結果
問題 | No.9 モンスターのレベル上げ |
ユーザー | La |
提出日時 | 2021-01-06 13:57:39 |
言語 | Ruby (3.3.0) |
結果 |
TLE
|
実行時間 | - |
コード長 | 2,574 bytes |
コンパイル時間 | 206 ms |
コンパイル使用メモリ | 7,552 KB |
実行使用メモリ | 13,632 KB |
最終ジャッジ日時 | 2024-11-06 23:35:27 |
合計ジャッジ時間 | 7,039 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge1 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 93 ms
12,416 KB |
testcase_01 | AC | 90 ms
12,416 KB |
testcase_02 | TLE | - |
testcase_03 | -- | - |
testcase_04 | -- | - |
testcase_05 | -- | - |
testcase_06 | -- | - |
testcase_07 | -- | - |
testcase_08 | -- | - |
testcase_09 | -- | - |
testcase_10 | -- | - |
testcase_11 | -- | - |
testcase_12 | -- | - |
testcase_13 | -- | - |
testcase_14 | -- | - |
testcase_15 | -- | - |
testcase_16 | -- | - |
testcase_17 | -- | - |
testcase_18 | -- | - |
testcase_19 | -- | - |
コンパイルメッセージ
Syntax OK
ソースコード
# Priority Queue # Reference: https://github.com/python/cpython/blob/master/Lib/heapq.py class PriorityQueue # By default, the priority queue returns the maximum element first. # If a block is given, the priority between the elements is determined with it. # For example, the following block is given, the priority queue returns the minimum element first. # `PriorityQueue.new { |x, y| x < y }` # # A heap is an array for which a[k] <= a[2*k+1] and a[k] <= a[2*k+2] for all k, counting elements from 0. def initialize(array = [], &comp) @heap = array @comp = comp || proc { |x, y| x > y } heapify end attr_reader :heap # Push new element to the heap. def push(item) shift_down(0, @heap.push(item).size - 1) end alias << push alias append push # Pop the element with the highest priority. def pop latest = @heap.pop return latest if empty? ret_item = heap[0] heap[0] = latest shift_up(0) ret_item end # Get the element with the highest priority. def get @heap[0] end alias top get # Returns true if the heap is empty. def empty? @heap.empty? end private def heapify (@heap.size / 2 - 1).downto(0) { |i| shift_up(i) } end def shift_up(pos) end_pos = @heap.size start_pos = pos new_item = @heap[pos] left_child_pos = 2 * pos + 1 while left_child_pos < end_pos right_child_pos = left_child_pos + 1 if right_child_pos < end_pos && @comp.call(@heap[right_child_pos], @heap[left_child_pos]) left_child_pos = right_child_pos end # Move the higher priority child up. @heap[pos] = @heap[left_child_pos] pos = left_child_pos left_child_pos = 2 * pos + 1 end @heap[pos] = new_item shift_down(start_pos, pos) end def shift_down(star_pos, pos) new_item = @heap[pos] while pos > star_pos parent_pos = (pos - 1) >> 1 parent = @heap[parent_pos] break if @comp.call(parent, new_item) @heap[pos] = parent pos = parent_pos end @heap[pos] = new_item end end N=gets.to_i A=gets.split.map(&:to_i) B=gets.split.map(&:to_i) MOD=2000 ans=1500 for i in 0...N do A[i]=-A[i]*MOD B[i]=B[i]/2*MOD end for i in 0...N do pq=PriorityQueue.new for j in 0...N do pq.push(A[j]) end for j in 0...N do l=pq.pop(); l-=B[(i+j)%N]+1 pq.push(l) end cnt=0 for j in 0...N do l=pq.pop(); cnt=-l%MOD if cnt<-l%MOD end ans=cnt if ans>cnt end puts ans