#60145 (C++11（廃止可能性あり）) No.269 見栄っ張りの募金活動

• 問題: No.269 見栄っ張りの募金活動
• ユーザー: Gyuuto
• 提出日時: 2015-11-25 18:08:26
• 言語: C++11（廃止可能性あり） (gcc 13.3.0)
• 結果: AC
• 実行時間: 21 ms / 5,000 ms
• コード長: 2,097 bytes
• コンパイル時間: 853 ms
• コンパイル使用メモリ: 82,500 KB
• 実行使用メモリ: 18,944 KB
• 最終ジャッジ日時: 2024-07-16 01:52:18
• 合計ジャッジ時間: 1,472 ms
• ジャッジサーバーID （参考情報）: judge1 / judge3

ファイルパターン	結果
sample	AC * 3
other	AC * 22

ソースコード

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// Standard I/O
#include <iostream>
#include <sstream>
#include <cstdio>
// Standard Library
#include <cstdlib>
#include <cstring>
#include <ctime>
#include <cmath>
// Template Class
#include <complex>
#include <string>
#include <vector>
#include <list>
#include <set>
#include <map>
#include <queue>
#include <stack>
// Container Control
#include <algorithm>
using namespace std;
#define rep( i, n ) for( int i = 0; i < n; ++i )
#define irep( i, n ) for( int i = n-1; i >= 0; --i )
#define reep( i, s, n ) for ( int i = s; i < n; ++i )
#define ireep( i, n, s ) for ( int i = n-1; i >= s; --i )
#define foreach(itr, x) for( typeof(x.begin()) itr = x.begin(); itr != x.end(); ++itr)
#define mp( a, b ) make_pair( a, b )
#define pb( a ) push_back( a )
#define all( v ) v.begin(), v.end()
#define fs first
#define sc second
#define vc vector
// for visualizer.html
double SCALE = 1.0;
double OFFSET_X = 0.0;
double OFFSET_Y = 0.0;
#define LINE(x,y,a,b) cerr << "line(" << SCALE*(x) + OFFSET_X << ","    \
    << SCALE*(y) + OFFSET_Y << ","                                      \
    << SCALE*(a) + OFFSET_X << ","                                      \
    << SCALE*(b) + OFFSET_Y << ")" << endl;
#define CIRCLE(x,y,r) cerr << "circle(" << SCALE*(x) + OFFSET_X << ","  \
    << SCALE*(y) + OFFSET_Y << ","                                      \
    << SCALE*(r) << ")" << endl;
typedef long long ll;
typedef complex<double> Point;
typedef pair<int, int> pii;
typedef pair<int, pii> ipii;
typedef vector<int> vi;
typedef vector<double> vd;
typedef vector< vector<int> > vii;
typedef vector< vector<double> > vdd;
typedef vector<int>::iterator vi_itr;
const int IINF = 1 << 28;
const ll LINF = 1ll << 50;
const double INF = 1e30;
const double EPS = 1e-10;
const double PI = acos(-1.0);
// Direction : L U R D
const int dx[] = { -1, 0, 1, 0};
const int dy[] = { 0, -1, 0, 1 };
ll N, S, K;
ll dp[110][20010];
const ll MOD = 1000000007ll;
int main()
{
    cin >> N >> S >> K;
    for( int i = 0; i*N <= S; ++i ) dp[0][i*N] = 1;
    
    reep(i, 1, N) rep(j, S+1)
        dp[i][j] = (dp[i][j] + (j-K*(N-i) < 0 ? 0 : dp[i-1][j-K*(N-i)]) + (j-(N-i) < 0 ? 0 : dp[i][j-(N-i)]))%MOD;
    cout << dp[N-1][S]%MOD << endl;
}
 
 
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