結果
| 問題 | No.1332 Range Nearest Query |
| ユーザー |
 heno239
|
| 提出日時 | 2021-01-08 21:53:42 |
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 291 ms / 2,500 ms |
| コード長 | 5,223 bytes |
| コンパイル時間 | 2,337 ms |
| コンパイル使用メモリ | 164,448 KB |
| 最終ジャッジ日時 | 2025-01-17 11:51:12 |
|
ジャッジサーバーID （参考情報） |
judge2 / judge3 |
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| ファイルパターン | 結果 |
|---|---|
| other | AC * 48 |
ソースコード
#pragma GCC optimize("Ofast")//#pragma GCC target ("sse4")#include<iostream>#include<string>#include<cstdio>#include<vector>#include<cmath>#include<algorithm>#include<functional>#include<iomanip>#include<queue>#include<ciso646>#include<random>#include<map>#include<set>#include<bitset>#include<stack>#include<unordered_map>#include<unordered_set>#include<utility>#include<cassert>#include<complex>#include<numeric>#include<array>using namespace std;//#define int long longtypedef long long ll;typedef unsigned long long ul;typedef unsigned int ui;constexpr ll mod = 1000000007;const ll INF = mod * mod;typedef pair<int, int>P;#define stop char nyaa;cin>>nyaa;#define rep(i,n) for(int i=0;i<n;i++)#define per(i,n) for(int i=n-1;i>=0;i--)#define Rep(i,sta,n) for(int i=sta;i<n;i++)#define rep1(i,n) for(int i=1;i<=n;i++)#define per1(i,n) for(int i=n;i>=1;i--)#define Rep1(i,sta,n) for(int i=sta;i<=n;i++)#define all(v) (v).begin(),(v).end()typedef pair<ll, ll> LP;typedef double ld;typedef pair<ld, ld> LDP;const ld eps = 1e-12;const ld pi = acosl(-1.0);ll mod_pow(ll x, ll n, ll m = mod) {if (n < 0) {ll res = mod_pow(x, -n, m);return mod_pow(res, m - 2, m);}if (abs(x) >= m)x %= m;if (x < 0)x += m;ll res = 1;while (n) {if (n & 1)res = res * x % m;x = x * x % m; n >>= 1;}return res;}struct modint {ll n;modint() :n(0) { ; }modint(ll m) :n(m) {if (n >= mod)n %= mod;else if (n < 0)n = (n % mod + mod) % mod;}operator int() { return n; }};bool operator==(modint a, modint b) { return a.n == b.n; }modint operator+=(modint& a, modint b) { a.n += b.n; if (a.n >= mod)a.n -= mod; return a; }modint operator-=(modint& a, modint b) { a.n -= b.n; if (a.n < 0)a.n += mod; return a; }modint operator*=(modint& a, modint b) { a.n = ((ll)a.n * b.n) % mod; return a; }modint operator+(modint a, modint b) { return a += b; }modint operator-(modint a, modint b) { return a -= b; }modint operator*(modint a, modint b) { return a *= b; }modint operator^(modint a, ll n) {if (n == 0)return modint(1);modint res = (a * a) ^ (n / 2);if (n % 2)res = res * a;return res;}ll inv(ll a, ll p) {return (a == 1 ? 1 : (1 - p * inv(p % a, a)) / a + p);}modint operator/(modint a, modint b) { return a * modint(inv(b, mod)); }modint operator/=(modint& a, modint b) { a = a / b; return a; }const int max_n = 1 << 17;modint fact[max_n], factinv[max_n];void init_f() {fact[0] = modint(1);for (int i = 0; i < max_n - 1; i++) {fact[i + 1] = fact[i] * modint(i + 1);}factinv[max_n - 1] = modint(1) / fact[max_n - 1];for (int i = max_n - 2; i >= 0; i--) {factinv[i] = factinv[i + 1] * modint(i + 1);}}modint comb(int a, int b) {if (a < 0 || b < 0 || a < b)return 0;return fact[a] * factinv[b] * factinv[a - b];}modint combP(int a, int b) {if (a < 0 || b < 0 || a < b)return 0;return fact[a] * factinv[a - b];}template<typename T>struct SegT {private:int sz; vector<T> node;T init_c;function<T(T, T)> f;public:SegT(vector<T> v, T _init_c, function<T(T, T)> _f) {init_c = _init_c; f = _f;int n = v.size();sz = 1;while (sz < n)sz *= 2;node.resize(2 * sz - 1, init_c);rep(i, n) {node[i + sz - 1] = v[i];}per(i, sz - 1) {node[i] = f(node[2 * i + 1], node[2 * i + 2]);}}SegT(int n, T _init_c, function<T(T, T)> _f) {init_c = _init_c; f = _f;sz = 1;while (sz < n)sz *= 2;node.resize(2 * sz - 1, init_c);}void update(int k, T a) {k += sz - 1;node[k] = a;while (k > 0) {k = (k - 1) / 2;node[k] = f(node[k * 2 + 1], node[k * 2 + 2]);}}T query(int a, int b, int k = 0, int l = 0, int r = -1) {if (r < 0)r = sz;if (r <= a || b <= l)return init_c;else if (a <= l && r <= b)return node[k];else {T vl = query(a, b, k * 2 + 1, l, (l + r) / 2);T vr = query(a, b, k * 2 + 2, (l + r) / 2, r);return f(vl, vr);}}};void solve() {int n; cin >> n;vector<int> a(n); rep(i, n)cin >> a[i];int q; cin >> q;vector<int> l(q), r(q), x(q);rep(i, q) {cin >> l[i] >> r[i] >> x[i]; l[i]--; r[i]--;}vector<P> vs;rep(i, n)vs.push_back({ a[i],i });sort(all(vs));vector<P> qs;rep(i, q) {qs.push_back({ x[i],i });}sort(all(qs));int loc = 0;vector<int> ans(q, mod);auto ma = [&](int a, int b) {return max(a, b); };SegT<int> stma(n, -mod, ma);rep(i, qs.size()) {while (loc < n && vs[loc].first <= qs[i].first) {stma.update(vs[loc].second, vs[loc].first);loc++;}int id = qs[i].second;int val = stma.query(l[id], r[id] + 1);ans[id] = min(ans[id], x[id] - val);}auto mi = [&](int a, int b) {return min(a, b); };SegT<int> stmi(n, 2*mod, mi);reverse(all(vs));loc = 0;reverse(all(qs));rep(i, qs.size()) {while (loc < n && vs[loc].first >= qs[i].first) {stmi.update(vs[loc].second, vs[loc].first);loc++;}int id = qs[i].second;int val = stmi.query(l[id], r[id] + 1);ans[id] = min(ans[id], val - x[id]);}rep(i, q)cout << ans[i] << "\n";}signed main() {ios::sync_with_stdio(false);cin.tie(0);//cout << fixed << setprecision(15);//init_f();//init();//expr();//int t; cin >> t; rep(i, t)solve();return 0;}