結果

問題 No.1366 交換門松列・梅
ユーザー wdiiahkwdiiahk
提出日時 2021-01-30 00:16:36
言語 C++17
(gcc 12.3.0 + boost 1.83.0)
結果
AC  
実行時間 2 ms / 1,000 ms
コード長 5,546 bytes
コンパイル時間 2,714 ms
コンパイル使用メモリ 216,676 KB
実行使用メモリ 6,820 KB
最終ジャッジ日時 2024-12-16 13:18:10
合計ジャッジ時間 3,143 ms
ジャッジサーバーID
（参考情報） 		judge3 / judge4
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
6,816 KB
testcase_01 AC 2 ms
6,816 KB
testcase_02 AC 2 ms
6,816 KB
testcase_03 AC 1 ms
6,820 KB
testcase_04 AC 2 ms
6,816 KB
testcase_05 AC 1 ms
6,820 KB
testcase_06 AC 2 ms
6,820 KB
testcase_07 AC 2 ms
6,816 KB
testcase_08 AC 1 ms
6,816 KB
testcase_09 AC 1 ms
6,816 KB
testcase_10 AC 2 ms
6,816 KB
testcase_11 AC 1 ms
6,816 KB
testcase_12 AC 2 ms
6,820 KB
testcase_13 AC 2 ms
6,820 KB
権限があれば一括ダウンロードができます

ソースコード

diff # 

//デバッグ用オプション：-fsanitize=undefined,address

//コンパイラ最適化
#pragma GCC optimize("Ofast")

//インクルードなど
#include <bits/stdc++.h>
//#include <atcoder/all>

using namespace std;
//using namespace atcoder;

typedef long long ll;
using vint = vector<int>;
using vll = vector<ll>;
using vbool = vector<bool>;
using vs = vector<string>;
using P = pair<ll, ll>;
using vp = vector<P>;
template <class T>
using arr = vector<vector<T>>;

//マクロ
#define REP(i, n) for (ll i = 0; i < ll(n); i++)
#define REPD(i, n) for (ll i = n - 1; i >= 0; i--)
#define FOR(i, a, b) for (ll i = a; i < ll(b); i++)
#define FORD(i, a, b) for (ll i = a; i >= ll(b); i--)
#define FORA(i, I) for (const auto &i : I)
#define ALL(x) x.begin(), x.end()
#define SIZE(x) ll(x.size())
#define INF 9223372036854775807

template <typename T>
bool chmax(T &a, const T &b)
{
  if (a < b)
  {
    a = b; // aをbで更新
    return true;
  }
  return false;
}
template <typename T>
bool chmin(T &a, const T &b)
{
  if (a > b)
  {
    a = b; // aをbで更新
    return true;
  }
  return false;
}

template <class T>
void pl(T x) { cout << x << " "; }

template <class T>
void pr(T x) { cout << x << endl; }

template <class T>
void prvec(const vector<T> &a)
{
  REP(i, a.size() - 1)
  {
    cout << a[i] << " ";
  }
  pr(a[a.size() - 1]);
}

template <class T>
void prarr(const arr<T> &a)
{
  REP(i, a.size())
  if (a[i].empty())
    pr("");
  else
    prvec(a[i]);
}

template <typename T1, typename T2>
pair<T1, T2> operator+(const pair<T1, T2> &l, const pair<T1, T2> &r) { return {l.first + r.first, l.second + r.second}; }
template <typename T1, typename T2>
pair<T1, T2> operator-(const pair<T1, T2> &l, const pair<T1, T2> &r) { return {l.first - r.first, l.second - r.second}; }
template <typename T>
pair<T, T> operator*(const pair<T, T> &l, const T &r) { return {l.first * r, l.second * r}; }
template <typename T>
pair<T, T> operator/(const pair<T, T> &l, const T &r) { return {l.first / r, l.second / r}; }

template <typename T>
istream &operator>>(istream &is, vector<T> &vec)
{
  for (auto &v : vec)
    is >> v;
  return is;
}
template <typename T>
ostream &operator<<(ostream &os, const vector<T> &vec)
{
  os << "[";
  for (auto v : vec)
    os << v << ",";
  os << "]";
  return os;
}

template <typename T>
ostream &operator<<(ostream &os, const deque<T> &vec)
{
  os << "deq[";
  for (auto v : vec)
    os << v << ",";
  os << "]";
  return os;
}

template <typename T>
ostream &operator<<(ostream &os, const set<T> &vec)
{
  os << "{";
  for (auto v : vec)
    os << v << ",";
  os << "}";
  return os;
}

template <typename T>
ostream &operator<<(ostream &os, const unordered_set<T> &vec)
{
  os << "{";
  for (auto v : vec)
    os << v << ",";
  os << "}";
  return os;
}
template <typename T>
ostream &operator<<(ostream &os, const multiset<T> &vec)
{
  os << "{";
  for (auto v : vec)
    os << v << ",";
  os << "}";
  return os;
}
template <typename T>
ostream &operator<<(ostream &os, const unordered_multiset<T> &vec)
{
  os << "{";
  for (auto v : vec)
    os << v << ",";
  os << "}";
  return os;
}
template <typename T1, typename T2>
istream &operator>>(istream &is, pair<T1, T2> &pa)
{
  is >> pa.first >> pa.second;
  return is;
}
template <typename T1, typename T2>
ostream &operator<<(ostream &os, const pair<T1, T2> &pa)
{
  os << "(" << pa.first << "," << pa.second << ")";
  return os;
}
template <typename... Ts>
istream &operator>>(istream &is, tuple<Ts...> &theTuple)
{
  apply([&is](Ts &...tupleArgs) { ((is >> tupleArgs), ...); }, theTuple);
  return is;
}
template <typename... Ts>
ostream &operator<<(ostream &os, const tuple<Ts...> &theTuple)
{
  apply([&os](const Ts &...tupleArgs) {
    os << '(';
    size_t n(0);
    ((os << tupleArgs << (++n < sizeof...(Ts) ? "," : "")), ...);
    os << ')';
  },
        theTuple);
  return os;
}
template <typename TK, typename TV>
ostream &operator<<(ostream &os, const map<TK, TV> &mp)
{
  os << "{";
  for (auto v : mp)
    os << v.first << "=>" << v.second << ",";
  os << "}";
  return os;
}
template <typename TK, typename TV>
ostream &operator<<(ostream &os, const unordered_map<TK, TV> &mp)
{
  os << "{";
  for (auto v : mp)
    os << v.first << "=>" << v.second << ",";
  os << "}";
  return os;
}

// const int intinf = numeric_limits<int>::max();
// const ll INF = numeric_limits<ll>::max();
// const P udlr[4] = {{1, 0}, {0, 1}, {-1, 0}, {0, -1}};
//
//

struct Constants
{
  ll N;
  Constants()
  {
    N = 3;
  }
} C;

struct Args
{
  vll a, b;
  Args() : a(C.N), b(C.N)
  {
    ios::sync_with_stdio(false);
    cin.tie(nullptr);
    cin >> a >> b;
  }
} args;

struct Solver
{
  bool ans;
  Solver() : ans(false)
  {
  }
  bool ok(const vll &v)
  {
    REP(i, C.N - 1)
    {
      FOR(j, i + 1, C.N)
      {
        if (v.at(i) == v.at(j))
        {
          return false;
        }
      }
    }

    if (v.at(0) < v.at(1) && v.at(1) > v.at(2))
    {
      return true;
    }
    if (v.at(0) > v.at(1) && v.at(1) < v.at(2))
    {
      return true;
    }
    return false;
  }
  //
  void solve()
  {
    if (ok(args.a) && ok(args.b))
    {
      ans = true;
      return;
    }

    REP(i, C.N)
    {
      REP(j, C.N)
      {
        vll a(args.a);
        vll b(args.b);
        swap(a.at(i), b.at(j));
        if (ok(a) && ok(b))
        {
          ans = true;
          return;
        }
      }
    }
  }
  //
  void output()
  {
    pr(ans ? "Yes" : "No");
  }
} s;

int main()
{
  s.solve();
  s.output();
  return 0;
}
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