結果

問題 No.1414 東大文系数学2021第2問改
ユーザー optopt
提出日時 2021-02-28 23:58:29
言語 C++17
(gcc 12.3.0 + boost 1.83.0)
結果
AC  
実行時間 143 ms / 2,000 ms
コード長 5,210 bytes
コンパイル時間 4,973 ms
コンパイル使用メモリ 257,540 KB
実行使用メモリ 81,532 KB
最終ジャッジ日時 2024-04-14 03:04:35
合計ジャッジ時間 9,016 ms
ジャッジサーバーID
(参考情報)
judge2 / judge4
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
6,816 KB
testcase_01 AC 2 ms
6,940 KB
testcase_02 AC 120 ms
81,448 KB
testcase_03 AC 2 ms
6,940 KB
testcase_04 AC 120 ms
81,452 KB
testcase_05 AC 142 ms
81,320 KB
testcase_06 AC 118 ms
81,376 KB
testcase_07 AC 2 ms
6,940 KB
testcase_08 AC 2 ms
6,940 KB
testcase_09 AC 118 ms
81,364 KB
testcase_10 AC 143 ms
81,348 KB
testcase_11 AC 120 ms
81,364 KB
testcase_12 AC 119 ms
81,408 KB
testcase_13 AC 119 ms
81,332 KB
testcase_14 AC 143 ms
81,340 KB
testcase_15 AC 119 ms
81,244 KB
testcase_16 AC 120 ms
81,380 KB
testcase_17 AC 120 ms
81,340 KB
testcase_18 AC 120 ms
81,308 KB
testcase_19 AC 142 ms
81,312 KB
testcase_20 AC 142 ms
81,308 KB
testcase_21 AC 118 ms
80,432 KB
testcase_22 AC 2 ms
6,940 KB
testcase_23 AC 119 ms
81,364 KB
testcase_24 AC 120 ms
81,532 KB
testcase_25 AC 120 ms
81,336 KB
testcase_26 AC 119 ms
81,348 KB
権限があれば一括ダウンロードができます

ソースコード

diff #

#include <bits/stdc++.h>
using namespace std;
#include <atcoder/all>
using namespace atcoder;
// input and output of modint
istream &operator>>(istream &is, modint998244353 &a) { long long v; is >> v; a = v; return is; }
ostream &operator<<(ostream &os, const modint998244353 &a) { return os << a.val(); }
istream &operator>>(istream &is, modint1000000007 &a) { long long v; is >> v; a = v; return is; }
ostream &operator<<(ostream &os, const modint1000000007 &a) { return os << a.val(); }
template<int m> istream &operator>>(istream &is, static_modint<m> &a) { long long v; is >> v; a = v; return is; }
template<int m> ostream &operator<<(ostream &os, const static_modint<m> &a) { return os << a.val(); }
template<int m> istream &operator>>(istream &is, dynamic_modint<m> &a) { long long v; is >> v; a = v; return is; }
template<int m> ostream &operator<<(ostream &os, const dynamic_modint<m> &a) { return os << a.val(); }
#define rep_(i, a_, b_, a, b, ...) for (int i = (a), lim##i = (b); i < lim##i; ++i)
#define rep(i, ...) rep_(i, __VA_ARGS__, __VA_ARGS__, 0, __VA_ARGS__)
#define drep_(i, a_, b_, a, b, ...) for (int i = (a)-1, lim##i = (b); i >= lim##i; --i)
#define drep(i, ...) drep_(i, __VA_ARGS__, __VA_ARGS__, __VA_ARGS__, 0)
#define all(x) (x).begin(), (x).end()
#define rall(x) (x).rbegin(), (x).rend()
#ifdef LOCAL
void debug_out() { cerr << endl; }
template <class Head, class... Tail> void debug_out(Head H, Tail... T) { cerr << ' ' << H; debug_out(T...); }
#define debug(...) cerr << 'L' << __LINE__ << " [" << #__VA_ARGS__ << "]:", debug_out(__VA_ARGS__)
#define dump(x) cerr << 'L' << __LINE__ << " " << #x << " = " << (x) << endl
#else
#define debug(...) (void(0))
#define dump(x) (void(0))
#endif
template<class T> using V = vector<T>;
using ll = long long;
using ld = long double;
using Vi = V<int>;  using VVi = V<Vi>;
using Vl = V<ll>;   using VVl = V<Vl>;
using Vd = V<ld>;   using VVd = V<Vd>;
using Vb = V<bool>; using VVb = V<Vb>;
template<class T> using priority_queue_rev = priority_queue<T, vector<T>, greater<T>>;
template<class T> vector<T> make_vec(size_t n, T a) { return vector<T>(n, a); }
template<class... Ts> auto make_vec(size_t n, Ts... ts) { return vector<decltype(make_vec(ts...))>(n, make_vec(ts...)); }
template<class T> inline int sz(const T &x) { return size(x); }
template<class T> inline bool chmin(T &a, const T b) { if (a > b) { a = b; return true; } return false; }
template<class T> inline bool chmax(T &a, const T b) { if (a < b) { a = b; return true; } return false; }
template<class T1, class T2> istream &operator>>(istream &is, pair<T1, T2> &p) { is >> p.first >> p.second; return is; }
template<class T1, class T2> ostream &operator<<(ostream &os, const pair<T1, T2> &p) { os << '(' << p.first << ", " << p.second << ')'; return os; }
template<class T, size_t n> istream &operator>>(istream &is, array<T, n> &v) { for (auto &e : v) is >> e; return is; }
template<class T, size_t n> ostream &operator<<(ostream &os, const  array<T, n> &v) { for (auto &e : v) os << e << ' '; return os; }
template<class T> istream &operator>>(istream &is, vector<T> &v) { for (auto &e : v) is >> e; return is; }
template<class T> ostream &operator<<(ostream &os, const vector<T> &v) { for (auto &e : v) os << e << ' '; return os; }
template<class T> inline void deduplicate(vector<T> &a) { sort(all(a)); a.erase(unique(all(a)), a.end()); }
template<class T> inline int count_between(const vector<T> &a, T l, T r) { return lower_bound(all(a), r) - lower_bound(all(a), l); } // [l, r)
inline ll cDiv(const ll x, const ll y) { return (x+y-1) / y; } // ceil(x/y)
inline int fLog2(const ll x) { assert(x > 0); return 63-__builtin_clzll(x); } // floor(log2(x))
inline int cLog2(const ll x) { assert(x > 0); return (x == 1) ? 0 : 64-__builtin_clzll(x-1); } // ceil(log2(x))
inline int popcount(const ll x) { return __builtin_popcountll(x); }
inline void fail() { cout << -1 << '\n'; exit(0); }
struct fast_ios { fast_ios(){ cin.tie(nullptr); ios::sync_with_stdio(false); cout << fixed << setprecision(20); }; } fast_ios_;
// const int INF  = (1<<30) - 1;
// const ll INFll = (1ll<<60) - 1;
// const ld EPS   = 1e-10;
// const ld PI    = acos(-1.0);
using mint = modint998244353;
// using mint = modint1000000007;
// using mint = modint;
// using Vm = V<mint>; using VVm = V<Vm>;


template<typename T> struct Factorial {
  int MAX;
  vector<T> fac, finv;
  Factorial(int m = 0) : MAX(m), fac(m+1, 1), finv(m+1, 1) {
    rep(i, 2, MAX+1) fac[i] = fac[i-1] * i;
    finv[MAX] /= fac[MAX];
    drep(i, MAX+1, 3) finv[i-1] = finv[i] * i;
  }
  T binom(int n, int k) {
    if (k < 0 || n < k) return 0;
    return fac[n] * finv[k] * finv[n-k];
  }
  T perm(int n, int k) {
    if (k < 0 || n < k) return 0;
    return fac[n] * finv[n-k];
  }
};
Factorial<mint> fc;


void solve() {
// ll solve() {
  int n, m, k; cin >> n >> m >> k;
  fc = Factorial<mint>(n+2);

  int p = n-m+1;
  mint ans = 0;
  rep(i, m+1) {
    int j = m - k*i;
    if (j < 0) break;
    mint res = fc.binom(p, i) * fc.binom(p+j-1, j);
    if (i&1) ans -= res;
    else ans += res;
  }
  ans = fc.binom(n, m) - ans;
  cout << ans << '\n';
  return;
}


int main() {
  solve();
  // cout << solve() << '\n';
}
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