結果

問題 No.1344 Typical Shortest Path Sum
ユーザー yuto1115yuto1115
提出日時 2021-01-16 14:27:37
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 27 ms / 2,000 ms
コード長 4,115 bytes
コンパイル時間 2,008 ms
コンパイル使用メモリ 198,740 KB
最終ジャッジ日時 2025-01-17 22:50:05
ジャッジサーバーID
(参考情報)
judge4 / judge1
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 77
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

//@formatter:off
#include<bits/stdc++.h>
#define overload4(_1,_2,_3,_4,name,...) name
#define rep1(i,n) for (ll i = 0; i < ll(n); ++i)
#define rep2(i,s,n) for (ll i = ll(s); i < ll(n); ++i)
#define rep3(i,s,n,d) for(ll i = ll(s); i < ll(n); i+=d)
#define rep(...) overload4(__VA_ARGS__,rep3,rep2,rep1)(__VA_ARGS__)
#define rrep(i,n) for (ll i = ll(n)-1; i >= 0; i--)
#define all(a) a.begin(),a.end()
#define rall(a) a.rbegin(),a.rend()
#define pb push_back
#define eb emplace_back
#define vi vector<int>
#define vvi vector<vector<int>>
#define vl vector<ll>
#define vvl vector<vector<ll>>
#define vd vector<double>
#define vvd vector<vector<double>>
#define vs vector<string>
#define vc vector<char>
#define vvc vector<vector<char>>
#define vb vector<bool>
#define vvb vector<vector<bool>>
#define vp vector<P>
#define vvp vector<vector<P>>
#ifdef __LOCAL
#define debug(...) { cout << #__VA_ARGS__; cout << ": "; print(__VA_ARGS__); cout << flush; }
#else
#define debug(...) void(0)
#endif
#define INT(...) int __VA_ARGS__;scan(__VA_ARGS__)
#define LL(...) ll __VA_ARGS__;scan(__VA_ARGS__)
#define STR(...) string __VA_ARGS__;scan(__VA_ARGS__)
#define CHR(...) char __VA_ARGS__;scan(__VA_ARGS__)
#define DBL(...) double __VA_ARGS__;scan(__VA_ARGS__)
#define LD(...) ld __VA_ARGS__;scan(__VA_ARGS__)
using namespace std;
using ll = long long;
using P = pair<int,int>;
using LP = pair<ll,ll>;
template<class S,class T> istream& operator>>(istream &is,pair<S,T> &p) { return is >> p.first >> p.second; }
template<class S,class T> ostream& operator<<(ostream &os,const pair<S,T> &p) { return os<<'{'<<p.first<<","<<p.second<<'}'; }
template<class T> istream& operator>>(istream &is,vector<T> &v) { for(T &t:v){is>>t;} return is; }
template<class T> ostream& operator<<(ostream &os,const vector<T> &v) { os<<'[';rep(i,v.size())os<<v[i]<<(i==int(v.size()-1)?"":","); return os<<']';
    }
void Yes(bool b) { cout << (b ? "Yes" : "No") << '\n'; }
void YES(bool b) { cout << (b ? "YES" : "NO") << '\n'; }
template<class T> void fin(T a) { cout << a << '\n'; exit(0); }
template<class T> bool chmin(T& a,T b) {if(a > b){a = b; return true;} return false;}
template<class T> bool chmax(T& a,T b) {if(a < b){a = b; return true;} return false;}
void scan(){}
template <class Head, class... Tail> void scan(Head& head, Tail&... tail){ cin >> head; scan(tail...); }
template<class T> void print(const T& t){ cout << t << '\n'; }
template <class Head, class... Tail> void print(const Head& head, const Tail&... tail){ cout<<head<<' '; print(tail...); }
const int inf = 1001001001;
const ll linf = 1001001001001001001;
//@formatter:on
struct edge {
int a, b; // from a to b
ll len;
edge(int a, int b, ll l) : a(a), b(b), len(l) {}
};
// return value is {} if there is a negative cycle.
/* detect only if a certain node(goal) is reachable
from a negative cycle (if goal != -1) */
// detect any negative cycles (if goal == -1)
vector<ll> bellman_ford(int n, const vector<edge> &v, int start, int goal = -1) {
vector<ll> dist(n, linf);
dist[start] = 0;
if (goal == -1) {
rep(i, n) {
for (auto e : v) {
if (dist[e.a] < linf && chmin(dist[e.b], dist[e.a] + e.len)) {
if (i == n - 1) return {};
}
}
}
} else {
rep(i, n * 2) {
for (auto e : v) {
if (dist[e.a] < linf && chmin(dist[e.b], dist[e.a] + e.len)) {
if (i >= n - 1 && e.b == goal) return {};
else if (i >= n - 1) dist[e.b] = -linf;
}
}
}
}
return dist;
}
using vve = vector<vector<edge>>;
int main() {
ios::sync_with_stdio(false);
cin.tie(nullptr);
cout.tie(nullptr);
INT(n, m);
vector<edge> es;
rep(_, m) {
INT(s, t);
LL(d);
s--;
t--;
es.eb(s, t, d);
}
rep(i, n) {
vl dist = bellman_ford(n, es, i);
ll ans = 0;
rep(j, n) {
if (dist[j] == linf) continue;
ans += dist[j];
}
print(ans);
}
}
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