結果
| 問題 | No.8073 - |
| ユーザー |
 tada721
|
| 提出日時 | 2021-04-01 20:02:07 |
| 言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 5,974 bytes |
| コンパイル時間 | 1,155 ms |
| コンパイル使用メモリ | 98,332 KB |
| 実行使用メモリ | 6,820 KB |
| 最終ジャッジ日時 | 2024-12-18 01:10:11 |
| 合計ジャッジ時間 | 1,475 ms |
|
ジャッジサーバーID （参考情報） |
judge5 / judge3 |
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コンパイルメッセージ
main.cpp: In function 'long long int keta(long long int)':
main.cpp:41:1: warning: control reaches end of non-void function [-Wreturn-type]
41 | }
| ^
main.cpp: In function 'long long int gcd(long long int, long long int)':
main.cpp:55:1: warning: control reaches end of non-void function [-Wreturn-type]
55 | }
| ^
main.cpp: In function 'long long int lcm(long long int, long long int)':
main.cpp:68:1: warning: control reaches end of non-void function [-Wreturn-type]
68 | }
| ^
ソースコード
#include<iostream>
#include<algorithm>
#include<cmath>
#include<map>
#include<stdio.h>
#include<vector>
#include<queue>
#include<math.h>
#include<deque>
#include<set>
#include<tuple>
#include<string>
using namespace std;
#define ll long long
#define int long long
#define rep(s,i,n) for(int i=s;i<n;i++)
#define c(n) cout<<n<<endl;
#define ic(n) int n;cin>>n;
#define sc(s) string s;cin>>s;
#define mod 998244353
#define inf 2000000000000000007
#define f first
#define s second
#define mini(c,a,b) *min_element(c+a,c+b)
#define maxi(c,a,b) *max_element(c+a,c+b)
#define pi 3.141592653589793238462643383279
#define e_ 2.718281828459045235360287471352
#define P pair<int,int>
#define upp(a,n,x) upper_bound(a,a+n,x)-a;
#define low(a,n,x) lower_bound(a,a+n,x)-a;
#define UF UnionFind
#define pb push_back
//printf("%.12Lf\n",);
int keta(int x) {
rep(0, i, 30) {
if (x < 10) {
return i + 1;
}
x = x / 10;
}
}
int gcd(int x, int y) {
if (x == 0 || y == 0)return x + y;
int aa = x, bb = y;
rep(0, i, 1000) {
aa = aa % bb;
if (aa == 0) {
return bb;
}
bb = bb % aa;
if (bb == 0) {
return aa;
}
}
}
int lcm(int x, int y) {
int aa = x, bb = y;
rep(0, i, 1000) {
aa = aa % bb;
if (aa == 0) {
return x / bb * y;
}
bb = bb % aa;
if (bb == 0) {
return x / aa * y;
}
}
}
bool prime(int x) {
if (x == 1)return false;
rep(2, i, sqrt(x) + 1) {
if (x % i == 0 && x != i) {
return false;
}
}
return true;
}
int max(int a, int b) {
if (a >= b)return a;
else return b;
}
string maxst(string s, string t) {
int n = s.size();
int m = t.size();
if (n > m)return s;
else if (n < m)return t;
else {
rep(0, i, n) {
if (s[i] > t[i])return s;
if (s[i] < t[i])return t;
}
return s;
}
}
int min(int a, int b) {
if (a >= b)return b;
else return a;
}
int yakuwa(int n) {
int sum = 0;
rep(1, i, sqrt(n + 1)) {
if (n % i == 0)sum += i + n / i;
if (i * i == n)sum -= i;
}
return sum;
}
int poow(int n,int m){
int pro=1;
int nn=n;
while(m){
if(m%2==1)pro=pro*nn%mod;
m=m/2;
nn=nn*nn%mod;
}
return pro;
}
int poow2(int n,int m,int modulo){
int pro=1;
int nn=n;
while(m){
if(m%2==1)pro=pro*nn%modulo;
m=m/2;
nn=nn*nn%modulo;
}
return pro;
}
int inv(int n,int m){
int t=poow(m,mod-2)%mod;
return n*t%mod;
}
int com(int n,int m){
if(n<m)return 0;
int bunsi=1,bunbo=1;
for(int i=n-m+1;i<=n;i++)bunsi=bunsi*i%mod;
for(int i=1;i<=m;i++)bunbo=bunbo*i%mod;
return inv(bunsi,bunbo);
}
int minpow(int x, int y) {
int sum = 1;
rep(0, i, y)sum *= x;
return sum;
}
int ketawa(int x, int sinsuu) {
int sum = 0;
rep(0, i, 100)sum += (x % poow(sinsuu, i + 1)) / (poow(sinsuu, i));
return sum;
}
int sankaku(int a) {
return a * (a + 1) / 2;
}
int sames(int a[1111111], int n) {
int ans = 0;
rep(0, i, n) {
if (a[i] == a[i + 1]) {
int j = i;
while (a[j + 1] == a[i] && j <= n - 2)j++;
ans += sankaku(j - i);
i = j;
}
}
return ans;
}
using Graph = vector<vector<int>>;
int oya[214514];
int depth[214514];
int subtreesize[214514];
void dfs(const Graph& G, int v, int p, int d) {
depth[v] = d;
oya[v] = p;
for (auto nv : G[v]) {
if (nv == p) continue; // nv が親 p だったらダメ
dfs(G, nv, v, d + 1); // d を 1 増やして子ノードへ
}
subtreesize[v]=1;
for(auto c:G[v]){
if(c==p)continue;
subtreesize[v]+=subtreesize[c];
}
}
struct UnionFind {
vector<int> par;
UnionFind(int n):par(n){
rep(0,i,n)par[i]=i;
}
int root(int x){
if (par[x]==x)return x;
return par[x]=root(par[x]);
}
void unite(int x,int y){
int rx=root(x);
int ry=root(y);
if (rx==ry) return;
par[rx]=ry;
}
bool same(int x,int y){
int rx=root(x);
int ry=root(y);
return rx==ry;
}
};
int dijkstraa[214514];
void dijkstra(int n,int m,int c[514514],int d[514514],int l[514514],int siten,bool mukou){
vector<P> e[214514];
rep(0,i,m){
e[c[i]].pb(P{l[i],d[i]});
if(mukou)e[d[i]].pb(P{l[i],c[i]});
}
rep(0,i,n)dijkstraa[i]=inf;
dijkstraa[siten]=0;
priority_queue<P,vector<P>,greater<P>>pp;
pp.push(P{0,siten});
while(!pp.empty()){
P t=pp.top();pp.pop();
if(t.first!=dijkstraa[t.second])continue;
rep(0,i,e[t.s].size()){
P g=e[t.s][i];
if(dijkstraa[g.second]>t.first+g.first){
dijkstraa[g.second]=t.first+g.first;
pp.push(P{dijkstraa[g.second],g.second});
}
}
}
}
int dijkstra2(int shuten){
return dijkstraa[shuten];
}
vector<int> toposo(vector<vector<int>> G,vector<int> indegree,int n){
vector<int> sorted_vertices;
queue<int> que;
rep(0,i,n)if(!indegree[i])que.push(i);
while(!que.empty()){
int v=que.front();
que.pop();
rep(0,i,G[v].size()){
int u=G[v][i];
indegree[u]-=1;
if(!indegree[u])que.push(u);
}
sorted_vertices.pb(v);
}
return sorted_vertices;
}
struct segtree{
vector<int> dat;
int n;
segtree(int n_):n(),dat(n_*4,inf){
int x=1;
while(n_>=x)x*=2;
n=x;
}
void update(int i,int x){
i+=n-1;
dat[i]=x;
while(i>0){
i=(i-1)/2;
dat[i]=min(dat[i*2+1],dat[i*2+2]);
}
}
int query(int a,int b){return query_sub(a,b,0,0,n);}
int query_sub(int a,int b,int k,int l,int r){
if(r<=a||b<=l)return inf;
else if(a<=l&&r<=b)return dat[k];
else{
int vl=query_sub(a,b,k*2+1,l,(l+r)/2);
int vr=query_sub(a,b,k*2+2,(l+r)/2,r);
return min(vl,vr);
}
}
int rightest(int a,int b,int x){return rightest_sub(a,b,x,0,0,n);}
int rightest_sub(int a,int b,int x,int k,int l,int r){
if(dat[k]>x||r<=a||b<=l)return a-1;
else if(k>=n-1)return k-(n-1);
else{
int vr=rightest_sub(a,b,x,2*k+2,(l+r)/2,r);
if(vr!=a-1)return vr;
else return rightest_sub(a,b,x,2*k+1,l,(l+r)/2);
}
}
int leftest(int a,int b,int x){return leftest_sub(a,b,x,0,0,n);}
int leftest_sub(int a,int b,int x,int k,int l,int r){
if(dat[k]>x||r<=a||b<=l)return b;
else if(k>=n-1)return k-(n-1);
else{
int vl=leftest_sub(a,b,x,2*k+1,l,(l+r)/2);
if(vl!=b)return vl;
else return leftest_sub(a,b,x,2*k+2,(l+r)/2,r);
}
}
};
signed main(){
cout<<"マイナス"<<endl;
}