結果
問題 | No.1332 Range Nearest Query |
ユーザー |
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提出日時 | 2021-01-08 21:47:43 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 550 ms / 2,500 ms |
コード長 | 3,174 bytes |
コンパイル時間 | 2,167 ms |
コンパイル使用メモリ | 200,824 KB |
最終ジャッジ日時 | 2025-01-17 11:38:21 |
ジャッジサーバーID (参考情報) |
judge2 / judge2 |
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ファイルパターン | 結果 |
---|---|
other | AC * 48 |
ソースコード
#include <bits/stdc++.h>using namespace std;using ll = long long;using pii = pair<int, int>;template <class T>using V = vector<T>;template <class T>using VV = V<V<T>>;#define pb push_back#define eb emplace_back#define mp make_pair#define fi first#define se second#define rep(i, n) rep2(i, 0, n)#define rep2(i, m, n) for (int i = m; i < (n); i++)#define per(i, b) per2(i, 0, b)#define per2(i, a, b) for (int i = int(b) - 1; i >= int(a); i--)#define ALL(c) (c).begin(), (c).end()#define SZ(x) ((int)(x).size())constexpr ll TEN(int n) { return (n == 0) ? 1 : 10 * TEN(n - 1); }template <class T, class U>void chmin(T& t, const U& u) {if (t > u) t = u;}template <class T, class U>void chmax(T& t, const U& u) {if (t < u) t = u;}template <class T, class U>ostream& operator<<(ostream& os, const pair<T, U>& p) {os << "(" << p.first << "," << p.second << ")";return os;}template <class T>ostream& operator<<(ostream& os, const vector<T>& v) {os << "{";rep(i, v.size()) {if (i) os << ",";os << v[i];}os << "}";return os;}#ifdef LOCALvoid debug_out() { cerr << endl; }template <typename Head, typename... Tail>void debug_out(Head H, Tail... T) {cerr << " " << H;debug_out(T...);}#define debug(...) \cerr << __LINE__ << " [" << #__VA_ARGS__ << "]:", debug_out(__VA_ARGS__)#define dump(x) cerr << __LINE__ << " " << #x << " = " << (x) << endl#else#define debug(...) (void(0))#define dump(x) (void(0))#endifconst int INF = TEN(9) + 10;const int sz = 1 << 20;struct segtree {using Val = int;vector<vector<Val>> dat;segtree() {}void init(vector<Val> num) {dat.resize(sz * 2);rep(i, sz * 2) { dat[i].clear(); }rep(i, num.size()) { dat[sz - 1 + i].pb(num[i]); }for (int i = sz - 2; i >= 0; --i) {int lc = i * 2 + 1, rc = i * 2 + 2;dat[i].resize(dat[lc].size() + dat[rc].size());merge(dat[lc].begin(), dat[lc].end(), dat[rc].begin(),dat[rc].end(), dat[i].begin());}}Val ask(int a, int b, int u, int k = 0, int l = 0, int r = sz) {if (b <= l || r <= a) return INF;if (a <= l && r <= b) {if (dat[k].size() == 0) return INF;int res = INF;if (u <= dat[k][0])res = dat[k][0] - u;else if (u >= dat[k].back())res = u - dat[k].back();else {auto it = lower_bound(ALL(dat[k]), u);res = min(abs((*it) - u), abs(*(prev(it)) - u));}return res;}return min(ask(a, b, u, k * 2 + 1, l, (l + r) / 2),ask(a, b, u, k * 2 + 2, (l + r) / 2, r));}} seg;int main() {cin.tie(nullptr);ios::sync_with_stdio(false);int N;cin >> N;V<int> X(N);rep(i, N) cin >> X[i];segtree seg;seg.init(X);int Q;cin >> Q;while (Q--) {int l, r, y;cin >> l >> r >> y;--l;int ans = INF;cout << seg.ask(l, r, y) << '\n';}return 0;}