結果

問題 No.1436 Rgaph
ユーザー leaf_1415
提出日時 2021-03-20 03:39:57
言語 C++11
(gcc 13.3.0)
結果
AC  
実行時間 270 ms / 2,000 ms
コード長 6,211 bytes
コンパイル時間 1,275 ms
コンパイル使用メモリ 100,648 KB
実行使用メモリ 74,092 KB
最終ジャッジ日時 2024-11-21 07:26:22
合計ジャッジ時間 5,131 ms
ジャッジサーバーID
(参考情報)
judge1 / judge5
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 2
other AC * 28
権限があれば一括ダウンロードができます
コンパイルメッセージ
main.cpp: In function ‘int main()’:
main.cpp:263:12: warning: ‘p’ may be used uninitialized in this function [-Wmaybe-uninitialized]
  263 |         ll p;
      |            ^

ソースコード

diff #
プレゼンテーションモードにする

#include <iostream>
#include <cstdio>
#include <cmath>
#include <ctime>
#include <cstdlib>
#include <cassert>
#include <vector>
#include <list>
#include <stack>
#include <queue>
#include <deque>
#include <map>
#include <set>
#include <bitset>
#include <string>
#include <algorithm>
#include <utility>
#include <complex>
#define rep(x, s, t) for(llint (x) = (s); (x) <= (t); (x)++)
#define reps(x, s) for(llint (x) = 0; (x) < (llint)(s).size(); (x)++)
#define chmin(x, y) (x) = min((x), (y))
#define chmax(x, y) (x) = max((x), (y))
#define sz(x) ((ll)(x).size())
#define ceil(x, y) (((x)+(y)-1) / (y))
#define all(x) (x).begin(),(x).end()
#define outl(...) dump_func(__VA_ARGS__)
#define inf 1e18
using namespace std;
typedef long long llint;
typedef long long ll;
typedef pair<ll, ll> P;
struct edge{
ll to, cost;
edge(){}
edge(ll a, ll b){ to = a, cost = b;}
};
const ll mod = 1000000007;
//const ll mod = 998244353;
struct mint{
ll x = 0;
mint(ll y = 0){x = y; if(x < 0 || x >= mod) x = (x%mod+mod)%mod;}
mint(const mint &ope) {x = ope.x;}
mint operator-(){return mint(-x);}
mint operator+(const mint &ope){return mint(x) += ope;}
mint operator-(const mint &ope){return mint(x) -= ope;}
mint operator*(const mint &ope){return mint(x) *= ope;}
mint operator/(const mint &ope){return mint(x) /= ope;}
mint& operator+=(const mint &ope){
x += ope.x;
if(x >= mod) x -= mod;
return *this;
}
mint& operator-=(const mint &ope){
x += mod - ope.x;
if(x >= mod) x -= mod;
return *this;
}
mint& operator*=(const mint &ope){
x *= ope.x, x %= mod;
return *this;
}
mint& operator/=(const mint &ope){
ll n = mod-2; mint mul = ope;
while(n){
if(n & 1) *this *= mul;
mul *= mul;
n >>= 1;
}
return *this;
}
mint inverse(){return mint(1) / *this;}
bool operator ==(const mint &ope){return x == ope.x;}
bool operator !=(const mint &ope){return x != ope.x;}
};
istream& operator >>(istream &is, mint &ope){
ll t; is >> t, ope.x = t;
return is;
}
ostream& operator <<(ostream &os, mint &ope){return os << ope.x;}
ostream& operator <<(ostream &os, const mint &ope){return os << ope.x;}
bool exceed(ll x, ll y, ll m){return x >= m / y + 1;}
void mark(){ cout << "*" << endl; }
void yes(){ cout << "Yes" << endl; }
void no(){ cout << "No" << endl; }
ll gcd(ll a, ll b){if(b == 0) return a; return gcd(b, a%b);}
ll modpow(ll a, ll n){
if(n == 0) return 1;
if(n % 2) return ((a%mod) * (modpow(a, n-1)%mod)) % mod;
else return modpow((a*a)%mod, n/2) % mod;
}
template<typename T>
ostream& operator << (ostream& os, vector<T>& vec) {
for(int i = 0; i < vec.size(); i++) {
os << vec[i] << (i + 1 == vec.size() ? "" : " ");
}
return os;
}
template<typename T>
ostream& operator << (ostream& os, deque<T>& deq) {
for(int i = 0; i < deq.size(); i++) {
os << deq[i] << (i + 1 == deq.size() ? "" : " ");
}
return os;
}
template<typename T, typename U>
ostream& operator << (ostream& os, pair<T, U>& pair_var) {
os << "(" << pair_var.first << ", " << pair_var.second << ")";
return os;
}
template<typename T, typename U>
ostream& operator << (ostream& os, const pair<T, U>& pair_var) {
os << "(" << pair_var.first << ", " << pair_var.second << ")";
return os;
}
template<typename T, typename U>
ostream& operator << (ostream& os, map<T, U>& map_var) {
for(typename map<T, U>::iterator itr = map_var.begin(); itr != map_var.end(); itr++) {
os << "(" << itr->first << ", " << itr->second << ")";
itr++;
if(itr != map_var.end()) os << ",";
itr--;
}
return os;
}
template<typename T>
ostream& operator << (ostream& os, set<T>& set_var) {
for(typename set<T>::iterator itr = set_var.begin(); itr != set_var.end(); itr++) {
os << *itr;
++itr;
if(itr != set_var.end()) os << " ";
itr--;
}
return os;
}
template<typename T>
void outa(T a[], ll s, ll t)
{
for(ll i = s; i <= t; i++){ cout << a[i]; if(i < t) cout << " ";}
cout << endl;
}
void dump_func() {cout << endl;}
template <class Head, class... Tail>
void dump_func(Head &&head, Tail &&... tail) {
cout << head;
if(sizeof...(Tail) > 0) cout << " ";
dump_func(std::move(tail)...);
}
ll n, m;
vector<ll> G[1005], g[2005];
ll dist[2005][2005], pre[2005][2005];
ll eid[1005][1005];
ll ans[2005];
bool used[2005];
void bfs(vector<llint> G[], int S, llint dist[], llint pre[])
{
queue<int> Q;
Q.push(S);
for(int i = 1; i <= 2*n; i++) dist[i] = inf;
dist[S] = 0;
while(Q.size()){
int v = Q.front();
Q.pop();
for(int i = 0; i < G[v].size(); i++){
if(dist[G[v][i]] < inf/2) continue;
Q.push(G[v][i]);
dist[G[v][i]] = dist[v] + 1;
pre[G[v][i]] = v;
}
}
}
int main(void)
{
ios::sync_with_stdio(0);
cin.tie(0);
cin >> n >> m;
ll u, v;
rep(i, 1, m){
cin >> u >> v;
eid[u][v] = i;
G[u].push_back(v);
g[u].push_back(n+v);
g[n+u].push_back(v);
}
rep(i, 1, 2*n){
bfs(g, i, dist[i], pre[i]);
rep(j, 1, 2*n){
if(dist[i][j] > inf/2){
outl(-1);
return 0;
}
}
}
vector<ll> vec;
rep(i, 1, n){
ll v = n+i; vector<ll> tmp;
while(pre[i][v]){
v = pre[i][v];
if(v > n) tmp.push_back(v-n);
else tmp.push_back(v);
}
map<ll, ll> mp;
for(auto x : tmp) mp[x]++;
bool flag = true;
for(auto p : mp) if(p.second >= 2) flag = false;
if(flag && (sz(vec) == 0 || sz(vec) > sz(tmp))) vec = tmp;
}
reverse(all(vec));
bool flag = false;
for(auto v : vec) if(sz(G[v]) > 1) flag = true;
if(!flag){
outl(-1);
return 0;
}
reps(i, vec) used[eid[vec[i]][vec[(i+1)%sz(vec)]]] = true;
rep(i, 1, n){
g[i].clear();
for(auto u : G[i]){
if(used[eid[i][u]]) continue;
g[i].push_back(u);
}
}
ll s = vec.front(), t = vec.front();
for(auto v : vec){
bfs(g, v, dist[v], pre[v]);
for(auto u : vec){
if(u != v && dist[v][u] < inf/2){
s = v, t = u;
ll x = u;
while(pre[v][x]){
ll nx = pre[v][x];
ans[eid[nx][x]] = 1;
x = nx;
}
goto end;
}
}
}
end:;
ll p;
reps(i, vec){
if(vec[i] == t){
p = i;
break;
}
}
ll cnt = 1;
while(1){
ll v = vec[p%sz(vec)], nv = vec[(p+1)%sz(vec)];
ans[eid[v][nv]] = cnt % 2, cnt++;
if(nv == s) break;
p++;
}
rep(i, 1, m){
if(ans[i]) cout << "R";
else cout << "G";
}
cout << endl;
return 0;
}
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