結果

問題 No.1193 Penguin Sequence
ユーザー saksak
提出日時 2021-01-06 03:40:02
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
WA  
実行時間 -
コード長 3,128 bytes
コンパイル時間 3,461 ms
コンパイル使用メモリ 206,424 KB
最終ジャッジ日時 2025-01-17 09:54:05
ジャッジサーバーID
(参考情報)
judge3 / judge4
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 19 WA * 19
権限があれば一括ダウンロードができます

ソースコード

diff #

#include <bits/stdc++.h>

using namespace std;
typedef long long ll;
typedef pair<ll, ll> p_ll;

template<class T>
void debug(T itr1, T itr2) { auto now = itr1; while(now<itr2) { cout << *now << " "; now++; } cout << endl; }
#define repr(i,from,to) for (ll i=(ll)from; i<(ll)to; i++)
#define all(vec) vec.begin(), vec.end()
#define rep(i,N) repr(i,0,N)
#define per(i,N) for (int i=(int)N-1; i>=0; i--)

const ll MOD = 998244353;
const ll LLINF = pow(2,61)-1;
const int INF = pow(2,30)-1;

vector<ll> fac;
void c_fac(int x=pow(10,6)+10) { fac.resize(x,true); rep(i,x) fac[i] = i ? (fac[i-1]*i)%MOD : 1; }
ll modpow(ll x, ll p) { ll result = 1, now = 1, pm = x; while (now<=p) { if (p&now) { result = result * pm % MOD; } now*=2; pm = pm*pm % MOD; } return result; }
ll inv(ll a, ll m=MOD) { ll b = m, x = 1, y = 0; while (b!=0) { int d = a/b; a -= b*d; swap(a,b); x -= y*d; swap(x,y); } return (x+m)%m; }
ll nck(ll n, ll k) { return k<0||k>n ? 0 : fac[n]*inv(fac[k]*fac[n-k]%MOD)%MOD; }
ll gcd(ll a, ll b) { if (a<b) swap(a,b); return b==0 ? a : gcd(b, a%b); }
ll lcm(ll a, ll b) { return a/gcd(a,b)*b; }

// ----------------------------------------------------------------------
// ----------------------------------------------------------------------

struct SegTree {
  ll size;
  vector<ll> pos;
  SegTree(ll N) { size = 1; while(size<N) size<<=1; pos.resize(2*size,0); }
  ll operator[](const ll &x) const { return pos[x+size]; }

  void set(ll x, const ll v) { pos[x+size] = v; }
  void update(ll x, const ll v) { set(x,v); x+=size; while (x>>=1) operate(x); }
  ll query(ll a, ll b) {
    ll L = 0, R = 0;
    for (a+=size, b+=size; a<b; a>>=1, b>>=1) {
      if (a&1) { L = q(L,pos[a]); a++; }
      if (b&1) { b--; R = q(pos[b],R); }
    }
    return q(L,R);
  }
  void operate(ll i) { pos[i] = q(pos[i*2], pos[i*2+1]); }
  ll q(ll x, ll y) { return x + y; }
};

// ----------------------------------------------------------------------
// ----------------------------------------------------------------------

vector<ll> zaatsu(vector<ll> &list) {
  map<ll, ll> num; for (auto x: list) num[x]++;
  ll p = 0; for (auto x: num) { num[x.first] = p; p++; }
  vector<ll> result; for (auto x: list) result.push_back(num[x]);
  return result;
}

// ----------------------------------------------------------------------
// ----------------------------------------------------------------------

int main() {
  ll N; cin >> N;
  vector<ll> A(N); rep(i,N) cin >> A[i];

  A = zaatsu(A);
  // debug(all(A));

  SegTree st(N);
  ll ten = 0; rep(i,N) { ten = (ten+st.query(A[i]+1,N)) % MOD; st.update(A[i],st[A[i]]+1); }
  ll later = 0; rep(i,N) later = (later+st[i]*st.query(i+1,N)) % MOD;
  // cout << ten << " " << later << endl;

  c_fac();
  ll allc = 1; rep(i,N) allc = allc * nck(N,i+1) % MOD;
  ll invn2 = modpow(inv(N),2);

  ll res1 = 0, res2 = 0;
  rep(i,N) {
    ll c1 = i+1, c2 = (i+2+N)*(N-(i+1))/2;
    res1 = (res1+allc*invn2%MOD*c1%MOD*c2%MOD*later%MOD) % MOD;
    res2 = (res2+allc*inv(nck(N,i+1))%MOD*nck(N-2,i-1)%MOD*ten%MOD) % MOD;
  }
  ll result = (res1+res2) % MOD;
  cout << result << endl;
  return 0;
}
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