結果
問題 | No.1330 Multiply or Divide |
ユーザー |
![]() |
提出日時 | 2021-01-08 21:43:17 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
WA
(最新)
AC
(最初)
|
実行時間 | - |
コード長 | 1,655 bytes |
コンパイル時間 | 2,291 ms |
コンパイル使用メモリ | 191,900 KB |
最終ジャッジ日時 | 2025-01-17 11:36:05 |
ジャッジサーバーID (参考情報) |
judge4 / judge3 |
(要ログイン)
ファイルパターン | 結果 |
---|---|
other | AC * 45 WA * 1 |
コンパイルメッセージ
main.cpp: In function ‘int main()’: main.cpp:49:10: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result] 49 | scanf("%d%lld%lld", &n, &m, &p); | ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~ main.cpp:51:20: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result] 51 | rep(i, n) scanf("%lld", &a[i]); | ~~~~~^~~~~~~~~~~~~~~
ソースコード
#include <bits/stdc++.h>//#include <atcoder/all>#define For(i, a, b) for (int(i) = (int)(a); (i) < (int)(b); ++(i))#define rFor(i, a, b) for (int(i) = (int)(a)-1; (i) >= (int)(b); --(i))#define rep(i, n) For((i), 0, (n))#define rrep(i, n) rFor((i), (n), 0)#define fi first#define se secondusing namespace std;typedef long long lint;typedef unsigned long long ulint;typedef pair<int, int> pii;typedef pair<lint, lint> pll;template <class T>bool chmax(T &a, const T &b) {if (a < b) {a = b;return true;}return false;}template <class T>bool chmin(T &a, const T &b) {if (a > b) {a = b;return true;}return false;}template <class T>T div_floor(T a, T b) {if (b < 0) a *= -1, b *= -1;return a >= 0 ? a / b : (a + 1) / b - 1;}template <class T>T div_ceil(T a, T b) {if (b < 0) a *= -1, b *= -1;return a > 0 ? (a - 1) / b + 1 : a / b;}constexpr lint mod = 1000000007;constexpr lint INF = mod * mod;constexpr int MAX = 200010;int main() {int n;lint m, p;scanf("%d%lld%lld", &n, &m, &p);lint a[n];rep(i, n) scanf("%lld", &a[i]);lint b = *max_element(a, a + n);if (b > m) {printf("%d\n", 1);return 0;}int ans = -1;rep(i, n) {int cnt = 1;lint t = a[i];while (t % p == 0) {++cnt;t /= p;}if (t == 1) continue;int tmp = 1;lint x = 1;while (x * b <= m) {tmp += cnt;x *= t;}if (ans == -1 || ans > tmp) ans = tmp;}printf("%d\n", ans);}