結果
問題 | No.879 Range Mod 2 Query |
ユーザー | KodaiShinkawa |
提出日時 | 2020-12-17 22:39:20 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 262 ms / 3,000 ms |
コード長 | 6,795 bytes |
コンパイル時間 | 1,920 ms |
コンパイル使用メモリ | 177,872 KB |
実行使用メモリ | 11,712 KB |
最終ジャッジ日時 | 2024-09-21 08:26:08 |
合計ジャッジ時間 | 5,854 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge3 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
6,812 KB |
testcase_01 | AC | 2 ms
6,944 KB |
testcase_02 | AC | 3 ms
6,940 KB |
testcase_03 | AC | 3 ms
6,944 KB |
testcase_04 | AC | 3 ms
6,940 KB |
testcase_05 | AC | 3 ms
6,944 KB |
testcase_06 | AC | 2 ms
6,940 KB |
testcase_07 | AC | 3 ms
6,940 KB |
testcase_08 | AC | 3 ms
6,944 KB |
testcase_09 | AC | 2 ms
6,940 KB |
testcase_10 | AC | 2 ms
6,940 KB |
testcase_11 | AC | 243 ms
11,284 KB |
testcase_12 | AC | 150 ms
11,276 KB |
testcase_13 | AC | 186 ms
11,252 KB |
testcase_14 | AC | 176 ms
11,588 KB |
testcase_15 | AC | 173 ms
7,936 KB |
testcase_16 | AC | 234 ms
11,712 KB |
testcase_17 | AC | 244 ms
11,664 KB |
testcase_18 | AC | 254 ms
11,640 KB |
testcase_19 | AC | 245 ms
11,560 KB |
testcase_20 | AC | 240 ms
11,624 KB |
testcase_21 | AC | 262 ms
11,584 KB |
ソースコード
#ifndef ATCODER_LAZYSEGTREE_HPP #define ATCODER_LAZYSEGTREE_HPP 1 #include <algorithm> #include <cassert> #include <iostream> #include <vector> int ceil_pow2(int n) { int x = 0; while ((1U << x) < (unsigned int)(n)) x++; return x; } namespace atcoder { template <class S, S (*op)(S, S), S (*e)(), class F, S (*mapping)(F, S), F (*composition)(F, F), F (*id)()> struct lazy_segtree { public: lazy_segtree() : lazy_segtree(0) {} lazy_segtree(int n) : lazy_segtree(std::vector<S>(n, e())) {} lazy_segtree(const std::vector<S>& v) : _n(int(v.size())) { log = ceil_pow2(_n); size = 1 << log; d = std::vector<S>(2 * size, e()); lz = std::vector<F>(size, id()); for (int i = 0; i < _n; i++) d[size + i] = v[i]; for (int i = size - 1; i >= 1; i--) { update(i); } } void set(int p, S x) { assert(0 <= p && p < _n); p += size; for (int i = log; i >= 1; i--) push(p >> i); d[p] = x; for (int i = 1; i <= log; i++) update(p >> i); } S get(int p) { assert(0 <= p && p < _n); p += size; for (int i = log; i >= 1; i--) push(p >> i); return d[p]; } S prod(int l, int r) { assert(0 <= l && l <= r && r <= _n); if (l == r) return e(); l += size; r += size; for (int i = log; i >= 1; i--) { if (((l >> i) << i) != l) push(l >> i); if (((r >> i) << i) != r) push(r >> i); } S sml = e(), smr = e(); while (l < r) { if (l & 1) sml = op(sml, d[l++]); if (r & 1) smr = op(d[--r], smr); l >>= 1; r >>= 1; } return op(sml, smr); } S all_prod() { return d[1]; } void apply(int p, F f) { assert(0 <= p && p < _n); p += size; for (int i = log; i >= 1; i--) push(p >> i); d[p] = mapping(f, d[p]); for (int i = 1; i <= log; i++) update(p >> i); } void apply(int l, int r, F f) { assert(0 <= l && l <= r && r <= _n); if (l == r) return; l += size; r += size; for (int i = log; i >= 1; i--) { if (((l >> i) << i) != l) push(l >> i); if (((r >> i) << i) != r) push((r - 1) >> i); } { int l2 = l, r2 = r; while (l < r) { if (l & 1) all_apply(l++, f); if (r & 1) all_apply(--r, f); l >>= 1; r >>= 1; } l = l2; r = r2; } for (int i = 1; i <= log; i++) { if (((l >> i) << i) != l) update(l >> i); if (((r >> i) << i) != r) update((r - 1) >> i); } } template <bool (*g)(S)> int max_right(int l) { return max_right(l, [](S x) { return g(x); }); } template <class G> int max_right(int l, G g) { assert(0 <= l && l <= _n); assert(g(e())); if (l == _n) return _n; l += size; for (int i = log; i >= 1; i--) push(l >> i); S sm = e(); do { while (l % 2 == 0) l >>= 1; if (!g(op(sm, d[l]))) { while (l < size) { push(l); l = (2 * l); if (g(op(sm, d[l]))) { sm = op(sm, d[l]); l++; } } return l - size; } sm = op(sm, d[l]); l++; } while ((l & -l) != l); return _n; } template <bool (*g)(S)> int min_left(int r) { return min_left(r, [](S x) { return g(x); }); } template <class G> int min_left(int r, G g) { assert(0 <= r && r <= _n); assert(g(e())); if (r == 0) return 0; r += size; for (int i = log; i >= 1; i--) push((r - 1) >> i); S sm = e(); do { r--; while (r > 1 && (r % 2)) r >>= 1; if (!g(op(d[r], sm))) { while (r < size) { push(r); r = (2 * r + 1); if (g(op(d[r], sm))) { sm = op(d[r], sm); r--; } } return r + 1 - size; } sm = op(d[r], sm); } while ((r & -r) != r); return 0; } private: int _n, size, log; std::vector<S> d; std::vector<F> lz; void update(int k) { d[k] = op(d[2 * k], d[2 * k + 1]); } void all_apply(int k, F f) { d[k] = mapping(f, d[k]); if (k < size) lz[k] = composition(f, lz[k]); } void push(int k) { all_apply(2 * k, lz[k]); all_apply(2 * k + 1, lz[k]); lz[k] = id(); } }; } // namespace atcoder #endif // ATCODER_LAZYSEGTREE_HPP #include <bits/stdc++.h> using namespace std; using namespace atcoder; #define rep(i, n) for (int i = 0; i < (int)(n); i++) typedef long long ll; typedef pair<ll, ll> P; typedef vector<string> vs; typedef vector<double> vb; typedef vector<int> vi; typedef vector<ll> vl; typedef vector<P> vp; typedef vector<vi> vvi; typedef vector<vl> vvl; typedef vector<vp> vvp; // input int N, Q; vl A; void input() { cin >> N >> Q; A = vl(N); rep(i, N) cin >> A[i]; } struct S { ll v; int even, odd; }; S op(S l, S r) { return S{l.v + r.v, l.even + r.even, l.odd + r.odd}; } S e() { return S{0, 0, 0}; } struct F { bool flag, inv; ll d; }; S mapping(F f, S s) { S t = s; if (f.flag) { if (f.inv) swap(t.even, t.odd); t.v = t.odd; } t.v += f.d * (t.even + t.odd); if (f.d & 1) swap(t.even, t.odd); return t; } F composition(F f, F g) { F h; int c = 0; c += f.inv; c += g.inv; c += (g.d & 1) == 1; if (f.flag) h = F{true, (c & 1) == 1, 0}; else h = g; h.d += f.d; return h; } F id() { return F{false, false, 0}; } int main() { input(); vector<S> w(N); rep(i, N) { if (A[i] & 1) w[i] = S{A[i], 0, 1}; else w[i] = S{A[i], 1, 0}; } lazy_segtree<S, op, e, F, mapping, composition, id> seg(w); rep(i, Q) { int q; cin >> q; if (q == 1) { int l, r; cin >> l >> r; seg.apply(l - 1, r, F{true, false, 0}); } else if (q == 2) { int l, r, x; cin >> l >> r >> x; seg.apply(l - 1, r, F{false, false, x}); } else { int l, r; cin >> l >> r; ll ans = seg.prod(l - 1, r).v; cout << ans << endl; } } }