結果

問題 No.1419 Power Moves
ユーザー fastmathfastmath
提出日時 2021-03-05 22:19:08
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 131 ms / 2,000 ms
コード長 4,153 bytes
コンパイル時間 1,193 ms
コンパイル使用メモリ 128,400 KB
最終ジャッジ日時 2025-01-19 11:19:44
ジャッジサーバーID
(参考情報)
judge5 / judge3
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 31
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <algorithm>
#include <cmath>
#include <vector>
#include <set>
#include <map>
#include <unordered_set>
#include <unordered_map>
#include <queue>
#include <ctime>
#include <cassert>
#include <complex>
#include <string>
#include <cstring>
#include <chrono>
#include <random>
#include <bitset>
#include <fstream>
using namespace std;
#define int long long
#define ii pair <int, int>
#define app push_back
#define all(a) a.begin(), a.end()
#define bp __builtin_popcountll
#define ll long long
#define mp make_pair
#define x first
#define y second
#define Time (double)clock()/CLOCKS_PER_SEC
#define debug(x) std::cerr << #x << ": " << x << '\n';
#define FOR(i, n) for (int i = 0; i < n; ++i)
#define pb push_back
#define trav(a, x) for (auto& a : x)
using vi = vector<int>;
template <typename T>
std::ostream& operator <<(std::ostream& output, const pair <T, T> & data)
{
output << "(" << data.x << "," << data.y << ")";
return output;
}
template <typename T>
std::ostream& operator <<(std::ostream& output, const std::vector<T>& data)
{
for (const T& x : data)
output << x << " ";
return output;
}
ll div_up(ll a, ll b) { return a/b+((a^b)>0&&a%b); } // divide a by b rounded up
ll div_down(ll a, ll b) { return a/b-((a^b)<0&&a%b); } // divide a by b rounded down
ll math_mod(ll a, ll b) { return a - b * div_down(a, b); }
#define tcT template<class T
#define tcTU tcT, class U
tcT> using V = vector<T>;
tcT> void re(V<T>& x) {
trav(a, x)
cin >> a;
}
tcT> bool ckmin(T& a, const T& b) {
return b < a ? a = b, 1 : 0;
} // set a = min(a,b)
tcT> bool ckmax(T& a, const T& b) {
return a < b ? a = b, 1 : 0;
}
ll gcd(ll a, ll b) {
while (b) {
tie(a, b) = mp(b, a % b);
}
return a;
}
//need define int long long
namespace Stuff {
int MOD = 1e9+7;
int mod(int n) {
n %= MOD;
if (n < 0) return n + MOD;
else return n;
}
int fp(int a, int p) {
int ans = 1, c = a;
for (int i = 0; (1ll << i) <= p; ++i) {
if ((p >> i) & 1) ans = mod(ans * c);
c = mod(c * c);
}
return ans;
}
int dv(int a, int b) { return mod(a * fp(b, MOD - 2)); }
};
struct M {
ll x;
M (int x_) { x = Stuff::mod(x_); }
M () { x = 0; }
M operator + (M y) {
int ans = x + y.x;
if (ans >= Stuff::MOD)
ans -= Stuff::MOD;
return M(ans);
}
M operator - (M y) {
int ans = x - y.x;
if (ans < 0)
ans += Stuff::MOD;
return M(ans);
}
M operator * (M y) { return M(x * y.x % Stuff::MOD); }
M operator / (M y) { return M(x * Stuff::fp(y.x, Stuff::MOD - 2) % Stuff::MOD); }
M operator + (int y) { return (*this) + M(y); }
M operator - (int y) { return (*this) - M(y); }
M operator * (int y) { return (*this) * M(y); }
M operator / (int y) { return (*this) / M(y); }
M operator ^ (int p) { return M(Stuff::fp(x, p)); }
void operator += (M y) { *this = *this + y; }
void operator -= (M y) { *this = *this - y; }
void operator *= (M y) { *this = *this * y; }
void operator /= (M y) { *this = *this / y; }
void operator += (int y) { *this = *this + y; }
void operator -= (int y) { *this = *this - y; }
void operator *= (int y) { *this = *this * y; }
void operator /= (int y) { *this = *this / y; }
void operator ^= (int p) { *this = *this ^ p; }
bool operator == (M y) { return x == y.x; }
};
std::ostream& operator << (std::ostream& o, const M& a)
{
cout << a.x;
return o;
}
signed main() {
#ifdef ONLINE_JUDGE
#define endl '\n'
ios_base::sync_with_stdio(0); cin.tie(0);
#endif
int n, k;
cin >> n >> k;
const int P = 1e9+7;
Stuff::MOD = n;
int sum_mod_n = (M(2)^k).x;
Stuff::MOD = P;
M sum_mod_P = M(2)^k;
M full = (sum_mod_P - sum_mod_n) / n;
//debug(full);
int start = (n - sum_mod_n + 1) % n;
V <M> ans(n);
FOR (i, n) {
//debug(i);
//debug((2 * i)%n);
ans[(start + 2 * i) % n] += full;
}
FOR (i, sum_mod_n) {
ans[(start + 2 * i) % n] += 1;
}
trav (e, ans) {
cout << e/(M(2)^k) << endl;
}
}
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