結果
問題 | No.1431 東大文系数学2020第2問改 |
ユーザー | mine691 |
提出日時 | 2021-03-14 13:59:37 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 559 ms / 5,000 ms |
コード長 | 5,213 bytes |
コンパイル時間 | 4,723 ms |
コンパイル使用メモリ | 281,192 KB |
実行使用メモリ | 249,832 KB |
最終ジャッジ日時 | 2024-11-06 03:41:06 |
合計ジャッジ時間 | 14,537 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge1 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
6,816 KB |
testcase_01 | AC | 2 ms
6,820 KB |
testcase_02 | AC | 2 ms
6,820 KB |
testcase_03 | AC | 434 ms
249,808 KB |
testcase_04 | AC | 2 ms
6,820 KB |
testcase_05 | AC | 396 ms
249,636 KB |
testcase_06 | AC | 321 ms
249,768 KB |
testcase_07 | AC | 322 ms
249,668 KB |
testcase_08 | AC | 332 ms
249,692 KB |
testcase_09 | AC | 559 ms
249,668 KB |
testcase_10 | AC | 432 ms
249,804 KB |
testcase_11 | AC | 355 ms
249,680 KB |
testcase_12 | AC | 457 ms
249,736 KB |
testcase_13 | AC | 403 ms
249,664 KB |
testcase_14 | AC | 413 ms
249,832 KB |
testcase_15 | AC | 404 ms
249,672 KB |
testcase_16 | AC | 393 ms
249,728 KB |
testcase_17 | AC | 385 ms
249,696 KB |
testcase_18 | AC | 389 ms
249,664 KB |
testcase_19 | AC | 545 ms
249,692 KB |
testcase_20 | AC | 389 ms
249,700 KB |
testcase_21 | AC | 481 ms
249,668 KB |
testcase_22 | AC | 178 ms
115,120 KB |
testcase_23 | AC | 550 ms
249,668 KB |
testcase_24 | AC | 522 ms
249,656 KB |
testcase_25 | AC | 2 ms
6,816 KB |
testcase_26 | AC | 4 ms
6,816 KB |
testcase_27 | AC | 2 ms
6,820 KB |
ソースコード
// Enjoy your stay. Code by evima #include <atcoder/convolution> #include <atcoder/dsu> #include <atcoder/fenwicktree> #include <atcoder/lazysegtree> #include <atcoder/math> #include <atcoder/maxflow> #include <atcoder/mincostflow> #include <atcoder/modint> #include <atcoder/scc> #include <atcoder/segtree> #include <atcoder/string> #include <atcoder/twosat> using namespace atcoder; using mint = modint998244353; // modint1000000007;// modint; #include <bits/stdc++.h> using namespace std; using ld = long double; using ll = long long; using lll = __int128; using vl = vector<ll>; using vs = vector<string>; using LOOPVAR_TYPE = ll; #define all(x) (x).begin(), (x).end() #define sq(x) ((x) * (x)) #define sz(x) ll((x).size()) #define GET_MACRO(_1, _2, _3, NAME, ...) NAME #define rep1(i, n) rep2(i, 0, n) #define rep2(i, a, b) for (LOOPVAR_TYPE i = LOOPVAR_TYPE(a); i < LOOPVAR_TYPE(b); i++) #define rep(...) \ GET_MACRO(__VA_ARGS__, rep2, rep1) \ (__VA_ARGS__) #define eb emplace_back #define fir first #define sec second #define mp make_pair #define mt make_tuple const ld EPS = 1e-9; const ld PI = 3.14159265358979323846L; const ll INF = 1070000000LL; const ll MOD = 998244353LL; // 1000000007LL; void fast_io() { cin.tie(NULL); ios_base::sync_with_stdio(false); } ll lin() { ll x; cin >> x; return x; } string input() { string s; cin >> s; return s; } vl vin(int n) { vector<ll> v(n); rep(i, n) cin >> v[i]; return v; } template <typename T> bool chmin(T &a, const T &b) { return (b < a) ? (a = b, true) : false; } template <typename T> bool chmax(T &a, const T &b) { return (a < b) ? (a = b, true) : false; } template <typename T> map<T, ll> freq(const vector<T> &v) { map<T, ll> ret; for (T x : v) ++ret[x]; return ret; } template <typename T> vector<T> reversed(vector<T> v) { reverse(all(v)); return v; } template <typename T> vector<T> sorted(vector<T> v) { sort(all(v)); return v; } template <typename T> vector<T> sub(const vector<T> &v, int from, int to) { vector<T> ret; copy(&v[from], &v[to], back_inserter(ret)); return ret; } template <typename T> string str(const T &x) { stringstream ss; ss << x; return ss.str(); } template <typename Tuple, size_t... I> array<int, sizeof...(I)> str_tuple_impl(stringstream &ss, Tuple &&t, index_sequence<I...>) { return {{(void(ss << str(get<I>(t)) << " "), 0)...}}; } template <typename Tuple> string str_tuple(Tuple &&t) { stringstream ss; str_tuple_impl(ss, forward<Tuple>(t), make_index_sequence<tuple_size<decay_t<Tuple>>::value>{}); string s = ss.str(); if (s.size() > 0) s.pop_back(); return s; } template <typename T, typename U> string str(const pair<T, U> &p) { return str_tuple(p); } template <typename... T> string str(const tuple<T...> &t) { return str_tuple(t); } template <typename T> string str(const vector<T> &v) { stringstream ss; rep(i, sz(v)) ss << v[i] << (i < sz(v) - 1 ? " " : ""); return ss.str(); } template <typename T> void print1(T &&x, const string &end) { cout << str(x) << end; } void print() { print1("", "\n"); } template <typename T, typename... U> void print(T &&head, U &&...tail) { print1(head, " "); print(forward<U>(tail)...); } template <typename T> void eprint1(T &&x, const string &end) { cerr << str(x) << end; } void eprint() { eprint1("", "\n"); } template <typename T, typename... U> void eprint(T &&head, U &&...tail) { eprint1(head, " "); eprint(forward<U>(tail)...); } template <typename... T> void quit(T &&...x) { print(forward<T>(x)...); exit(0); } template <typename T, typename U> void yn(bool cnd, T &&yes = "Yes", U &&no = "No") { if (cnd) print(yes); else print(no); } void zip(vl &v) { vl w = v; sort(all(w)); int n = unique(all(w)) - w.begin(); for (ll &x : v) x = lower_bound(&w[0], &w[n], x) - &w[0]; } vl zipped(vl v) { zip(v); return v; } map<ll, ll> zipmap(vl v) { map<ll, ll> ret; sort(all(v)); v.erase(unique(all(v)), v.end()); rep(i, sz(v)) ret[v[i]] = i; return ret; } vector<mint> fact, ifact, inv; void init_fact_ifact_inv(ll n) { fact.resize(n + 1); ifact.resize(n + 1); inv.resize(n + 1); fact[0] = 1; rep(i, n) { fact[i + 1] = fact[i] * (i + 1); } ifact[n] = fact[n].inv(); for (int i = n - 1; i >= 0; --i) { ifact[i] = ifact[i + 1] * (i + 1); } rep(i, n) { inv[i + 1] = fact[i] * ifact[i + 1]; } } const mint ncr(ll n, ll r) { return n < 0 || r < 0 || r > n ? 0 : fact[n] * ifact[r] * ifact[n - r]; } void solveOne() { ll N, M, K; cin >> N >> M >> K; assert(1 <= N and N <= 3000); assert(1 <= M and M <= N * N); assert(0 <= K and K <= 2 * N - 2); init_fact_ifact_inv(N * (N + 2)); vector<vector<mint>> small(2 * N + 1, vector<mint>(2 * N + 1)); rep(i, 2 * N + 1) rep(j, i + 1) small[i][j] = ncr(i, j); mint ans = 0; rep(i, 1, N + 1) { rep(j, i, N + 1) { if (2 * N - K - i - j < 0) break; ans += (i != j ? 2 : 1) * ((K + i + j) & 1 ? -1 : 1) * small[N][i] * small[N][j] * small[2 * N - i - j][2 * N - K - i - j] * ncr(i * j, M); } } print(ans.val()); } int main() { fast_io(); cout << setprecision(20); int num_tc = 1; // cin >> num_tc; rep(tc, 1, num_tc + 1) { // cout << "Case #" << tc << ": " ;// << endl; solveOne(); } }