結果
問題 | No.1331 Moving Penguin |
ユーザー |
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提出日時 | 2021-01-08 22:19:22 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 181 ms / 1,500 ms |
コード長 | 3,878 bytes |
コンパイル時間 | 2,025 ms |
コンパイル使用メモリ | 197,516 KB |
最終ジャッジ日時 | 2025-01-17 12:34:33 |
ジャッジサーバーID (参考情報) |
judge5 / judge3 |
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ファイルパターン | 結果 |
---|---|
other | AC * 49 |
コンパイルメッセージ
main.cpp: In function ‘int main()’: main.cpp:152:16: warning: format ‘%lld’ expects argument of type ‘long long int’, but argument 2 has type ‘modint<1000000007>::i64’ {aka ‘long int’} [-Wformat=] 152 | printf("%lld\n", dp[n].a); | ~~~^ ~~~~~~~ | | | | | modint<1000000007>::i64 {aka long int} | long long int | %ld main.cpp:129:10: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result] 129 | scanf("%d", &n); | ~~~~~^~~~~~~~~~ main.cpp:131:27: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result] 131 | For(i, 1, n + 1) scanf("%d", &a[i]); | ~~~~~^~~~~~~~~~~~~
ソースコード
#include <bits/stdc++.h>//#include <atcoder/all>#define For(i, a, b) for (int(i) = (int)(a); (i) < (int)(b); ++(i))#define rFor(i, a, b) for (int(i) = (int)(a)-1; (i) >= (int)(b); --(i))#define rep(i, n) For((i), 0, (n))#define rrep(i, n) rFor((i), (n), 0)#define fi first#define se secondusing namespace std;typedef long long lint;typedef unsigned long long ulint;typedef pair<int, int> pii;typedef pair<lint, lint> pll;template <class T>bool chmax(T &a, const T &b) {if (a < b) {a = b;return true;}return false;}template <class T>bool chmin(T &a, const T &b) {if (a > b) {a = b;return true;}return false;}template <class T>T div_floor(T a, T b) {if (b < 0) a *= -1, b *= -1;return a >= 0 ? a / b : (a + 1) / b - 1;}template <class T>T div_ceil(T a, T b) {if (b < 0) a *= -1, b *= -1;return a > 0 ? (a - 1) / b + 1 : a / b;}constexpr lint mod = 1000000007;constexpr lint INF = mod * mod;constexpr int MAX = 200010;template <int_fast64_t MOD>struct modint {using i64 = int_fast64_t;i64 a;modint(const i64 a_ = 0) : a(a_) {if (a > MOD)a %= MOD;else if (a < 0)(a %= MOD) += MOD;}modint inv() {i64 t = 1, n = MOD - 2, x = a;while (n) {if (n & 1) (t *= x) %= MOD;(x *= x) %= MOD;n >>= 1;}modint ret(t);return ret;}bool operator==(const modint x) const { return a == x.a; }bool operator!=(const modint x) const { return a != x.a; }modint operator+(const modint x) const { return modint(*this) += x; }modint operator-(const modint x) const { return modint(*this) -= x; }modint operator*(const modint x) const { return modint(*this) *= x; }modint operator/(const modint x) const { return modint(*this) /= x; }modint operator^(const lint x) const { return modint(*this) ^= x; }modint &operator+=(const modint &x) {a += x.a;if (a >= MOD) a -= MOD;return *this;}modint &operator-=(const modint &x) {a -= x.a;if (a < 0) a += MOD;return *this;}modint &operator*=(const modint &x) {(a *= x.a) %= MOD;return *this;}modint &operator/=(modint x) {(a *= x.inv().a) %= MOD;return *this;}modint &operator^=(lint n) {i64 ret = 1;while (n) {if (n & 1) (ret *= a) %= MOD;(a *= a) %= MOD;n >>= 1;}a = ret;return *this;}modint operator-() const { return modint(0) - *this; }modint &operator++() { return *this += 1; }modint &operator--() { return *this -= 1; }bool operator<(const modint x) const { return a < x.a; }};using mint = modint<1000000007>;vector<mint> fact;vector<mint> revfact;void setfact(int n) {fact.resize(n + 1);revfact.resize(n + 1);fact[0] = 1;rep(i, n) fact[i + 1] = fact[i] * mint(i + 1);revfact[n] = fact[n].inv();for (int i = n - 1; i >= 0; i--) revfact[i] = revfact[i + 1] * mint(i + 1);}mint getC(int n, int r) {if (n < r) return 0;return fact[n] * revfact[r] * revfact[n - r];}int main() {int n;scanf("%d", &n);int a[n + 1];For(i, 1, n + 1) scanf("%d", &a[i]);int b = 400;mint dp[n + 1], sum[b][b];rep(i, n + 1) dp[i] = 0;dp[1] = 1;rep(i, b) rep(j, b) sum[i][j] = 0;For(i, 1, n) {if (a[i] < b) {sum[a[i]][i % a[i]] += dp[i];} else {for (int j = i + a[i]; j <= n; j += a[i]) {dp[j] += dp[i];}}if (a[i] != 1) dp[i + 1] += dp[i];For(k, 1, b) dp[i + 1] += sum[k][(i + 1) % k];}printf("%lld\n", dp[n].a);}