結果

問題 No.1411 Hundreds of Conditions Sequences
ユーザー kiyoshi0205
提出日時 2021-02-28 18:06:47
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
RE  
実行時間 -
コード長 4,184 bytes
コンパイル時間 3,198 ms
コンパイル使用メモリ 201,920 KB
実行使用メモリ 9,472 KB
最終ジャッジ日時 2024-10-02 20:58:54
合計ジャッジ時間 19,800 ms
ジャッジサーバーID
(参考情報)
judge2 / judge1
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample RE * 2
other RE * 62
権限があれば一括ダウンロードができます
コンパイルメッセージ
main.cpp: In function 'int main()':
main.cpp:132:14: warning: structured bindings only available with '-std=c++17' or '-std=gnu++17' [-Wc++17-extensions]
  132 |     for(auto [p,cnt]:ch[i]){
      |              ^
main.cpp:140:12: warning: structured bindings only available with '-std=c++17' or '-std=gnu++17' [-Wc++17-extensions]
  140 |   for(auto [p,x]:fmp){
      |            ^

ソースコード

diff #
プレゼンテーションモードにする

#pragma GCC target("avx")
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
#include<bits/stdc++.h>
// #include<ext/pb_ds/assoc_container.hpp>
// #include<ext/pb_ds/tree_policy.hpp>
// #include<ext/pb_ds/tag_and_trait.hpp>
// using namespace __gnu_pbds;
// #include<boost/multiprecision/cpp_int.hpp>
// namespace multiprecisioninteger = boost::multiprecision;
// using cint=multiprecisioninteger::cpp_int;
using namespace std;
using ll=long long;
// #define double long double
using datas=pair<ll,ll>;
using ddatas=pair<double,double>;
using tdata=pair<ll,datas>;
using vec=vector<ll>;
using mat=vector<vec>;
using pvec=vector<datas>;
using pmat=vector<pvec>;
// using llset=tree<ll,null_type,less<ll>,rb_tree_tag,tree_order_statistics_node_update>;
#define For(i,a,b) for(i=a;i<(ll)b;++i)
#define bFor(i,b,a) for(i=b,--i;i>=(ll)a;--i)
#define rep(i,N) For(i,0,N)
#define rep1(i,N) For(i,1,N)
#define brep(i,N) bFor(i,N,0)
#define brep1(i,N) bFor(i,N,1)
#define all(v) (v).begin(),(v).end()
#define allr(v) (v).rbegin(),(v).rend()
#define vsort(v) sort(all(v))
#define vrsort(v) sort(allr(v))
#define uniq(v) vsort(v);(v).erase(unique(all(v)),(v).end())
#define endl "\n"
#define eb emplace_back
#define print(x) cout<<x<<endl
#define printyes print("Yes")
#define printno print("No")
#define printYES print("YES")
#define printNO print("NO")
#define output(v) do{bool f=0;for(auto outi:v){cout<<(f?" ":"")<<outi;f=1;}cout<<endl;}while(0)
#define matoutput(v) do{for(auto outimat:v)output(outimat);}while(0)
constexpr ll mod=1000000007;
// constexpr ll mod=998244353;
constexpr ll inf=1LL<<60;
constexpr long double eps=1e-9;
const long double PI=acosl(-1);
template<class T,class E> ostream& operator<<(ostream& os,const pair<T,E>& p){return os<<"("<<p.first<<","<<p.second<<")";}
template<class T> ostream& operator<<(ostream& os,const vector<T>& v){
os<<"{";bool f=false;
for(auto& x:v){if(f)os<<",";os<<x;f=true;}
os<<"}";
return os;
}
template<class T> ostream& operator<<(ostream& os,const set<T>& v){
os<<"{";bool f=false;
for(auto& x:v){if(f)os<<",";os<<x;f=true;}
os<<"}";
return os;
}
template<class T,class E> ostream& operator<<(ostream& os,const map<T,E>& v){
os<<"{";bool f=false;
for(auto& x:v){if(f)os<<",";os<<x;f=true;}
os<<"}";
return os;
}
template<class T> inline bool chmax(T& a,T b){bool x=a<b;if(x)a=b;return x;}
template<class T> inline bool chmin(T& a,T b){bool x=a>b;if(x)a=b;return x;}
#ifdef DEBUG
void debugg(){cout<<endl;}
template<class T,class... Args>void debugg(const T& x,const Args&... args){cout<<" "<<x;debugg(args...);}
#define debug(...) cout<<__LINE__<<" ["<<#__VA_ARGS__<<"]:",debugg(__VA_ARGS__)
#else
#define debug(...) (void(0))
#endif
void startupcpp(){
cin.tie(0);
ios::sync_with_stdio(false);
}
vector<int> eratosthenes(int N){
vector<int> ch(N+1,1);
for(int i=2;i<=N;++i){
if(ch[i]==1){
for(int j=1;i*j<=N;j++){
ch[i*j]=i;
}
}
}
return ch;
}
ll modpow(ll a,ll n,ll m=mod){
if(n<0)return 0;
ll res=1;
while(n>0){
if(n&1)res=res*a%m;
a=a*a%m;
n>>=1;
}
return res;
}
ll modinv(ll a,ll m=mod) {
ll b=m,u=1,v=0,t;
while(b){
t=a/b;
a-=t*b; swap(a,b);
u-=t*v; swap(u,v);
}
return (u+m)%m;
}
vector<pair<int,int>> ch[100001];
int main(){
startupcpp();
auto v=eratosthenes(1000000);
int N;
vector<ll> a(N);
ll allprod=1,alllcm=1;
cin>>N;
map<int,pair<int,int>> fmp;
map<int,int> smp;
for(int i=0;i<N;++i){
cin>>a[i];
(allprod*=a[i])%=mod;
int x=a[i];
while(x!=1){
if(ch[i].empty()||ch[i].back().first!=v[x]){
ch[i].emplace_back(v[x],1);
}else ch[i].back().second++;
x/=v[x];
}
for(auto [p,cnt]:ch[i]){
auto now=fmp[p];
if(chmax(fmp[p],pair<int,int>(cnt,i)))smp[p]=now.first;
else chmax(smp[p],cnt);
}
debug(ch[i]);
}
vector<ll> invlist(N,1);
for(auto [p,x]:fmp){
(alllcm*=modpow(p,x.first))%=mod;
(invlist[x.second]*=modpow(p,x.first-smp[p]))%=mod;
}
debug(fmp,smp);
for(int i=0;i<N;++i){
ll ans1=allprod*modinv(a[i])%mod;
ll ans2=alllcm*modinv(invlist[i])%mod;
print((ans1-ans2+mod)%mod);
}
}
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