#define vl vector<ll>
#define vii vector< vector<int> >
#define vll vector< vector<ll> >
#define vs vector<string>
#define pii pair<int,int>
#define pis pair<int,string>
#define psi pair<string,int>
#define pll pair<ll,ll>
template<class S, class T> pair<S, T> operator+(const pair<S, T> &s, const pair<S, T> &t) { return pair<S, T>(s.first + t.first, s.second + t.second
    ); }
template<class S, class T> pair<S, T> operator-(const pair<S, T> &s, const pair<S, T> &t) { return pair<S, T>(s.first - t.first, s.second - t.second
    ); }
template<class S, class T> ostream& operator<<(ostream& os, pair<S, T> p) { os << "(" << p.first << ", " << p.second << ")"; return os; }
#define X first
#define Y second
#define rep(i,n) for(int i=0;i<(int)(n);i++)
#define rep1(i,n) for(int i=1;i<=(int)(n);i++)
#define rrep(i,n) for(int i=(int)(n)-1;i>=0;i--)
#define rrep1(i,n) for(int i=(int)(n);i>0;i--)
#define REP(i,a,b) for(int i=a;i<b;i++)
#define in(x, a, b) (a <= x && x < b)
#define all(c) c.begin(),c.end()
void YES(bool t=true) {cout<<(t?"YES":"NO")<<endl;}
void Yes(bool t=true) {cout<<(t?"Yes":"No")<<endl;}
void yes(bool t=true) {cout<<(t?"yes":"no")<<endl;}
void NO(bool t=true) {cout<<(t?"NO":"YES")<<endl;}
void No(bool t=true) {cout<<(t?"No":"Yes")<<endl;}
void no(bool t=true) {cout<<(t?"no":"yes")<<endl;}
template<class T> bool chmax(T &a, const T &b) { if (a<b) { a = b; return 1; } return 0; }
template<class T> bool chmin(T &a, const T &b) { if (a>b) { a = b; return 1; } return 0; }
#define UNIQUE(v) v.erase(std::unique(v.begin(), v.end()), v.end());
const ll inf = 1000000001;
const ll INF = (ll)1e18 + 1;
const long double pi = 3.1415926535897932384626433832795028841971L;
#define Sp(p) cout<<setprecision(25)<< fixed<<p<<endl;
// int dx[4] = {1, 0, -1, 0}, dy[4] = {0, 1, 0, -1};
// int dx2[8] = { 1,1,0,-1,-1,-1,0,1 }, dy2[8] = { 0,1,1,1,0,-1,-1,-1 };
vi dx = {0, 1, 0, -1}, dy = {-1, 0, 1, 0};
// vi dx2 = { 1,1,0,-1,-1,-1,0,1 }, dy2 = { 0,1,1,1,0,-1,-1,-1 };
#define fio() cin.tie(0); ios::sync_with_stdio(false);
// const ll MOD = 1000000007;
const ll MOD = 998244353;
// #define mp make_pair
//#define endl '\n'
int C[5][5];
signed main() {
fio();
C[0][0] = 1;
rep1 (i, 4) {
rep (j, i + 1) {
if (j == 0 or j == i) C[i][j] = 1;
else C[i][j] = C[i - 1][j - 1] + C[i - 1][j];
}
}
int n, m;
cin >> n >> m;
vl ans(n + 1);
unordered_map<int, int> mp;
int cnt = 0;
rep (a, m + 1) {
int now = a * a;
if (now > n) break;
int sum = a;
REP (b, a, m + 1) {
int now2 = now + b * b + sum * b;
if (now2 > n) break;
int sum2 = sum + b;
REP (c, b, m + 1) {
int now3 = now2 + c * c + sum2 * c;
if (now3 > n) break;
int sum3 = sum2 + c;
REP (d, c, m + 1) {
int now4 = now3 + d * d + sum3 * d;
if (now4 > n) break;
cnt++;
// mp.clear();
// mp[a]++;
// mp[b]++;
// mp[c]++;
// mp[d]++;
// int now = 4;
// ll add = 1;
// for (auto itr = mp.begin(); itr != mp.end(); itr++) {
// add *= C[now][itr->second];
// now -= itr->second;
// }
if (a == b) {
if (b == c) {
if (c == d) ans[now4]++;
else ans[now4] += 4;
}
else {
if (c == d) ans[now4] += 6;
else ans[now4] += 12;
}
}
else if (b == c) {
if (c == d) {
ans[now4] += 4;
}
else {
ans[now4] += 12;
}
}
else if (c == d) {
ans[now4] += 12;
}
else {
ans[now4] += 24;
}
}
}
}
}
rep (i, n + 1) {
cout << ans[i] << '\n';
}
}
הההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההה
XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX
0