結果
| 問題 |
No.1438 Broken Drawers
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2021-03-27 12:16:34 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
AC
|
| 実行時間 | 129 ms / 2,000 ms |
| コード長 | 3,838 bytes |
| コンパイル時間 | 213 ms |
| コンパイル使用メモリ | 82,048 KB |
| 実行使用メモリ | 122,880 KB |
| 最終ジャッジ日時 | 2024-11-29 08:15:39 |
| 合計ジャッジ時間 | 4,122 ms |
|
ジャッジサーバーID (参考情報) |
judge3 / judge5 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 25 |
ソースコード
import sys
input = lambda : sys.stdin.readline().rstrip()
sys.setrecursionlimit(2*10**5+10)
write = lambda x: sys.stdout.write(x+"\n")
debug = lambda x: sys.stderr.write(x+"\n")
### セグメント木(はやい)
class SG:
def __init__(self, n, v=None):
self._n = n
self.geta = 0
x = 0
while (1 << x) < n:
x += 1
self._log = x
self._size = 1 << self._log
self._d = [ninf] * (2 * self._size)
if v is not None:
for i in range(self._n):
self._d[self._size + i] = v[i]
for i in range(self._size - 1, 0, -1):
self._update(i)
def update(self, p, x):
# assert 0 <= p < self._n
x -= self.geta
p += self._size
self._d[p] = x
for i in range(1, self._log + 1):
# self._update(p >> i)
k = p>>i
self._d[k] = op(self._d[2 * k], self._d[2 * k + 1])
def get(self, p):
# assert 0 <= p < self._n
return self._d[p + self._size] + self.geta
def check(self):
return [self.get(p) for p in range(self._n)]
def query(self, left, right):
# assert 0 <= left <= right <= self._n
sml = ninf
smr = ninf
left += self._size
right += self._size
while left < right:
if left & 1:
sml = op(sml, self._d[left])
left += 1
if right & 1:
right -= 1
smr = op(self._d[right], smr)
left >>= 1
right >>= 1
return op(sml, smr) + self.geta
def update_all(self, v):
# 全体加算
self.geta += v
def _update(self, k):
self._d[k] = op(self._d[2 * k], self._d[2 * k + 1])
def query_all(self):
return self._d[1] + self.geta
def max_right(self, left, f):
"""f(op(a[l], a[l + 1], ..., a[r - 1])) = true となる最大の r
-> rはf(op(a[l:r+1]))がFalseになる最小のr
"""
# assert 0 <= left <= self._n
# assert f(ninf)
if left == self._n:
return self._n
left += self._size
sm = ninf
first = True
while first or (left & -left) != left:
first = False
while left % 2 == 0:
left >>= 1
if not f(op(sm, self._d[left])):
while left < self._size:
left *= 2
if f(op(sm, self._d[left])):
sm = op(sm, self._d[left])
left += 1
return left - self._size
sm = op(sm, self._d[left])
left += 1
return self._n
def min_left(self, right, f):
"""f(op(a[l], a[l + 1], ..., a[r - 1])) = true となる最小の l
"""
# assert 0 <= right <= self._n
# assert f(ninf)
if right == 0:
return 0
right += self._size
sm = ninf
first = True
while first or (right & -right) != right:
first = False
right -= 1
while right > 1 and right % 2:
right >>= 1
if not f(op(self._d[right], sm)):
while right < self._size:
right = 2 * right + 1
if f(op(self._d[right], sm)):
sm = op(self._d[right], sm)
right -= 1
return right + 1 - self._size
sm = op(self._d[right], sm)
return 0
op = min
ninf = 10**12
n = int(input())
a = list(map(int, input().split()))
pos = {}
for i,v in enumerate(a):
pos[v] = i
done = [0]*n
ans = 0
for v in range(1,n+1):
p = pos[v]
if done[p]:
continue
else:
ans += 1
if p>=1:
done[p-1] = 1
print(ans)