結果

問題 No.1095 Smallest Kadomatsu Subsequence
ユーザー tatt61880
提出日時 2021-03-25 00:17:12
言語 Kuin
(KuinC++ v.2021.9.17)
結果
TLE  
実行時間 -
コード長 3,139 bytes
コンパイル時間 2,841 ms
コンパイル使用メモリ 149,616 KB
実行使用メモリ 49,152 KB
最終ジャッジ日時 2024-09-16 12:06:00
合計ジャッジ時間 10,632 ms
ジャッジサーバーID
(参考情報)
judge6 / judge3
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 3
other AC * 25 TLE * 1 -- * 4
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

func main()
const invalid: int :: lib@intMax
var n: int :: cui@inputInt()
var a: []int :: #[n]int
for i(0, n - 1)
do a[i] :: cui@inputInt()
end for
var lMin: []int :: #[n]int
var rMin: []int :: #[n]int
block
var min: int :: a[0]
for i(1, n - 1)
do lMin[i] :: min
do min :: [min, a[i]].min()
end for
end block
block
var min: int :: a[n - 1]
for i(n - 2, 0, -1)
do rMin[i] :: min
do min :: [min, a[i]].min()
end for
end block
var lLow: []int :: #[n]int
var rLow: []int :: #[n]int
block
var bin: BinaryTree :: #BinaryTree
do bin.ins(a[0])
for i(1, n - 1)
var p: Node :: bin.lower_bound(a[i])
do lLow[i] :: p =& null ?(-1, p.val)
do bin.ins(a[i])
end for
end block
block
var bin: BinaryTree :: #BinaryTree
do bin.ins(a[n - 1])
for i(n - 2, 0, -1)
var p: Node :: bin.lower_bound(a[i])
do rLow[i] :: p =& null ?(-1, p.val)
do bin.ins(a[i])
end for
end block
var ans: int :: invalid
for i(1, n - 2)
var v: int :: a[i]
; ^
var lm: int :: lMin[i]
var rm: int :: rMin[i]
if(lm < v & v > rm)
do ans :: [ans, lm + v + rm].min()
end if
; v
var ll: int :: lLow[i]
var rl: int :: rLow[i]
if(ll > v & v < rl)
do ans :: [ans, ll + v + rl].min()
end if
end for
if(ans = invalid)
do ans :: -1
end if
do cui@print("\{ans}\n")
class Node()
+var val: int
+var left: Node
+var right: Node
+var parent: Node
+*func toStr(): []char
ret "\{me.val}"
end func
+func init(val: int, parent: Node): Node
do me.val :: val
do me.parent :: parent
do me.left :: null
do me.right :: null
ret me
end func
+func next(): Node
var n: Node :: me
if(n.right <>& null)
ret n.right.min()
end if
while(n.parent <>& null & n.parent.left <>& n)
do n :: n.parent
end while
ret n.parent
end func
+func min(): Node
var n: Node :: me
while(n.left <>& null)
do n :: n.left
end while
ret n
end func
end class
class BinaryTree()
var root: Node
+func find(elem: int): Node
var n: Node :: me.root
while loop(n <>& null)
if(elem < n.val)
do n :: n.left
elif(elem > n.val)
do n :: n.right
else
break loop
end if
end while
ret n
end func
+func lower_bound(elem: int): Node
var n: Node :: me.root
while loop(n <>& null)
if(elem < n.val)
if(n.left =& null)
if(n.val >= elem)
ret n
else
ret n.parent
end if
end if
do n :: n.left
elif(elem > n.val)
if(n.right =& null)
if(n.val >= elem)
ret n
else
ret n.parent
end if
end if
do n :: n.right
else
break loop
end if
end while
ret n
end func
+func ins(elem: int)
if(me.root =& null)
do me.root :: (#Node).init(elem, null)
ret
end if
var n: Node :: me.root
var p: Node :: null
while(n <>& null)
do p :: n
if(elem < n.val)
do n :: n.left
else
do n :: n.right
end if
end while
do n :: (#Node).init(elem, p)
if(elem < p.val)
do p.left :: n
else
do p.right :: n
end if
end func
end class
end func
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