#606983 (PyPy3) No.1043 直列大学

• 問題: No.1043 直列大学
• ユーザー: tcltk
• 提出日時: 2021-01-17 23:31:41
• 言語: PyPy3 (7.3.15)
• 結果: AC
• 実行時間: 907 ms / 2,000 ms
• コード長: 1,587 bytes
• コンパイル時間: 298 ms
• コンパイル使用メモリ: 82,316 KB
• 実行使用メモリ: 367,152 KB
• 最終ジャッジ日時: 2024-12-22 20:13:52
• 合計ジャッジ時間: 10,602 ms
• ジャッジサーバーID （参考情報）: judge5 / judge3

ファイルパターン	結果
sample	AC * 3
other	AC * 28

ソースコード

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#region Header
#!/usr/bin/env python3
# from typing import *
import sys
import io
import math
import collections
import decimal
import itertools
from queue import PriorityQueue
import bisect
import heapq
def input():
    return sys.stdin.readline()[:-1]
sys.setrecursionlimit(1000000)
#endregion
# _INPUT = """3 3
# 2 3 4
# 10 23 26
# 1 100
# """
# sys.stdin = io.StringIO(_INPUT)
MOD = 1000000007
def main():
    N, M = map(int, input().split())
    V = list(map(int, input().split()))
    R = list(map(int, input().split()))
    A, B = map(int, input().split())
    SumV = sum(V)
    dpV = [[0 for _ in range(SumV+1)] for _ in range(N)]
    dpV[0][0] = 1
    dpV[0][V[0]] = 1
    for i in range(0, N-1):
        for v in range(SumV+1):
            if dpV[i][v] > 0:
                dpV[i+1][v] += dpV[i][v]
                dpV[i+1][v+V[i+1]] += dpV[i][v]
    SumR = sum(R)
    dpR = [[0 for _ in range(SumR+1)] for _ in range(M)]
    dpR[0][0] = 1
    dpR[0][R[0]] = 1
    for i in range(0, M-1):
        for r in range(SumR+1):
            if dpR[i][r] > 0:
                dpR[i+1][r] += dpR[i][r]
                dpR[i+1][r+R[i+1]] += dpR[i][r]
    SV = [0 for _ in range(SumV+1)]
    SV[0] = dpV[N-1][0]
    for v in range(1, SumV+1):
        SV[v] = SV[v-1] + dpV[N-1][v]
    n = 0
    for r in range(1, SumR+1):
        v1 = max(r*A, 1)
        v2 = min(r*B, SumV)
        if v1 <= v2:
            n += dpR[M-1][r] * (SV[v2] - SV[v1-1])
    print(n % MOD)
if __name__ == '__main__':
    main()
 
 
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