結果
| 問題 |
No.1418 Sum of Sum of Subtree Size
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2021-03-06 00:37:47 |
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 49 ms / 2,000 ms |
| コード長 | 1,052 bytes |
| コンパイル時間 | 1,933 ms |
| コンパイル使用メモリ | 200,124 KB |
| 最終ジャッジ日時 | 2025-01-19 12:10:28 |
|
ジャッジサーバーID (参考情報) |
judge5 / judge4 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 41 |
コンパイルメッセージ
main.cpp: In function ‘int main()’:
main.cpp:15:26: warning: format ‘%lld’ expects argument of type ‘long long int*’, but argument 2 has type ‘i64*’ {aka ‘long int*’} [-Wformat=]
15 | i64 n; scanf("%lld", &n);
| ~~~^ ~~
| | |
| | i64* {aka long int*}
| long long int*
| %ld
main.cpp:40:20: warning: format ‘%lld’ expects argument of type ‘long long int’, but argument 2 has type ‘i64’ {aka ‘long int’} [-Wformat=]
40 | printf("%lld\n", ans);
| ~~~^ ~~~
| | |
| | i64 {aka long int}
| long long int
| %ld
main.cpp:15:21: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
15 | i64 n; scanf("%lld", &n);
| ~~~~~^~~~~~~~~~~~
main.cpp:19:22: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
19 | scanf("%d%d", &a[i], &b[i]); a[i]--; b[i]--;
| ~~~~~^~~~~~~~~~~~~~~~~~~~~~
ソースコード
#include <bits/stdc++.h>
using namespace std::literals::string_literals;
using i64 = std::int_fast64_t;
using std::cout;
using std::cerr;
using std::endl;
using std::cin;
template<typename T> std::vector<T> make_v(size_t a){return std::vector<T>(a);}
template<typename T, typename... Ts> auto make_v(size_t a, Ts... ts){
return std::vector<decltype(make_v<T>(ts...))>(a, make_v<T>(ts...));
}
int main() {
i64 n; scanf("%lld", &n);
std::vector<int> a(n - 1), b(n - 1);
std::vector<std::vector<int>> g(n);
for(int i = 0; i < n - 1; i++) {
scanf("%d%d", &a[i], &b[i]); a[i]--; b[i]--;
g[a[i]].push_back(b[i]);
g[b[i]].push_back(a[i]);
}
i64 ans = 0;
auto solve = [&](auto&& solve, int v, int par) -> i64 {
i64 ret = 0, sum = 0;
for(auto to: g[v]) {
if(to == par) continue;
i64 val = solve(solve, to, v);
ans += val - val * val;
sum += val;
}
ans += (n - (sum + 1)) - (n - (sum + 1)) * (n - (sum + 1));
ans += (n - 1) * (n - 1) + n;
return sum + 1;
};
solve(solve, 0, -1);
printf("%lld\n", ans);
return 0;
}