結果

問題 No.710 チーム戦
ユーザー hamrayhamray
提出日時 2021-03-25 00:33:55
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 49 ms / 3,000 ms
コード長 4,504 bytes
コンパイル時間 1,425 ms
コンパイル使用メモリ 170,880 KB
実行使用メモリ 46,976 KB
最終ジャッジ日時 2024-11-26 23:43:24
合計ジャッジ時間 3,690 ms
ジャッジサーバーID
(参考情報)
judge5 / judge3
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 2
other AC * 25
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
//#include <atcoder/all>
//using namespace atcoder;
#pragma GCC target ("avx")
#pragma GCC optimization ("O3")
#pragma GCC optimization ("unroll-loops")
using namespace std;
typedef vector<int> VI;
typedef vector<VI> VVI;
typedef vector<string> VS;
typedef pair<int, int> PII;
typedef pair<int, int> pii;
typedef pair<long long, long long> PLL;
typedef pair<int, PII> TIII;
typedef long long ll;
typedef long double ld;
typedef unsigned long long ull;
#define FOR(i, s, n) for (int i = s; i < (int)n; ++i)
#define REP(i, n) FOR(i, 0, n)
#define rep(i, a, b) for (int i = a; i < (b); ++i)
#define trav(a, x) for (auto &a : x)
#define all(x) x.begin(), x.end()
#define MOD 1000000007
template<class T1, class T2> inline bool chmax(T1 &a, T2 b) {if (a < b) {a = b; return true;} return false;}
template<class T1, class T2> inline bool chmin(T1 &a, T2 b) {if (a > b) {a = b; return true;} return false;}
const double EPS = 1e-6, PI = acos(-1);
const double pi = 3.141592653589793238462643383279;
//
typedef string::const_iterator State;
ll GCD(ll a, ll b){
return (b==0)?a:GCD(b, a%b);
}
ll LCM(ll a, ll b){
return a/GCD(a, b) * b;
}
template< int mod >
struct ModInt {
int x;
ModInt() : x(0) {}
ModInt(int64_t y) : x(y >= 0 ? y % mod : (mod - (-y) % mod) % mod) {}
ModInt &operator+=(const ModInt &p) {
if((x += p.x) >= mod) x -= mod;
return *this;
}
ModInt &operator-=(const ModInt &p) {
if((x += mod - p.x) >= mod) x -= mod;
return *this;
}
ModInt &operator*=(const ModInt &p) {
x = (int) (1LL * x * p.x % mod);
return *this;
}
ModInt &operator/=(const ModInt &p) {
*this *= p.inverse();
return *this;
}
ModInt operator-() const { return ModInt(-x); }
ModInt operator+(const ModInt &p) const { return ModInt(*this) += p; }
ModInt operator-(const ModInt &p) const { return ModInt(*this) -= p; }
ModInt operator*(const ModInt &p) const { return ModInt(*this) *= p; }
ModInt operator/(const ModInt &p) const { return ModInt(*this) /= p; }
bool operator==(const ModInt &p) const { return x == p.x; }
bool operator!=(const ModInt &p) const { return x != p.x; }
ModInt inverse() const {
int a = x, b = mod, u = 1, v = 0, t;
while(b > 0) {
t = a / b;
swap(a -= t * b, b);
swap(u -= t * v, v);
}
return ModInt(u);
}
ModInt pow(int64_t n) const {
ModInt ret(1), mul(x);
while(n > 0) {
if(n & 1) ret *= mul;
mul *= mul;
n >>= 1;
}
return ret;
}
friend ostream &operator<<(ostream &os, const ModInt &p) {
return os << p.x;
}
friend istream &operator>>(istream &is, ModInt &a) {
int64_t t;
is >> t;
a = ModInt< mod >(t);
return (is);
}
static int get_mod() { return mod; }
};
using modint = ModInt< 1000000007 >;
template< typename T >
struct Combination {
vector< T > _fact, _rfact, _inv;
Combination(int sz) : _fact(sz + 1), _rfact(sz + 1), _inv(sz + 1) {
_fact[0] = _rfact[sz] = _inv[0] = 1;
for(int i = 1; i <= sz; i++) _fact[i] = _fact[i - 1] * i;
_rfact[sz] /= _fact[sz];
for(int i = sz - 1; i >= 0; i--) _rfact[i] = _rfact[i + 1] * (i + 1);
for(int i = 1; i <= sz; i++) _inv[i] = _rfact[i] * _fact[i - 1];
}
inline T fact(int k) const { return _fact[k]; }
inline T rfact(int k) const { return _rfact[k]; }
inline T inv(int k) const { return _inv[k]; }
T P(int n, int r) const {
if(r < 0 || n < r) return 0;
return fact(n) * rfact(n - r);
}
T C(int p, int q) const {
if(q < 0 || p < q) return 0;
return fact(p) * rfact(q) * rfact(p - q);
}
T H(int n, int r) const {
if(n < 0 || r < 0) return (0);
return r == 0 ? 1 : C(n + r - 1, r);
}
};
int modpow(ll x, ll n, int mod) {
if(x == 0) return 0;
ll res = 1;
while(n) {
if(n&1) res = res*x % mod;
x = x*x%mod;
n >>= 1;
}
return res;
}
int dp[110][101010];
int main() {
cin.tie(0);
ios::sync_with_stdio(false);
cout << fixed << setprecision(11);
int N; cin >> N;
vector<int> a(N), b(N);
REP(i,N) cin >> a[i] >> b[i];
REP(i,101010) REP(j,110) dp[j][i] = 1e9;
dp[0][0] = 0;
REP(i,N) {
REP(j,101010) {
if(j+a[i] < 101010) {
dp[i+1][j+a[i]] = min(dp[i+1][j+a[i]], dp[i][j]);
}
dp[i+1][j] = min(dp[i+1][j], dp[i][j] + b[i]);
}
}
int ans = 1e9;
for(int i=0; i<=100000; i++) {
ans = min(ans, max(i,dp[N][i]));
}
cout << ans << endl;
return 0;
}
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