結果
| 問題 |
No.526 フィボナッチ数列の第N項をMで割った余りを求める
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2021-01-18 05:37:38 |
| 言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 2 ms / 2,000 ms |
| コード長 | 2,953 bytes |
| コンパイル時間 | 2,139 ms |
| コンパイル使用メモリ | 176,260 KB |
| 実行使用メモリ | 6,820 KB |
| 最終ジャッジ日時 | 2024-11-30 14:14:03 |
| 合計ジャッジ時間 | 2,662 ms |
|
ジャッジサーバーID (参考情報) |
judge3 / judge4 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 12 |
ソースコード
/* C++ */
#include<bits/stdc++.h>
using namespace std;
typedef long long int ll;
typedef long double ld;
typedef vector<ll> vl;
typedef vector<vector<ll>> vvl;
typedef vector<vector<vector<ll>>> vvvl;
typedef pair<ll, ll> pint;
const ll MOD = 1000000007;
const ll INF = 922337203685477580;
#define rep(i, n) for(ll i = (ll)0; i < (ll)(n); i++)
#define Rep(i, s, t) for(ll i = (ll)(s); i < (ll)(t); i++)
#define ALL(a) (a).begin(),(a).end()
#define IOS ios::sync_with_stdio(0); cin.tie(0); cout.tie(0);
#define PI 3.14159265358979323846
#define ifYN(x) cout << (x ? "Yes" : "No") << "\n"
ll dx[4] = {-1, 1, 0, 0};
ll dy[4] = {0, 0, -1, 1};
template<class T> inline bool chmin(T& a, T b) {
if (a > b) {
a = b;
return true;
}
return false;
}
template<class T> inline bool chmax(T& a, T b) {
if (a < b) {
a = b;
return true;
}
return false;
}
ll Len(ll n) {
if (n == 0) return 1;
ll s = 0;
while (n != 0) s++, n /= 10;
return s;
}
ll Sint(ll n) {
ll ans = 0;
while (n != 0) ans += n % 10, n /= 10;
return ans;
}
ll Svec(vector<ll> v){
ll n = 0;
rep(i, (ll)v.size()) n += v[i];
return n;
}
ll GCD(ll a, ll b) {
return b ? GCD(b, a % b) : a;
}
ll LCM(ll a, ll b){
return a / GCD(a, b) * b;
}
ll POW(ll a, ll n, ll mod = INF) {
ll res = 1;
while (n > 0) {
if (n & 1) res = res * a % mod;
a = a * a % mod;
n >>= 1;
}
return res;
}
void dis(vector<ll> v){ rep(i, v.size()) cout << v[i] << endl; }
void dis2(vector<vector<ll> > v) {
rep (i, v.size()) {
rep (j, v[0].size()) cout << v[i][j] << ' ';
cout << endl;
}
}
bool cmp(pint a, pint b) { return a.second < b.second; }
vector<vector<ll>> MATMUL(vector<vector<ll>> &A, vector<vector<ll>> &B, ll MOD) {
vector<vector<ll>> ret(A.size(), vector<ll>(B[0].size(), 0));
rep (i, A.size()) {
rep (j, B[0].size()) {
rep (k, B.size()) {
ret[i][j] = (ret[i][j] + A[i][k] * B[k][j]) % MOD;
}
}
}
return ret;
}
vector<vector<ll>> MATPOW(vector<vector<ll>> A, ll K, ll MOD) {
ll N = A.size();
vector<vector<ll>> ret(N, vector<ll>(N, 0));
rep (i, N) ret[i][i] = 1;
while (K) {
if (K & 1) ret = MATMUL(ret, A, MOD);
A = MATMUL(A, A, MOD);
K >>= 1;
}
return ret;
}
/*
void MATPOW(vector<ll> &dp, vector<vector<ll>> &mat, ll k, ll MOD) {
ll N = mat.size();
while (k > 0) {
if (k & 1) {
vector<ll> ret(N, 0);
rep (i, N) rep (j, N) ret[i] += mat[i][j] * dp[j], ret[i] %= MOD;
dp = ret;
}
vector<vector<ll>> ret(N, vector<ll>(N, 0));
rep (i, N) rep (j, N) rep (k, N) ret[i][j] += mat[i][k] * mat[k][j], ret[i][j] %= MOD;
mat = ret;
k >>= 1;
}
return;
}*/
/*↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓*/
int main() {
IOS;
ll N, M; cin >> N >> M;
vector<vector<ll>> dp = {{1}, {0}};
vector<vector<ll>> mat = {{1, 1}, {1, 0}};
mat = MATPOW(mat, N - 1, M);
dp = MATMUL(mat, dp, M);
cout << dp[1][0] << endl;
}