結果
問題 | No.269 見栄っ張りの募金活動 |
ユーザー |
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提出日時 | 2021-01-18 16:59:56 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 66 ms / 5,000 ms |
コード長 | 3,601 bytes |
コンパイル時間 | 1,064 ms |
コンパイル使用メモリ | 110,708 KB |
実行使用メモリ | 21,120 KB |
最終ジャッジ日時 | 2024-12-14 07:28:27 |
合計ジャッジ時間 | 2,070 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge3 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 22 |
ソースコード
#include <iostream>#include <iomanip>#include <vector>#include <set>#include <string>#include <queue>#include <algorithm>#include <map>#include <cmath>#include <numeric>#include <list>#include <stack>#include <cstdio>#include <cstdlib>#include <cstring>#include <tuple>#include <deque>#include <complex>#include <bitset>#include <functional>#include <cassert>//#include <atcoder/all>using namespace std;//using namespace atcoder;using ll = long long;using vll = vector<ll>;using vvll = vector<vll>;using pll = pair<ll, ll>;using vpll = vector<pll>;using ld = long double;using vld = vector<ld>;using vb = vector<bool>;#define rep(i, n) for (ll i = 0; i < (n); i++)#ifdef LOCAL#define dbg(x) cerr << __LINE__ << " : " << #x << " = " << (x) << endl#else#define dbg(x) true#endiftemplate <class T> void chmin(T& a, T b) { a = min(a, b);}template <class T> void chmax(T& a, T b) { a = max(a, b);}template <class T> ostream& operator<<(ostream& s, const vector<T>& a) { for(auto i : a) s << i << ' '; return s; }constexpr ll INFL = 1LL << 60;constexpr ld EPS = 1e-12;ld PI = acos(-1.0);struct mint {static const long long mod = 1000000007;long long x;mint(long long x = 0) : x((x % mod + mod) % mod) {}mint operator-() const { return mint(-x);}mint& operator+=(const mint& a) {if ((x += a.x) >= mod) x -= mod; return *this;}mint& operator-=(const mint& a) {if ((x += mod - a.x) >= mod) x -= mod; return *this;}mint& operator*=(const mint& a) {(x *= a.x) %= mod; return *this;}friend const mint operator+(const mint& a, const mint& b) { mint ret = a; return ret += b; }friend const mint operator-(const mint& a, const mint& b) { mint ret = a; return ret -= b; }friend const mint operator*(const mint& a, const mint& b) { mint ret = a; return ret *= b; }friend ostream& operator<<(ostream& s, const mint& a) { return s << a.x; }mint pow(long long t) const {if (!t) return 1;mint a = pow(t >> 1);a *= a;if (t & 1) a *= *this;return a;}// for prime modmint inv() const { return pow(mod - 2);}mint& operator/=(const mint a) { return (*this) *= a.inv();}friend const mint operator/(const mint& a, const mint& b) { mint ret = a; return ret /= b; }};struct combi {const static long long mod = mint::mod;int n;vector<mint> fac, finv, inv;combi(int _n) : n(_n + 1), fac(n, 1), finv(n, 1), inv(n, 1) {for (int i = 2; i < n; ++i) {fac[i] = fac[i - 1] * i;inv[i] =- inv[mod % i] * (mod / i);finv[i] = finv[i - 1] * inv[i];}};mint get(int n, int k) {if(n < k) return 0;if(n < 0 || k < 0) return 0;mint ret = fac[n] * finv[k] * finv[n - k];return ret;}};void solve() {ll n, s, k;cin >> n >> s >> k;s -= n*(n-1)*k/2;if(s < 0) {cout << 0 << endl;return;}vector<vb> memob(s+1, vb(n+1, false));using vm = vector<mint>;vector<vm> memom(s+1, vm(n+1));function<mint(int, int)> rec = [&](int a, int b) {if(a < 0 || b == 0) return mint(0);else if(a == 0 || b == 1) return mint(1);else if(memob[a][b]) return memom[a][b];memom[a][b] += rec(a, b-1) + rec(a-b, b);memob[a][b] = true;return memom[a][b];};cout << rec(s, n) << endl;return;}int main() {std::cin.tie(nullptr);std::ios_base::sync_with_stdio(false);cout << fixed << setprecision(15);solve();}