結果
| 問題 |
No.1441 MErGe
|
| コンテスト | |
| ユーザー |
tenten
|
| 提出日時 | 2021-04-14 10:47:23 |
| 言語 | Java (openjdk 23) |
| 結果 |
TLE
|
| 実行時間 | - |
| コード長 | 2,571 bytes |
| コンパイル時間 | 2,296 ms |
| コンパイル使用メモリ | 77,964 KB |
| 実行使用メモリ | 88,640 KB |
| 最終ジャッジ日時 | 2024-06-30 11:26:47 |
| 合計ジャッジ時間 | 14,551 ms |
|
ジャッジサーバーID (参考情報) |
judge2 / judge5 |
(要ログイン)
| ファイルパターン | 結果 |
|---|---|
| sample | AC * 2 |
| other | AC * 11 TLE * 3 -- * 14 |
ソースコード
import java.io.*;
import java.util.*;
public class Main {
public static void main(String[] args) throws Exception {
Scanner sc = new Scanner();
int n = sc.nextInt();
int q = sc.nextInt();
long[] sums = new long[n + 1];
for (int i = 1; i <= n; i++) {
sums[i] = sums[i - 1] + sc.nextInt();
}
BinaryIndexedTree bit = new BinaryIndexedTree(n + 2);
StringBuilder sb = new StringBuilder();
for (int i = 0; i < q; i++) {
int type = sc.nextInt();
int left = sc.nextInt();
int right = sc.nextInt();
if (type == 1) {
bit.add(bit.getIdx(left), right - left);
} else {
long ans = sums[bit.getIdx(right)] - sums[bit.getIdx(left - 1)];
sb.append(ans).append("\n");
}
}
System.out.print(sb);
}
}
class BinaryIndexedTree {
int size;
int[] tree;
public BinaryIndexedTree(int size) {
this.size = size;
tree = new int[size];
}
public void add(int idx, int value) {
int mask = 1;
while (idx < size) {
if ((idx & mask) != 0) {
tree[idx] += value;
idx += mask;
}
mask <<= 1;
}
}
public int getSum(int from, int to) {
return getSum(to) - getSum(from - 1);
}
public int getSum(int x) {
int mask = 1;
int ans = 0;
while (x > 0) {
if ((x & mask) != 0) {
ans += tree[x];
x -= mask;
}
mask <<= 1;
}
return ans;
}
public int getIdx(int x) {
int prev = 0;
while (true) {
int current = getSum(x);
if (current == prev) {
break;
}
x += current - prev;
prev = current;
}
return x;
}
}
class Scanner {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
StringTokenizer st = new StringTokenizer("");
public Scanner() throws Exception {
}
public int nextInt() throws Exception {
return Integer.parseInt(next());
}
public long nextLong() throws Exception {
return Long.parseLong(next());
}
public String next() throws Exception {
if (!st.hasMoreTokens()) {
st = new StringTokenizer(br.readLine());
}
return st.nextToken();
}
}
tenten