結果

問題 No.1349 Subset Product Queries
ユーザー PCTprobability
提出日時 2021-01-13 19:34:16
言語 C++17(gcc12)
(gcc 12.3.0 + boost 1.87.0)
結果
WA  
実行時間 -
コード長 3,932 bytes
コンパイル時間 19,448 ms
コンパイル使用メモリ 292,984 KB
最終ジャッジ日時 2025-01-17 17:32:36
ジャッジサーバーID
（参考情報） 		judge4 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
sample WA * 1
other AC * 1 WA * 29
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

// TLE code
#pragma GCC target("avx")
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
#include <bits/stdc++.h>
using namespace std;
#define rep(i, n)  for(long long i=0;i<(long long)(n);i++)
#define REP(i,k,n) for(long long i=k;i<(long long)(n);i++)
#define all(a) a.begin(),a.end()
#define rsort(a) {sort(all(a));reverse(all(a));}
#define pb emplace_back
#define eb emplace_back
#define lb(v,k) (lower_bound(all(v),(k))-v.begin())
#define ub(v,k) (upper_bound(all(v),(k))-v.begin())
#define fi first
#define se second
#define pi M_PI
#define PQ(T) priority_queue<T>
#define SPQ(T) priority_queue<T,vector<T>,greater<T>>
#define dame(a) {out(a);return 0;}
#define decimal cout<<fixed<<setprecision(15);
#define dupli(a) {sort(all(a));a.erase(unique(all(a)),a.end());}
typedef long long ll;
typedef pair<ll,ll> P;
typedef tuple<ll,ll,ll> PP;
typedef tuple<ll,ll,ll,ll> PPP;
typedef multiset<ll> S;
using vi=vector<ll>;
using vvi=vector<vi>;
using vvvi=vector<vvi>;
using vvvvi=vector<vvvi>;
using vp=vector<P>;
using vvp=vector<vp>;
using vb=vector<bool>;
using vvb=vector<vb>;
const ll inf=1001001001001001001;
const ll INF=1001001001;
const ll mod=1000000007;
const double eps=1e-10;
template<class T> bool chmin(T&a,T b){if(a>b){a=b;return true;}return false;}
template<class T> bool chmax(T&a,T b){if(a<b){a=b;return true;}return false;}
template<class T> void out(T a){cout<<a<<'\n';}
template<class T> void outp(T a){cout<<'('<<a.fi<<','<<a.se<<')'<<'\n';}
template<class T> void outvp(T v){rep(i,v.size())cout<<'('<<v[i].fi<<','<<v[i].se<<')';cout<<'\n';}
template<class T> void outvvp(T v){rep(i,v.size())outvp(v[i]);}
template<class T> void outv(T v){rep(i,v.size()){if(i)cout<<' ';cout<<v[i];}cout<<'\n';}
template<class T> void outvv(T v){rep(i,v.size())outv(v[i]);}
template<class T> bool isin(T x,T l,T r){return (l)<=(x)&&(x)<=(r);}
template<class T> void yesno(T b){if(b)out("yes");else out("no");}
template<class T> void YesNo(T b){if(b)out("Yes");else out("No");}
template<class T> void YESNO(T b){if(b)out("YES");else out("NO");}
template<class T> void noyes(T b){if(b)out("no");else out("yes");}
template<class T> void NoYes(T b){if(b)out("No");else out("Yes");}
template<class T> void NOYES(T b){if(b)out("NO");else out("YES");}
inline ll readll() {
    ll x = 0;
    char ch = getchar_unlocked();
    while (ch < '0' || ch > '9') ch = getchar_unlocked();
    while (ch >= '0' && ch <= '9'){
        x = (x << 3) + (x << 1) + ch - '0';
        ch = getchar_unlocked();
    }
    return x;
}
void outs(ll a,ll b){if(a>=inf-100)out(b);else out(a);}
ll gcd(ll a,ll b){if(b==0)return a;return gcd(b,a%b);}
ll modpow(ll a,ll b){ll res=1;a%=mod;while(b){if(b&1)res=res*a%mod;a=a*a%mod;b>>=1;}return res;}
const ll B=10;
int main(){
    ll n=readll(),q=readll();
    vvp query(n);
    vi idx(n);
    vi v(n);rep(i,n)v[i]=readll();
    vi K(q);
    vi ans(q,-1);
    rep(i,q){
        ll l=readll(),r=readll();K[i]=readll();l--;r--;
        if(r-l<=100){
            bitset<5001> dp;
            dp.set(0);
            REP(j,l,r+1){
                dp|=dp<<v[j];
                if(dp.test(K[i])){
                    ans[i]=1;break;
                }
            }
            if(ans[i]==-1)ans[i]=0;
        }
        // else if(K[i]>=mx)ans[i]=true;
        else query[r].pb(l,i);
    }
    rep(i,n)sort(all(query[i]));
    for(int i=0;i<n;i+=B){
        bitset<5001> dp;
        dp.set(0);
        REP(j,i,n){
            dp|=dp<<v[j];
            while(idx[j]<query[j].size()&&query[j][idx[j]].fi<i){
                auto x=query[j][idx[j]];
                bitset<5001> ndp=dp;
                for(int t=i-1;t>=x.fi;t--){
                    ndp|=ndp<<v[t];
                    if(ndp.test(K[x.se])){
                        ans[x.se]=1;break;
                    }
                }
                if(ans[x.se]==-1)ans[x.se]=0;
                idx[j]++;
            }
        }
    }
    for(ll x:ans)YesNo(x);
}
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