結果
問題 | No.168 ものさし |
ユーザー |
|
提出日時 | 2021-02-01 20:13:33 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 247 ms / 2,000 ms |
コード長 | 2,404 bytes |
コンパイル時間 | 1,215 ms |
コンパイル使用メモリ | 138,504 KB |
最終ジャッジ日時 | 2025-01-18 10:39:30 |
ジャッジサーバーID (参考情報) |
judge5 / judge4 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 4 |
other | AC * 19 |
ソースコード
#include <iostream>#include <vector>#include <algorithm>#include <cmath>#include <queue>#include <string>#include <map>#include <set>#include <stack>#include <tuple>#include <deque>#include <array>#include <numeric>#include <bitset>#include <iomanip>#include <cassert>#include <chrono>#include <random>#include <limits>#include <iterator>#include <functional>#include <sstream>#include <fstream>#include <complex>#include <cstring>#include <unordered_map>#include <unordered_set>using namespace std;using ll = long long;constexpr int INF = 1001001001;// constexpr int mod = 1000000007;constexpr int mod = 998244353;template<class T>inline bool chmax(T& x, T y){if(x < y){x = y;return true;}return false;}template<class T>inline bool chmin(T& x, T y){if(x > y){x = y;return true;}return false;}int main(){ios::sync_with_stdio(false);cin.tie(nullptr);int N;cin >> N;vector<ll> X(N), Y(N);for(int i = 0; i < N; ++i) cin >> X[i] >> Y[i];vector<vector<ll>> d(N, vector<ll>(N));for(int i = 0; i < N; ++i){for(int j = 0; j < i; ++j){ll dx = abs(X[i] - X[j]), dy = abs(Y[i] - Y[j]);d[i][j] = d[j][i] = dx * dx + dy * dy;}}auto bfs = [&](int s, ll bound){vector<ll> dist(N, INF);queue<int> que;dist[s] = 0;que.emplace(s);while(!que.empty()){int from = que.front();que.pop();for(int to = 0; to < N; ++to){if(to == from || d[from][to] > bound) continue;if(chmin(dist[to], dist[from] + 1)){que.emplace(to);}}}return dist;};ll lb = 0, ub = 3e+18;while(ub - lb > 1){ll mid = (lb + ub) / 2;auto dist1 = bfs(0, mid);auto distN = bfs(N - 1, mid);bool ok = false;for(int i = 0; i < N; ++i){if(dist1[i] != INF && distN[i] != INF) ok = true;}if(ok) ub = mid;else lb = mid;}ll low = 0, high = 2e+9;while(high - low > 1){ll mid = (low + high) / 2;if(mid * mid >= ub) high = mid;else low = mid;}cout << high / 10 * 10 + (high % 10 > 0) * 10 << endl;return 0;}