結果
| 問題 | No.1438 Broken Drawers | 
| コンテスト | |
| ユーザー |  | 
| 提出日時 | 2021-03-27 12:16:34 | 
| 言語 | PyPy3 (7.3.15) | 
| 結果 | 
                                AC
                                 
                             | 
| 実行時間 | 129 ms / 2,000 ms | 
| コード長 | 3,838 bytes | 
| コンパイル時間 | 213 ms | 
| コンパイル使用メモリ | 82,048 KB | 
| 実行使用メモリ | 122,880 KB | 
| 最終ジャッジ日時 | 2024-11-29 08:15:39 | 
| 合計ジャッジ時間 | 4,122 ms | 
| ジャッジサーバーID (参考情報) | judge3 / judge5 | 
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| ファイルパターン | 結果 | 
|---|---|
| sample | AC * 3 | 
| other | AC * 25 | 
ソースコード
import sys
input = lambda : sys.stdin.readline().rstrip()
sys.setrecursionlimit(2*10**5+10)
write = lambda x: sys.stdout.write(x+"\n")
debug = lambda x: sys.stderr.write(x+"\n")
### セグメント木(はやい)
class SG:
    def __init__(self, n, v=None):
        self._n = n
        self.geta = 0
        x = 0
        while (1 << x) < n:
            x += 1
        self._log = x
        self._size = 1 << self._log
        self._d = [ninf] * (2 * self._size)
        if v is not None:
            for i in range(self._n):
                self._d[self._size + i] = v[i]
        for i in range(self._size - 1, 0, -1):
            self._update(i)
    def update(self, p, x):
#         assert 0 <= p < self._n
        x -= self.geta
        p += self._size
        self._d[p] = x
        for i in range(1, self._log + 1):
#             self._update(p >> i)
            k = p>>i
            self._d[k] = op(self._d[2 * k], self._d[2 * k + 1])
    def get(self, p):
#         assert 0 <= p < self._n
        return self._d[p + self._size] + self.geta
    def check(self):
        return [self.get(p) for p in range(self._n)]
    def query(self, left, right):
        # assert 0 <= left <= right <= self._n
        sml = ninf
        smr = ninf
        left += self._size
        right += self._size
        while left < right:
            if left & 1:
                sml = op(sml, self._d[left])
                left += 1
            if right & 1:
                right -= 1
                smr = op(self._d[right], smr)
            left >>= 1
            right >>= 1
        return op(sml, smr) + self.geta
    def update_all(self, v):
        # 全体加算
        self.geta += v
    def _update(self, k):
        self._d[k] = op(self._d[2 * k], self._d[2 * k + 1])
    def query_all(self):
        return self._d[1] + self.geta
    def max_right(self, left, f):
        """f(op(a[l], a[l + 1], ..., a[r - 1])) = true となる最大の r
        -> rはf(op(a[l:r+1]))がFalseになる最小のr
        """
#         assert 0 <= left <= self._n
#         assert f(ninf)
        if left == self._n:
            return self._n
        left += self._size
        sm = ninf
        first = True
        while first or (left & -left) != left:
            first = False
            while left % 2 == 0:
                left >>= 1
            if not f(op(sm, self._d[left])):
                while left < self._size:
                    left *= 2
                    if f(op(sm, self._d[left])):
                        sm = op(sm, self._d[left])
                        left += 1
                return left - self._size
            sm = op(sm, self._d[left])
            left += 1
        return self._n
    def min_left(self, right, f):
        """f(op(a[l], a[l + 1], ..., a[r - 1])) = true となる最小の l
        """
#         assert 0 <= right <= self._n
#         assert f(ninf)
        if right == 0:
            return 0
        right += self._size
        sm = ninf
        first = True
        while first or (right & -right) != right:
            first = False
            right -= 1
            while right > 1 and right % 2:
                right >>= 1
            if not f(op(self._d[right], sm)):
                while right < self._size:
                    right = 2 * right + 1
                    if f(op(self._d[right], sm)):
                        sm = op(self._d[right], sm)
                        right -= 1
                return right + 1 - self._size
            sm = op(self._d[right], sm)
        return 0
op = min
ninf = 10**12
n = int(input())
a = list(map(int, input().split()))
pos = {}
for i,v in enumerate(a):
    pos[v] = i
done = [0]*n
ans = 0
for v in range(1,n+1):
    p = pos[v]
    if done[p]:
        continue
    else:
        ans += 1
        if p>=1:
            done[p-1] = 1
print(ans)
            
            
            
        